How to Read Xml Response from a Url in Java

How to read XML response from a URL in java?

For xml parsing of an inputstream you can do:

// the SAX way:
XMLReader myReader = XMLReaderFactory.createXMLReader();
myReader.setContentHandler(handler);
myReader.parse(new InputSource(new URL(url).openStream()));

// or if you prefer DOM:
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new URL(url).openStream());

But to communicate over http from server to client I prefer using hessian library or springs http invoker lib

Reading XML file from URL in java

xyou can try like this,
Here you can set your string response ang get xml string response into XML Document

        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder;
        Document doc;
        try {
            builder = factory.newDocumentBuilder();
            doc =  builder.parse(new InputSource( new StringReader("your xml string response")));
        } catch (ParserConfigurationException | SAXException | IOException ex) {
            ex.printStackTrace();
        }

i'm not sure but i think it's helpful to you.

parsing XML from URL in java

By default, the URL returns data in JSON format. You see an XML in the browser because the way the browser negotiates a return type (via Accept header).

You can either parse the data as JSON, or change the URL to http://api.nbp.pl/api/exchangerates/rates/c/gbp/2015-01-01/2015-01-31?format=xml.

Notice ?format=xml at the end.

See the User manual.

Reading XML online and Storing It (Using Java)

Very simply:

File myOutput = new File("c:\\myDirectory\\myOutput.xml");
xform.transform(new DOMSource(doc), new StreamResult(myOutput));

How to Read XML Response using Java

I never work on XML parsing but when I debug your Code in my machine I got an error something like,

[Fatal Error] :1:84: The markup in the document following the root element must be well-formed.
Exception in thread "main" org.xml.sax.SAXParseException; lineNumber: 1; columnNumber: 84; The markup in the document following the root element must be well-formed.
    at com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(DOMParser.java:257)
    at com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(DocumentBuilderImpl.java:339)
    at com.flotomate.fd.system.etc.OprUtility.main(OprUtility.java:87)

and search on StackOverflow what cause I got an error I find this Answer

issue is not root element Added.

after I add root element still not fix. so I follow pattern same as Answer

not Sure optimize and well define but working

String response = " <root>"
                      +"   <Response>  "
                      + "       <NO>1</NO>  "
                      + "       <NAME>John Doe</NAME>  " 
                      + "   </Response>  " 
                      + "   <Response>  "
                      + "       <NO>2</NO>  " 
                      + "       <NAME>Jane Doe</NAME>  " 
                      + "  </Response>  "
                      + "</root>";
    Document document = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(
            new InputSource(new StringReader(response.toString())));

    NodeList nodeList = document.getDocumentElement().getChildNodes();

    for (int i = 0; i < nodeList.getLength(); i++) {
    Node node = nodeList.item(i);
    if (node.getNodeType() == Node.ELEMENT_NODE) {
        Element element = (Element) node;
        if (element.getNodeName().contains("Response")) {
            System.out.println(element.getElementsByTagName("NO").item(0).getTextContent());
            System.out.println(element.getElementsByTagName("NAME").item(0).getTextContent());
        }
    }
}

    //And from this also.....
    for (int i = 0; i < nodeList.getLength(); i++) {
        Element element1 = (Element) nodeList.item(i);
                System.out.println(element.getElementsByTagName("NO").item(0).getTextContent());
                System.out.println(element.getElementsByTagName("NAME").item(0).getTextContent());
    }

output:

1
John Doe
2
Jane Doe

HttpUrlConnection: how to get the XML response into a String?

I have two observations.

1. Move connection.disconnect(); towards the end, where you are done with reading i.e. after the br.close(); line.

2. Follow Below sequence:

   InputStream stream = connection.getInputStream();
   InputStreamReader isReader = new InputStreamReader(stream ); 
   
   //put output stream into a string
   BufferedReader br = new BufferedReader(isReader );
   

Hope that works!

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