How to convert jsonString to JSONObject in Java
Using org.json library:
try {
JSONObject jsonObject = new JSONObject("{\"phonetype\":\"N95\",\"cat\":\"WP\"}");
}catch (JSONException err){
Log.d("Error", err.toString());
}
Safely turning a JSON string into an object
JSON.parse(jsonString)
is a pure JavaScript approach so long as you can guarantee a reasonably modern browser.
How to convert Java String to JSON Object
You are passing into the JSONObject
constructor an instance of a StringBuilder
class.
This is using the JSONObject(Object)
constructor, not the JSONObject(String)
one.
Your code should be:
JSONObject jsonObj = new JSONObject(jsonString.toString());
Converting Java objects to JSON with Jackson
To convert your object
in JSON with Jackson:
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.ObjectWriter;
ObjectWriter ow = new ObjectMapper().writer().withDefaultPrettyPrinter();
String json = ow.writeValueAsString(object);
How to convert a string to JSON object in PHP
What @deceze said is correct, it seems that your JSON is malformed, try this:
{
"Coords": [{
"Accuracy": "30",
"Latitude": "53.2778273",
"Longitude": "-9.0121648",
"Timestamp": "Fri Jun 28 2013 11:43:57 GMT+0100 (IST)"
}, {
"Accuracy": "30",
"Latitude": "53.2778273",
"Longitude": "-9.0121648",
"Timestamp": "Fri Jun 28 2013 11:43:57 GMT+0100 (IST)"
}, {
"Accuracy": "30",
"Latitude": "53.2778273",
"Longitude": "-9.0121648",
"Timestamp": "Fri Jun 28 2013 11:43:57 GMT+0100 (IST)"
}, {
"Accuracy": "30",
"Latitude": "53.2778339",
"Longitude": "-9.0121466",
"Timestamp": "Fri Jun 28 2013 11:45:54 GMT+0100 (IST)"
}, {
"Accuracy": "30",
"Latitude": "53.2778159",
"Longitude": "-9.0121201",
"Timestamp": "Fri Jun 28 2013 11:45:58 GMT+0100 (IST)"
}]
}
Use json_decode
to convert String into Object (stdClass
) or array: http://php.net/manual/en/function.json-decode.php
[edited]
I did not understand what do you mean by "an official JSON object", but suppose you want to add content to json via PHP and then converts it right back to JSON?
assuming you have the following variable:
$data = '{"Coords":[{"Accuracy":"65","Latitude":"53.277720488429026","Longitude":"-9.012038778269686","Timestamp":"Fri Jul 05 2013 11:59:34 GMT+0100 (IST)"},{"Accuracy":"65","Latitude":"53.277720488429026","Longitude":"-9.012038778269686","Timestamp":"Fri Jul 05 2013 11:59:34 GMT+0100 (IST)"},{"Accuracy":"65","Latitude":"53.27770755361785","Longitude":"-9.011979642121824","Timestamp":"Fri Jul 05 2013 12:02:09 GMT+0100 (IST)"},{"Accuracy":"65","Latitude":"53.27769091555766","Longitude":"-9.012051410095722","Timestamp":"Fri Jul 05 2013 12:02:17 GMT+0100 (IST)"},{"Accuracy":"65","Latitude":"53.27769091555766","Longitude":"-9.012051410095722","Timestamp":"Fri Jul 05 2013 12:02:17 GMT+0100 (IST)"}]}';
You should convert it to Object (stdClass):
$manage = json_decode($data);
But working with stdClass
is more complicated than PHP-Array, then try this (use second param with true
):
$manage = json_decode($data, true);
This way you can use array functions: http://php.net/manual/en/function.array.php
adding an item:
$manage = json_decode($data, true);
echo 'Before: <br>';
print_r($manage);
$manage['Coords'][] = Array(
'Accuracy' => '90'
'Latitude' => '53.277720488429026'
'Longitude' => '-9.012038778269686'
'Timestamp' => 'Fri Jul 05 2013 11:59:34 GMT+0100 (IST)'
);
echo '<br>After: <br>';
print_r($manage);
remove first item:
$manage = json_decode($data, true);
echo 'Before: <br>';
print_r($manage);
array_shift($manage['Coords']);
echo '<br>After: <br>';
print_r($manage);
any chance you want to save to json to a database or a file:
$data = '{"Coords":[{"Accuracy":"65","Latitude":"53.277720488429026","Longitude":"-9.012038778269686","Timestamp":"Fri Jul 05 2013 11:59:34 GMT+0100 (IST)"},{"Accuracy":"65","Latitude":"53.277720488429026","Longitude":"-9.012038778269686","Timestamp":"Fri Jul 05 2013 11:59:34 GMT+0100 (IST)"},{"Accuracy":"65","Latitude":"53.27770755361785","Longitude":"-9.011979642121824","Timestamp":"Fri Jul 05 2013 12:02:09 GMT+0100 (IST)"},{"Accuracy":"65","Latitude":"53.27769091555766","Longitude":"-9.012051410095722","Timestamp":"Fri Jul 05 2013 12:02:17 GMT+0100 (IST)"},{"Accuracy":"65","Latitude":"53.27769091555766","Longitude":"-9.012051410095722","Timestamp":"Fri Jul 05 2013 12:02:17 GMT+0100 (IST)"}]}';
$manage = json_decode($data, true);
$manage['Coords'][] = Array(
'Accuracy' => '90'
'Latitude' => '53.277720488429026'
'Longitude' => '-9.012038778269686'
'Timestamp' => 'Fri Jul 05 2013 11:59:34 GMT+0100 (IST)'
);
if (($id = fopen('datafile.txt', 'wb'))) {
fwrite($id, json_encode($manage));
fclose($id);
}
I hope I have understood your question.
Good luck.
Convert object string to JSON
If the string is from a trusted source, you could use eval
then JSON.stringify
the result. Like this:
var str = "{ hello: 'world', places: ['Africa', 'America', 'Asia', 'Australia'] }";
var json = JSON.stringify(eval("(" + str + ")"));
Note that when you eval
an object literal, it has to be wrapped in parentheses, otherwise the braces are parsed as a block instead of an object.
I also agree with the comments under the question that it would be much better to just encode the object in valid JSON to begin with and avoid having to parse, encode, then presumably parse it again. HTML supports single-quoted attributes (just be sure to HTML-encode any single quotes inside strings).
How to convert the following json string to java object?
No need to go with GSON for this; Jackson can do either plain Maps/Lists:
ObjectMapper mapper = new ObjectMapper();
Map<String,Object> map = mapper.readValue(json, Map.class);
or more convenient JSON Tree:
JsonNode rootNode = mapper.readTree(json);
By the way, there is no reason why you could not actually create Java classes and do it (IMO) more conveniently:
public class Library {
@JsonProperty("libraryname")
public String name;
@JsonProperty("mymusic")
public List<Song> songs;
}
public class Song {
@JsonProperty("Artist Name") public String artistName;
@JsonProperty("Song Name") public String songName;
}
Library lib = mapper.readValue(jsonString, Library.class);
Issue with converting string to json in Java
You need to escape your double quotes in your STRING
variable:
"{\"status\":0}"
You can do that programmatically like that (we need to call toString()
because STRING
is an instance of StringBuilder):
String escapedJsonStr = STRING.toString().replaceAll("\"", "\\\"");
Converting a string to JSON object
var obj = JSON.parse(string);
Where string
is your json string.
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