Regex to Get String Between Two % Characters

Regular Expression to find a string included between two characters while EXCLUDING the delimiters

Easy done:

(?<=\[)(.*?)(?=\])

Technically that's using lookaheads and lookbehinds. See Lookahead and Lookbehind Zero-Width Assertions. The pattern consists of:

• is preceded by a [ that is not captured (lookbehind);
• a non-greedy captured group. It's non-greedy to stop at the first ]; and
• is followed by a ] that is not captured (lookahead).

Alternatively you can just capture what's between the square brackets:

\[(.*?)\]

and return the first captured group instead of the entire match.

Regular expression to get a string between two strings in Javascript

A lookahead (that (?= part) does not consume any input. It is a zero-width assertion (as are boundary checks and lookbehinds).

You want a regular match here, to consume the cow portion. To capture the portion in between, you use a capturing group (just put the portion of pattern you want to capture inside parenthesis):

cow(.*)milk

No lookaheads are needed at all.

Get string between two characters using regex in typescript

If your identifiers are comprised of word characters only:

this regex works: (?<=id=")\w+(?="). The full match is the id. However, this could cause compatibility issue in Safari, that doesn't support lookbehinds ((?<= ))

Test it on Regex101

You can also use capture groups with id="(\w+)". The only captured group will be the id you're looking for.

Test it on Regex101

Regex Match all characters between two strings

For example

(?<=This is)(.*)(?=sentence)

Regexr

I used lookbehind (?<=) and look ahead (?=) so that "This is" and "sentence" is not included in the match, but this is up to your use case, you can also simply write This is(.*)sentence.

The important thing here is that you activate the "dotall" mode of your regex engine, so that the . is matching the newline. But how you do this depends on your regex engine.

The next thing is if you use .* or .*?. The first one is greedy and will match till the last "sentence" in your string, the second one is lazy and will match till the next "sentence" in your string.

Update

Regexr

This is(?s)(.*)sentence

Where the (?s) turns on the dotall modifier, making the . matching the newline characters.

Update 2:

(?<=is \()(.*?)(?=\s*\))

is matching your example "This is (a simple) sentence". See here on Regexr

Javascipt regex to get string between two characters except escaped without lookbehind

You can use this regular expression:

(?:\\.|[^*])*\*((?:\\.|[^*])*)\*

Your code should then only take the (only) capture group of each match.

Like this:

var str = "\\*jdjdjdfdf*test*dfsdf\\*adfasdasdasd*test**test\\**sd*";
var regex = /(?:\\.|[^*])*\*((?:\\.|[^*])*)\*/g

var match;
while (match = regex.exec(str)) {
    console.log(match[1]);
}

Extract substring between two different characters using a python regular expression

Use expression:

(?<=>)[^<:]+(?=:?<)

• (?<=>) Positive lookbehind for >.
• [^<:]+ Match anything other than < or :.
• (?=:?<) Positive lookahead for optional colon :, and <.

You can try the expression live here.

In Python:

import re
first_string = '<h4 id="Foobar:">Foobar:</h4>'
second_string = '<h1 id="Monty">Python<a href="https://..."></a></h1>'

print(re.findall(r'(?<=>)[^<:]+(?=:?<)',first_string)[0])
print(re.findall(r'(?<=>)[^<:]+(?=:?<)',second_string)[0])

Prints:

Foobar
Python

---

Alternatively you could use expression:

(?<=>)[a-zA-Z]+(?=\W*<)

• (?<=>) Positive lookbehind for >.
• [a-zA-Z]+ Lower and upper case letters.
• (?=\W*<) Positive lookahead for any non word characters followed by <.

You can test this expression here.

print(re.findall(r'(?<=>)[a-zA-Z]+(?=\W*<)',first_string)[0])
print(re.findall(r'(?<=>)[a-zA-Z]+(?=\W*<)',second_string)[0])

Prints:

Foobar
Python

---

Related Topics