No Primary or Default Constructor Found for Interface Java.Util.List Rest API Spring Boot

No primary or default constructor found for interface org.springframework.data.domain.Pageable

I would suggest refactoring you controller to

public List<ItemCategory> getAllItemCategoryByPage(@RequestParam("page") int pageIndex, 
@RequestParam("size") int pageSize){
return itemCategoryService
.getAllItemCategoriesByPageable(PageRequest.of(pageIndex, pageSize)).getContent();
}

I think you are missing an annotation before Pageable (how are you sending that data from client?).

No primary or single public constructor found for interface javax.ws.rs.core.UriInfo - and no default constructor found either

As Paul mentioned above in the comments legacy code has mixed up JAX-RS and Spring MVC in the controller code and I have no clue how it was working so far (maybe because running on Java6/7?) but the solution in my case was to use @RequestParam instead of @Context, as there is no equivalent of URIInfo in the Spring MVC, and the code will looks like this:

@RestController
@RequestMapping(APIConstants.API_BASE_URI + APIConstants.MYCONTROLLER)
public class MyController extends APIRESTResource {

@Context
UriInfo uriInfo;

@GetMapping({"/activate"})
public ResponseEntity<String> activateAccount(@PathVariable("service") String srvc, @RequestParam String accId) {
HttpStatus status = HttpStatus.OK;
MediaType type = MediaType.TEXT_PLAIN;
String payload = "Activated";

try {
List<Long> accountIdList = extractAccountIdsAsList(accId);

String datasource = getDatasourceForService(srvc);
AccountsServiceImpl mgr = new AccountsServiceImpl(datasource);
mgr.activateAccounts(accIdList);

HttpHeaders headers = new HttpHeaders();
headers.setContentType(type);
return new ResponseEntity<>(payload, headers, status);
}
catch (Exception ex) {
return new ResponseEntity<>(ex.getMessage(), HttpStatus.INTERNAL_SERVER_ERROR);
}
}

}

where

   private List<Long> extractAccountIdsAsList(String accIdStr) throws Exception {
String fieldName = "accId";
validateRequiredField(fieldName, accIdStr);

accIdStr = accIdStr.replace(" ", ""); // remove any spaces...

String[] accIds = null;
if (accIdStr.contains(",")) {
accIds = accIdStr.split("\\,");
}
else {
accIds = new String[1];
accIds[0] = accIdStr;
}

List<Long> accIdList = new ArrayList<Long>();
for (int i = 0; i < accIds.length; i++) {
validateFieldValueType(fieldName, accIds[i], Long.TYPE);
Long accId = new Long(accIds[i]);
accIdList.add(accId);
}

return accIdList;
}

Selenium python Error: element could not be scrolled into view

This error message...

selenium.common.exceptions.ElementNotInteractableException: Message: Element <span class="ui-button-text"> could not be scrolled into view

...implies that the WebDriver instance i.e. driver was unable to scroll the element within the Viewport to invoke click().


First of all, as your usecase is to invoke click() on the element, ideally instead of using presence_of_element_located() you need to use the ExpectedConditions as element_to_be_clickable() as follows:

WebDriverWait(driver, 1000000).until(EC.element_to_be_clickable((By.XPATH, '/html/body/div[5]/div[3]/div/button/span'))).click()

You can find a couple of detailed discussions in:

  • Message: Element could not be scrolled into view while trying to click on an option within a dropdown menu through Selenium
  • org.openqa.selenium.ElementNotInteractableException: Element could not be scrolled into view when trying to click a button

As an alternative, as per the error message, to scroll an element within the Viewport before invoking click() you can also use the Element.scrollIntoView() method.

You can find a detailed discussion in:
- What is the difference between the different scroll options?


At this point it is worth to mention, the following methods:

  • move_to_element() from selenium.webdriver.common.action_chains
  • element_to_be_clickable() from selenium.webdriver.support.expected_conditions

will automatically scroll the element within the Viewport.

You can find a detailed discussion in:
- How to scroll a webpage using selenium webdriver in Python without using javascript method execute_script()


This usecase

The button with text as Continue is within the Top Level Content but rendered within a Modal Dialog Box.

DevTools Snapshot:

ModalDialogBox

As the desired element is within a Modal Dialog Box, so to locate and invoke click() on the element you have to induce WebDriverWait for the element_to_be_clickable() and you can use the following Locator Strategy:

  • Using XPATH:

    WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//div[starts-with(@aria-describedby, 'ui-id-')]//span[@class='ui-button-text' and text()='Continue']"))).click()
  • Note : You have to add the following imports :

    from selenium.webdriver.support.ui import WebDriverWait
    from selenium.webdriver.common.by import By
    from selenium.webdriver.support import expected_conditions as EC

DevTools Snapshot:

XPath



Related Topics



Leave a reply



Submit