Get Protocol, Domain, and Port from Url

Get protocol, domain, and port from URL

first get the current address

var url = window.location.href

Then just parse that string

var arr = url.split("/");

your url is:

var result = arr[0] + "//" + arr[2]

Hope this helps

Java | API to get protocol://domain.port from URL

Create a new URL object using your String value and call getHost() or any other method on it, like so:

URL url = new URL("https://test.domain.com/a/b/c.html?test=hello");
String protocol = url.getProtocol();
String host = url.getHost();
int port = url.getPort();

// if the port is not explicitly specified in the input, it will be -1.
if (port == -1) {
    return String.format("%s://%s", protocol, host);
} else {
    return String.format("%s://%s:%d", protocol, host, port);
}

Get protocol, hostname, and path from URL

Your regex won't capture https://www.google.com.

Use capturing group and apply your regex with regex.exec(). Then access the returned array to set your variable:

str="https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8#q=picture%20of%20a%20potato";regex = new RegExp('(https?://.*?\)/');match = regex.exec(str)[1];console.log(match);

.NET - Get protocol, host, and port

The following (C#) code should do the trick

Uri uri = new Uri("http://www.mywebsite.com:80/pages/page1.aspx");
string requested = uri.Scheme + Uri.SchemeDelimiter + uri.Host + ":" + uri.Port;

Get protocol and domain (WITHOUT subdomain) from a URL

I am using tldextract When I doing the domain parse.

In your case you only need combine the domain + suffix

import tldextract
tldextract.extract('mail.google.com')
Out[756]: ExtractResult(subdomain='mail', domain='google', suffix='com')
tldextract.extract('classes.usc.edu/xxx/yy/zz')
Out[757]: ExtractResult(subdomain='classes', domain='usc', suffix='edu')
tldextract.extract('google.co.uk')
Out[758]: ExtractResult(subdomain='', domain='google', suffix='co.uk')

Get protocol + host name from URL

You should be able to do it with urlparse (docs: python2, python3):

from urllib.parse import urlparse
# from urlparse import urlparse  # Python 2
parsed_uri = urlparse('http://stackoverflow.com/questions/1234567/blah-blah-blah-blah' )
result = '{uri.scheme}://{uri.netloc}/'.format(uri=parsed_uri)
print(result)

# gives
'http://stackoverflow.com/'

Getting port from URL string using Javascript

From what I get, you don't want to use location as the URL to subtract the port from, just any string as an URL. Well, I came up with this, for such a case. This function takes any string (but you can pass it the location URL anyway, and it works the same):

function getPort(url) {
    url = url.match(/^(([a-z]+:)?(\/\/)?[^\/]+).*$/)[1] || url;
    var parts = url.split(':'),
        port = parseInt(parts[parts.length - 1], 10);
    if(parts[0] === 'http' && (isNaN(port) || parts.length < 3)) {
        return 80;
    }
    if(parts[0] === 'https' && (isNaN(port) || parts.length < 3)) {
        return 443;
    }
    if(parts.length === 1 || isNaN(port)) return 80;
    return port;
}

• It gets the base url from the string.
• It splits the base url into parts, by ':'.
• It tries to parse the digits-only part of the port (the last element of the parts array) into an integer.
• If the URL starts with 'http' AND the port is not a number or the length of the URL parts array is less than 3 (which means no port was implied in the URL string), it returns the default HTTP port.
• Same thing goes for 'https'.
• If the length was 1, it means no protocol nor port was provided. In that case or in the case the port is not a number (and again, no protocol was provided), return the default HTTP port.
• If it passes through all these tests, then it just returns the port it tried to parse into an integer at the beginning of the function.

Get the website protocol when I have the address

You can achieve this with the following command:

openssl s_client -showcerts -connect google.com:443

This assumes that the server you are testing is setup to use the standard https port 443.

Return only protocol and domain from full URI string

    sometodo("http://127.0.0.1:8000/hello/some/word1212/");
    sometodo("http://127.0.0.1:8000/hello/some/valorant_operator/");
    
    function sometodo(str) {        
        var output = str.match(/^(?:[^\/]*\/){3}/)[0];
        console.log(output);
        return output;
    }

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