Ios: JSONobjectwithdata

How to use NSJSONSerialization

Your root json object is not a dictionary but an array:

[{"id": "1", "name":"Aaa"}, {"id": "2", "name":"Bbb"}]

This might give you a clear picture of how to handle it:

NSError *e = nil;
NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData: data options: NSJSONReadingMutableContainers error: &e];

if (!jsonArray) {
  NSLog(@"Error parsing JSON: %@", e);
} else {
   for(NSDictionary *item in jsonArray) {
      NSLog(@"Item: %@", item);
   }
}

Swift 2 - NSJSONSerialization.JSONObjectWithData Handling Error

swift3

NSJSONSerialization and its methods are modified, according to the Swift Documents.

do {
  
    let JsonDict = try JSONSerialization.jsonObject(with: data, options: [])
    // you can now use t with the right type        
    if let dictFromJSON = JsonDict as? [String:String]
 {
        // use dictFromJSON
    }
} catch let error as NSError {
    print(error)
}

Swift2

   init(data: NSData){  // ~this chunk~
     do {
        self.json = try NSJSONSerialization.JSONObjectWithData(data, options: []) as! [String:AnyObject]
   
     } catch {
        print("error: \(error)")
        self.json = nil
     }
  }

for more information tutorial1, tutorial2

How to pass no options to NSJSONSerialization.JSONObjectWithData in Swift

In swift 2 you should use the empty array [] to indicate no options:

NSJSONSerialization.JSONObjectWithData(data, options: [])

NSJSONSerialization.JSONObjectWithData returns weird array instead of dictionary

It's not an array, it's your NSMutableDictionary.

It looks like that when printed in the debugger: there's 3 entries, each one has a key and a value.

Do ALT+CLICK on dataDictionary and read the Xcode tip, you'll see the type.

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