Error Deserializing Xml to Object - xmlns='' was not expected
Simply take off the Namespace =
:
[XmlRoot("register-account"), XmlType("register-account")]
public class RegisterAccountResponse {...}
since your xml doesn't seem to be in an xml-namespace. Also, [Serializable]
isn't used by XmlSerializer
.
If your xml was using a namespace it would have an xmlns
at the root.
Also, to help with callers you could add where T : class, new()
(the , new()
being the addition) to your Deserialize
method, since XmlSerializer
demands a public parameterless constructor.
Deserializing XML response xmlns='' was not expected
The capitalization of the XML elements and of your classes do not match. You have two options:
- Rename your classes to match the actual cases.
- Add attributes to the classes that map to the actual names.
I would recommend the second way. For the Response class, this would look like:
<XmlRoot(ElementName:="response")>
Public Class Response
'...
End Class
You should not need any other attributes because the classes are explicitly stated in the root class.
XML Deserialize rss xmlns='' was not expected
The issue is one of namespaces. The rss
element in your XML is in the default namespace, but the XmlRoot
attribute on googleRss
has a namespace of http://base.google.com/ns/1.0
.
The namespace declaration of xmlns:g="..."
binds a namespace to the prefix g
, but this isn't used anywhere in the snippet of XML in your question.
Remove the Namespace
value from the XmlRoot
attribute:
[XmlRoot(ElementName = "rss")]
public partial class googleRss
And remove the default namespace of rss
from the serializer constructor:
var serializer = new XmlSerializer(typeof(GCatalog.googleRss));
See this fiddle for a demo.
{user xmlns='' was not expected.} Deserializing Twitter XML
Either decorate your root entity with the XmlRoot attribute which will be used at compile time.
[XmlRoot(Namespace = "www.contoso.com", ElementName = "MyGroupName", DataType = "string", IsNullable=true)]
Or specify the root attribute when de serializing at runtime.
XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "user";
// xRoot.Namespace = "http://www.cpandl.com";
xRoot.IsNullable = true;
XmlSerializer xs = new XmlSerializer(typeof(User),xRoot);
Deserializing XML and Getting an Error in XML Document (2, 2)
I think there are a number of issues here, more specifically with the Generated Code for the XML.
In Visual Studio, I created a new Class and copied your XML content and used Edit -> Paste Special -> Paste XML as Classes.
Here's the generated code from that exercise:
[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "urn:us:gov:treasury:irs:msg:irstransmitterstatusrequest")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "urn:us:gov:treasury:irs:msg:irstransmitterstatusrequest", IsNullable = false)]
public partial class ACABulkRequestTransmitterStatusDetailResponse
{
private ACABulkRequestTransmitterResponse aCABulkRequestTransmitterResponseField;
private ACABulkReqTrnsmtStsRespGrpDtl aCABulkReqTrnsmtStsRespGrpDtlField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Namespace = "urn:us:gov:treasury:irs:ext:aca:air:ty20")]
public ACABulkRequestTransmitterResponse ACABulkRequestTransmitterResponse
{
get
{
return this.aCABulkRequestTransmitterResponseField;
}
set
{
this.aCABulkRequestTransmitterResponseField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Namespace = "urn:us:gov:treasury:irs:ext:aca:air:ty20")]
public ACABulkReqTrnsmtStsRespGrpDtl ACABulkReqTrnsmtStsRespGrpDtl
{
get
{
return this.aCABulkReqTrnsmtStsRespGrpDtlField;
}
set
{
this.aCABulkReqTrnsmtStsRespGrpDtlField = value;
}
}
}
/// <remarks/>
[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "urn:us:gov:treasury:irs:ext:aca:air:ty20")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "urn:us:gov:treasury:irs:ext:aca:air:ty20", IsNullable = false)]
public partial class ACABulkRequestTransmitterResponse
{
private string transmissionStatusCdField;
private string receiptIdField;
/// <remarks/>
public string TransmissionStatusCd
{
get
{
return this.transmissionStatusCdField;
}
set
{
this.transmissionStatusCdField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Namespace = "urn:us:gov:treasury:irs:common")]
public string ReceiptId
{
get
{
return this.receiptIdField;
}
set
{
this.receiptIdField = value;
}
}
}
/// <remarks/>
[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "urn:us:gov:treasury:irs:ext:aca:air:ty20")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "urn:us:gov:treasury:irs:ext:aca:air:ty20", IsNullable = false)]
public partial class ACABulkReqTrnsmtStsRespGrpDtl
{
private BulkExchangeFile bulkExchangeFileField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Namespace = "urn:us:gov:treasury:irs:common")]
public BulkExchangeFile BulkExchangeFile
{
get
{
return this.bulkExchangeFileField;
}
set
{
this.bulkExchangeFileField = value;
}
}
}
/// <remarks/>
[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "urn:us:gov:treasury:irs:common")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "urn:us:gov:treasury:irs:common", IsNullable = false)]
public partial class BulkExchangeFile
{
private Include includeField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Namespace = "http://www.w3.org/2004/08/xop/include")]
public Include Include
{
get
{
return this.includeField;
}
set
{
this.includeField = value;
}
}
}
/// <remarks/>
[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://www.w3.org/2004/08/xop/include")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://www.w3.org/2004/08/xop/include", IsNullable = false)]
public partial class Include
{
private string hrefField;
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string href
{
get
{
return this.hrefField;
}
set
{
this.hrefField = value;
}
}
}
Using your Deserialize method and this new Class I was able to successfully parse your XML file.
I would use this Class to compare against your own Generated Code and see where the main differences are. Unless you have scope to replace the Generated Code?
The first one I can spot is that the attributes needs to be amended above the ACABulkRequestTransmitterStatusDetailResponse partial class to:
[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Xml", "4.8.4084.0")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "urn:us:gov:treasury:irs:msg:irstransmitterstatusrequest")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "urn:us:gov:treasury:irs:msg:irstransmitterstatusrequest", IsNullable = false)]
I hope this helps you on your way.
Deserializing Xml to ListT - xmlns='' was not expected
You need only two classes:
[XmlType("level")]
public class Level
{
[XmlAttribute("name")]
public string Name { get; set; }
[XmlAttribute("complete")]
public string Complete { get; set; }
[XmlAttribute("stars")]
public string Stars { get; set; }
[XmlAttribute("firstMisson")]
public string FirstMisson { get; set; }
[XmlAttribute("secondMission")]
public string SecondMission { get; set; }
[XmlAttribute("thridMission")]
public string ThridMission { get; set; }
}
[XmlType("location")]
public class Location
{
[XmlElement("level")]
public Level Level { get; set; }
[XmlAttribute("id")]
public string Id { get; set; }
}
The important is to apply XmlType
attribute to the class Location
rather than XmlRoot
.
Now you can deserialize your XML to List<Location>
like this:
var xmlSerializer = new XmlSerializer(typeof(List<Location>),
new XmlRootAttribute("locations"));
List<Location> locations;
using (var stream = File.OpenRead(filepath))
locations = (List<Location>)xmlSerializer.Deserialize(stream);
The trick is to specify the root element name ("locations" in your case) using the XmlSerializer(Type, XmlRootAttribute)
constructor overload.
xmlns='' was not expected. - There is an error in XML document (2, 2) while DeserializeXml to object
Got it need to fix class
[Serializable, XmlRoot(ElementName = "HotelListResponse", Namespace = "http://v3.hotel.wsapi.ean.com/")]
public class HotelListResponse
{
[XmlElement(ElementName = "customerSessionId", Namespace = "")]
public string customerSessionId { get; set; }
[XmlElement(ElementName = "numberOfRoomsRequested", Namespace = "")]
public int numberOfRoomsRequested { get; set; }
[XmlElement(ElementName = "moreResultsAvailable", Namespace = "")]
public bool moreResultsAvailable { get; set; }
}
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