How can I pad a value with leading zeros?
Since ECMAScript 2017 we have padStart:
const padded = (.1 + "").padStart(6, "0");
console.log(`-${padded}`);
Pad with leading zeros
You can do this with a string datatype. Use the PadLeft
method:
var myString = "1";
myString = myString.PadLeft(myString.Length + 5, '0');
000001
How can I pad an integer with zeros on the left?
Use java.lang.String.format(String,Object...)
like this:
String.format("%05d", yournumber);
for zero-padding with a length of 5. For hexadecimal output replace the d
with an x
as in "%05x"
.
The full formatting options are documented as part of java.util.Formatter
.
How to pad an integer number with leading zeros?
The problem is that the following:
.ToString()
.PadLeft(...)
all return a new string, they don't in any way modify the object you call the method on.
Please note that you have to place the result into a string. An integer value does not have any concept of padding, so the integer value 0010 is identical to the integer value 10.
So try this:
string value = temCode.ToString().PadLeft(4, '0');
or you can use this:
string value = temCode.ToString("d4");
or this:
string value = string.Format("{0:0000}", temCode);
Pad a string with leading zeros so it's 3 characters long in SQL Server 2008
If the field is already a string, this will work
SELECT RIGHT('000'+ISNULL(field,''),3)
If you want nulls to show as '000'
It might be an integer -- then you would want
SELECT RIGHT('000'+CAST(field AS VARCHAR(3)),3)
As required by the question this answer only works if the length <= 3, if you want something larger you need to change the string constant and the two integer constants to the width needed. eg
'0000' and VARCHAR(4)),4
How to pad integer printing with leading zeros?
tostring[0]=(char)0;
does not write the character representation of 0
into tostring[0]. It writes a zero. You want tostring[0] = '0'
, with single quotes. And similarly, to write the character representation of a single digit, you can write tostring[1] = '0' + hours
(If hours is 5, then '0' + 5 is the character value used to represent 5
in the local character set. Thankfully, it was standardized long ago that those representations should be sequential so that sort of thing works.) But, unless the point of this exercise is to avoid using printf, you should really just use printf.
How can I pad a string with a variable number of leading zeros?
You will need to utilize a couple Expressions to handle this.
Declare a String variable to store the input (e.g. named
InputVar
). You will need to continue using theconcat()
Expression here with the input value to add the maximum possible zeros required for each item (e.g. 4 for BoxNo and 5 for ItemID).This is obviously inefficient, but there's no better way to insert a dynamic number of characters in Flow, to my knowledge.
Declare a second Integer variable to determine the length (e.g. named
InputVarLength
), with the following custom Expression as the value:length(variables('InputVar'))
Finally, declare a third variable that will calculate a substring result (e.g. named
InputVarResult
). Use this custom substring Expression as the value:substring(variables('InputVar'),sub(variables('InputVarLength'),5),5)
For the ItemID or other results, you'd replace the 5
s in the substring Expression with the appropriate startIndex
and length
to return the size you would like. For reference, the substring format is:
substring(text, startIndex, length)
Which includes the String value you want to find a substring of, the position within that string that you want to start from, and how many characters from that starting position you want to include in your substring result.
The nested subtract format is:
sub(minuend, subtrahend)
Which includes the Integer value to be subtracted from (minuend) and the Integer value that you want to subtract (subtrahend). E.g. sub(10, 2)
would return an Integer value of 8
.
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