Link Should Be Open in Same Web View in Android

Link should be open in same web view in Android

You need to add WebViewClient to your WebView in order to open it in the WebView. Something like

myWebView.setWebViewClient(new WebViewClient() {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {
        view.loadUrl(request.getUrl().toString());
        return false;
    }
});

How to open url in webview activity

Replace the following code

Intent browseintent=new Intent(Intent.ACTION_VIEW, 
  Uri.parse("http://www.example.com/index.php?iduser="+ scanContent));
  startActivity(browseintent);

with below code

Intent browseintent=new Intent(this, SecondActivity.class);
browseintent.putExtra("url","http://www.example.com/index.php?iduser="+ scanContent);
startActivity(browseintent);

This will open the secondactivity with url in intent extras. You can set it to your edittext or you can use it directly to your webview.
You can receive the url in the second activity using the following code

String url = getIntent().getExtras().getString("url");

You can use it in your button click as follows

b1.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    String url = getIntent().getExtras().getString("url");

                    wv1.getSettings().setLoadsImagesAutomatically(true);
                    wv1.getSettings().setJavaScriptEnabled(true);
                    wv1.setScrollBarStyle(View.SCROLLBARS_INSIDE_OVERLAY);
                    wv1.loadUrl(url);
                }
            });

Open External Links inside Webview

So i found the solution it is pretty much same for both GET and POST requests.

    webView = (WebView) findViewById(R.id.dashboard);

    String url = "http://www.example.test";
    String postData = "json=" + JSON;

    webView.postUrl(url,postData.getBytes());

    webView.setWebViewClient(new WebViewClient() {
        public boolean shouldOverrideUrlLoading(WebView viewx, String urlx) {
            viewx.loadUrl(urlx);
            return false;
        }
    });

How to open different url in single web view android studio

You can send the url of the website to the webview activity using intent and receive them accordingly!on each button click add you

    button1.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                Intent intent=new Intent(this, webview.class);
        intent.putExtra("URL","your url");   
        startActivity(intent);
            }
        });
 button2.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                Intent intent=new Intent(this, webview.class);
        intent.putExtra("URL","your url2");   
        startActivity(intent);
            }
        });

on your weview activity recive these urls and fire your webview as follows

  String url=getIntent().getExtras().getString("URL");

Android WebView links to same window with target=_blank to open new window

First,

mWebView.getSettings().setSupportMultipleWindows(true);

Then in WebChromeClient, override OnCreateWindow()

    private class MyWebChromeclient extends WebChromeClient {


    @Override
    public boolean onCreateWindow(WebView view, boolean isDialog,
            boolean isUserGesture, Message resultMsg) {

            WebView newWebView = new WebView(WebViewActivity2.this);
            view.addView(newWebView);
            WebView.WebViewTransport transport = (WebView.WebViewTransport) resultMsg.obj;
            transport.setWebView(newWebView);
            resultMsg.sendToTarget();

            newWebView.setWebViewClient(new WebViewClient() {
                @Override
                public boolean shouldOverrideUrlLoading(WebView view, String url) {
                    Intent browserIntent = new Intent(Intent.ACTION_VIEW);
                    browserIntent.setData(Uri.parse(url));
                    startActivity(browserIntent);
                    return true;
                }
            });
        return true;
    }

Is it possible to open only one specific link within a browser within a WebView android app?

Yes, that's quite possible. Something like this should do it:

public boolean shouldOverrideUrlLoading(WebView webView, String url) {
    if (url.equals("my url here")) {
        Intent i = new Intent(Intent.ACTION_VIEW);
        i.setData(Uri.parse(url));
        startActivity(i);

        return true;
    }

    return false;
}

Note that you'll return true in the case of loading the URL via the browser to cancel loading it in your WebView.

Android open URL in WebView

You need to Create a WebViewClient

and override the shouldOverrideUrlLoading() method

try this:

    @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    WebView view = (WebView) findViewById(R.id.webView1);
     view.setWebViewClient(new WebViewClient() {
        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            view.loadUrl(url);
            return false;
        }
    });
    view.getSettings().setJavaScriptEnabled(true);
    view.loadUrl("http://example.com");
}

From the Documentation of shouldOverrideUrlLoading

Give the host application a chance to take over the control when a new
url is about to be loaded in the current WebView. If WebViewClient is
not provided, by default WebView will ask Activity Manager to choose
the proper handler for the url. If WebViewClient is provided, return
true means the host application handles the url, while return false
means the current WebView handles the url.

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