Replacement for Stringbyaddingpercentescapesusingencoding in iOS9

Replacement for stringByAddingPercentEscapesUsingEncoding in ios9?

The deprecation message says (emphasis mine):

Use stringByAddingPercentEncodingWithAllowedCharacters(_:) instead, which always uses the recommended UTF-8 encoding, and which encodes for a specific URL component or subcomponent since each URL component or subcomponent has different rules for what characters are valid.

So you only need to supply an adequate NSCharacterSet as argument. Luckily, for URLs there's a very handy class method called URLHostAllowedCharacterSet that you can use like this:

let encodedHost = unencodedHost.stringByAddingPercentEncodingWithAllowedCharacters(.URLHostAllowedCharacterSet())

Update for Swift 3 -- the method becomes the static property urlHostAllowed:

let encodedHost = unencodedHost.addingPercentEncoding(withAllowedCharacters: .urlHostAllowed)

Be aware, though, that:

This method is intended to percent-encode an URL component or subcomponent string, NOT an entire URL string.

stringByAddingPercentEscapesUsingEncoding deprecated

Try below line of code:

NSString *encodedString = [modalData.imageURL stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];

stringByAddingPercentEncodingWithAllowedCharacters:

Returns a new string made from the receiver by replacing all
characters not in the specified set with percent encoded characters.

Character sets are passed to - stringByAddingPercentEncodingWithAllowedCharacters:

+ (NSCharacterSet *)URLUserAllowedCharacterSet;
+ (NSCharacterSet *)URLPasswordAllowedCharacterSet;
+ (NSCharacterSet *)URLHostAllowedCharacterSet;
+ (NSCharacterSet *)URLPathAllowedCharacterSet;
+ (NSCharacterSet *)URLQueryAllowedCharacterSet;
+ (NSCharacterSet *)URLFragmentAllowedCharacterSet;

Reference: https://developer.apple.com/reference/foundation/nsstring/1411946-stringbyaddingpercentencodingwit

stringByAddingPercentEscapesUsingEncoding was deprecated in 9.0 .How to do this?

If you want just fast example look at this code:

NSString * encodedString = [@"string to encode" stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLFragmentAllowedCharacterSet]];

Also check List of predefined characters sets

If you want explanation read the documents or at least this topic: How to encode a URL in Swift

Implicit conversion of 'NSStringEncoding' (aka 'unsigned long') to 'NSCharacterSet * _Nonnull' is disallowed with ARC

You are using the wrong method. Instead of using stringByAddingPercentEncodingWithAllowedCharacters use this stringByAddingPercentEscapesUsingEncoding

If you wan't to use this method stringByAddingPercentEncodingWithAllowedCharacters you have to pass a set of allowed characters.

Try this.

NSURL *candidatesURL = [NSURL URLWithString:[str_url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];

Or if you app development target is IOS 9.0 and above.

stringByAddingPercentEscapesUsingEncoding is deprecated so you can use stringByAddingPercentEncodingWithAllowedCharacters and use URLHostAllowedCharacterSet.

NSURL *candidatesURL = [NSURL URLWithString:[str_url stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];

Encoding a comma with stringByAddingPercentEscapesUsingEncoding

As noted by @DayS, because comma is a legal URL character. However, if you would like to have control over which characters are escaped, look at CFURLCreateStringByAddingPercentEscapes().

NSString *toencode = @",";
NSString *result =
CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(NULL,
                                                          (__bridge CFTypeRef)toencode,
                                                          NULL,
                                                          CFSTR(","),
                                                          kCFStringEncodingUTF8));
NSLog(@"%@", result);

Cannot assign UIImage from NSURL because of string encoding

do like

func setImageWithString(stringbyName: String?) {

     let urlStr = stringbyName.stringByAddingPercentEncodingWithAllowedCharacters(. URLQueryAllowedCharacterSet())

    if let  url = NSURL(string: urlStr) {
        sd_setImageWithURL(url)
    }
}

or use like

   func setImageWithString(stringbyName: String?) {

     let urlStr = stringbyName.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)

    if let  url = NSURL(string: urlStr) {
        sd_setImageWithURL(url)
    }
}

for additional information see this link

NSData & NSURL - url with space having problem

Use: stringByAddingPercentEscapesUsingEncoding:

Returns a representation of the receiver using a given encoding to determine the percent escapes necessary to convert the receiver into a legal URL string.

-(NSString *)stringByAddingPercentEscapesUsingEncoding:(NSStringEncoding)encoding

A representation of the receiver using encoding to determine the percent escapes necessary to convert the receiver into a legal URL string. Returns nil if encoding cannot encode a particular character

Added per request by @rule

NSString* urlText = @"70.84.58.40/projects/igolf/TipThumb/GOLF 58B.jpg";
NSString* urlTextEscaped = [urlText stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [NSURL URLWithString: urlTextEscaped];
NSLog(@"urlText:        '%@'", urlText);
NSLog(@"urlTextEscaped: '%@'", urlTextEscaped);
NSLog(@"url:            '%@'", url);

NSLog output:

urlText:        '70.84.58.40/projects/igolf/TipThumb/GOLF 58B.jpg'  
urlTextEscaped: '70.84.58.40/projects/igolf/TipThumb/GOLF%2058B.jpg'  
url:            '70.84.58.40/projects/igolf/TipThumb/GOLF%2058B.jpg'  

Replace occurrences of space in URL

The correct format for replacing space from url is :

Swift 4.2 , Swift 5

var urlString = originalString.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)

Swift 4

var urlString = originalString.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed)

Objective C

NSString *urlString;//your url string.

urlString = [originalUrl stringByReplacingOccurrencesOfString:@" " withString:@"%20"];

or

urlString = [originalUrl stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

iOS 9 and later

urlString = [originalUrl stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLQueryAllowedCharacterSet]];

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