Using for Loop for Fibonacci Series to Print Values It Will Print Up to 47 Values Above That It Shows Error

using for loop for fibonacci series to print values it will print up to 47 values above that it shows error

Fib(47) is 2,971,215,073.

2,971,215,073 is larger than 2³¹ - 1 ... which is the largest 32 bit signed integer.

Hence your calculation is overflowing. (In a lot of programming languages, you wouldn't have gotten an error. You would have just gotten the wrong answer.)

How i find the fibonacci series for number 100.

You can't use simple integer arithmetic. You will need to use the Swift equivalent of Java's BigInteger class.

• BigInteger equivalent in Swift?

Why does my c++ fibonacci sequence code give negative values after 46 iterations

The negative values should have been a big hint to you. An int has a maximum value of 2147483647. You overflow the int and it wraps around to being negative.

If you use a bigger type, like std::uint64_t, you can postpone the overflow by a decent amount. Its maximum value is: 18446744073709551615.

Finally, printing in the loop creates a lot of repetition that can be hard to decipher. Just print your vector after the loop is complete, and test with a smaller number of iterations to ensure that your algorithm is functioning properly.

#include <cstdint>
#include <iostream>
#include <limits>
#include <vector>

int main() {
  std::vector<std::uint64_t> vector{0, 1};

  for (int i = 0; i < 47; i++) {
    vector.push_back(vector[i] + vector[i + 1]);
  }

  for (auto i : vector) {
    std::cout << i << ' ';
  }
  std::cout << '\n';
}

The for loop creating the sequence iterates 47 times, so double-check your requirements.

java fibonacci series error : not getting proper output

Your solution is already iterative, including the while loop. However, you are calling fib with the reduced count, greatly increasing the number of numbers printed.

Remove the recursive call, and it will work just fine.

I'm not able to step up terms in fibonacci sequence python

The problem is that you use print at the lowest level, so it is not possible to filter anything from a higher level. If you want to be able to filter, the low fibo_sequence(n) function should not print anything but should return a sequence. A simple way would be to use a list:

# Program to display the Fibonacci sequence up to n-th term
def fibo_sequence(n):
    seq = []

# first two terms
    n1, n2 = 0, 1
    count = 0

# check if the number of terms is valid
    if n <= 0:
        print("Please enter a positive integer")
# if there is only one term, return n1
    elif n == 1:
        print("Fibonacci sequence upto",n,":")
        seq.append(n1)
# generate fibonacci sequence
    else:
        print("Fibonacci sequence:")
        while count < n:
            seq.append(n1)
            nth = n1 + n2
            # update values
            n1 = n2
            n2 = nth
            count += 1
    return seq

But it would still not follow good encapsulation pratices, because the same function shows messages and build the sequence. You should only build the sequence (optionaly an empty list) and let the caller decide what to display if the length of the returned list is 0 or 1.

If you want to go further, you should considere to build a generator that would yield the values one at a time, and because of that would avoid to store them.

Fibonacci sequence with numbers in 1 line and without using list or array

To calculate the next Fibonacci number simply add together the two previous values. You can do this in a for loop using variables declared outside the loop to hold the previous two values.

Use this statement within your loop

print (value, end = '')

This will print the sequence all on one line with each value separated by a space.

n = int(input()) 

fib0 = 0
fib1 = 1
for x in range(0, n):
    nextFib = fib0 + fib1
    fib0 = fib1
    fib1 = nextFib
    print(fib0 , end = ' ')  

How to write the Fibonacci Sequence?

There is lots of information about the Fibonacci Sequence on wikipedia and on wolfram. A lot more than you may need. Anyway it is a good thing to learn how to use these resources to find (quickly if possible) what you need.

Write Fib sequence formula to infinite

In math, it's given in a recursive form:

In programming, infinite doesn't exist. You can use a recursive form translating the math form directly in your language, for example in Python it becomes:

def F(n):
    if n == 0: return 0
    elif n == 1: return 1
    else: return F(n-1)+F(n-2)

Try it in your favourite language and see that this form requires a lot of time as n gets bigger. In fact, this is O(2ⁿ) in time.

Go on on the sites I linked to you and will see this (on wolfram):

This one is pretty easy to implement and very, very fast to compute, in Python:

from math import sqrt
def F(n):
    return ((1+sqrt(5))**n-(1-sqrt(5))**n)/(2**n*sqrt(5))

An other way to do it is following the definition (from wikipedia):

The first number of the sequence is 0,
the second number is 1, and each
subsequent number is equal to the sum
of the previous two numbers of the
sequence itself, yielding the sequence
0, 1, 1, 2, 3, 5, 8, etc.

If your language supports iterators you may do something like:

def F():
    a,b = 0,1
    while True:
        yield a
        a, b = b, a + b

Display startNumber to endNumber only from Fib sequence.

Once you know how to generate Fibonacci Numbers you just have to cycle trough the numbers and check if they verify the given conditions.

Suppose now you wrote a f(n) that returns the n-th term of the Fibonacci Sequence (like the one with sqrt(5) )

In most languages you can do something like:

def SubFib(startNumber, endNumber):
    n = 0
    cur = f(n)
    while cur <= endNumber:
        if startNumber <= cur:
            print cur
        n += 1
        cur = f(n)

In python I'd use the iterator form and go for:

def SubFib(startNumber, endNumber):
    for cur in F():
        if cur > endNumber: return
        if cur >= startNumber:
            yield cur

for i in SubFib(10, 200):
    print i

My hint is to learn to read what you need. Project Euler (google for it) will train you to do so :P
Good luck and have fun!

PHP Fibonacci Sequence

There is actually a way to calculate a Fibonacci number without iteration by using rounding:

http://en.wikipedia.org/wiki/Fibonacci_number#Computation_by_rounding

function getFib($n)
{
    return round(pow((sqrt(5)+1)/2, $n) / sqrt(5));
}

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