MVC Which Submit Button Has Been Pressed

MVC which submit button has been pressed

Name both your submit buttons the same

<input name="submit" type="submit" id="submit" value="Save" />
<input name="submit" type="submit" id="process" value="Process" />

Then in your controller get the value of submit. Only the button clicked will pass its value.

public ActionResult Index(string submit)
{
    Response.Write(submit);
    return View();
}

You can of course assess that value to perform different operations with a switch block.

public ActionResult Index(string submit)
{
    switch (submit)
    {
        case "Save":
            // Do something
            break;
        case "Process":
            // Do something
            break;
        default:
            throw new Exception();
            break;
    }

    return View();
}

How to detect which submit button was clicked in asp.net (mvc)

your buttons should look like this:

<button name="button" value="12">Press This</button>
<button name="button" value="13">Press That</button>

then just get them in the action

public ActionResult MyAction(string button)
{
    if (button == "12"){
        //Do this
    }

    if (button == "13"){
        //Do that
    }
}

how can I check which submit button was pressed?

well try binding the click event handler to the Save and SaveAndNext buttons like

$(document).delegate("#Save,#SaveAndNext","click",function(e){
 console.log($(this).attr("id"));//here you will know which button was pressed
 //next you can check if the form is valid or not
 if($(this).closest('form').valid()){
 //form is valid submit it ajax(ily)

 }else{
 //form is not valid
 }
});

you can also cache the selector

var $this = $(this);

Determining which submit button was used to POST a form in asp.net MVC

I'd be tempted to add that I'd have used two forms, each one with a single submit button to ensure that each form only had a single responsibility. That would aid the separation of concerns and make the app more testable.

identify which button is being clicked in mvc 5

Give each input button the same name, but a different value

<input type="submit" name="action" value="save" class="btn btn-primary glyphicon glyphicon-save" />

<input type="submit" name="action" id="reset" value="reset" class="btn btn-warning active glyphicon glyphicon-refresh" />

The value will then be in your form collection as

fc["action"]

So your controller action could look like

[HttpPost]
public ActionResult insertrecd(FormCollection fc)
{
    var action = fc["action"];

    if(action == "save")
    {
        //save stuff
    }

    if(action =="reset")
    {
        //reset stuff
    }
}

Checking which submit button was clicked

You should add a name field to both buttons:

<input type="submit" name="button" value="Save and continue"/>
<input type="submit" name="button" value="Save and finish"/>

Once in the controller, you can recover the element by this name field and check its value field:

String field = request.getParameter("button");

if ("Save and continue".equals(button)){
    // Do stuff
}
else if ("Save and finish".equals(button)){
    // Do a different stuff
}
else {
    // None of them were pressed
}

Or also you can use a different name value for both buttons:

<input type="submit" name="button1" value="Save and continue"/>
<input type="submit" name="button2" value="Save and finish"/>

In your controller:

String button1 = request.getParameter("button1");
String button2 = request.getParameter("button2");

if (button1 != null){
    // Do stuff
}
else if (button2 != null){
    // Do a different stuff
}
else {
    // None of them were pressed
}

Second solution is preferred because it doesn't depend on the value of the elements

MVC submit button is always submitting the first record details on POST

There are a couple of problems here. The first is that Html.DisplayFor will just write the display string for the selected property's value with nothing telling the browser that it is form data to be submitted. The other is that all of your submit buttons are for the same form. There are a few ways to solve these problems. The one I would suggest is to create a separate form for each instance of DeployModel, and create hidden inputs for each property you are expecting to receive upon submission of the form:

// inside your foreach loop
@using (Html.BeginForm("Index", "Dep", FormMethod.Post))
{
    <input type="hidden" name="S1" value="@item.S1" />
    <input type="hidden" name="S2" value="@item.S2" />
    ...
    <input type="submit" value="Submit" />
}

Also please note that if you use this method you should remove the outer form - you don't want nested forms!

MVC: what code gets called when you click the submit button?

It would call whatever public action method the form action is pointing to on your controller. You can then call save on the view model.

    public virtual ActionResult Save(MyViewModel model) {
        model.Save();            

        --- more code to do stuff here
    }

Set your form action to MyController/Save

You can also use using (Html.BeginForm... in your code to point the form to a specific action method on a specific controller.

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