Round currency closest to five
Turns out..it's really simple
let x: Float = 1.03 //or whatever value, you can also use the Double type
let y = round(x * 20) / 20
SQL money round to closest 0.05 cents
SELECT ROUND(140.77/5,2) * 5;
+-----------------------+
| ROUND(140.77/5,2) * 5 |
+-----------------------+
| 140.75 |
+-----------------------+
Round to nearest 5 in SQL Server
select round(FineAmount*2,-1)/2 from tickets
or to put nicholaides suggestion in sql
select round(FineAmount/5,0)*5 from tickets
The example assumes that FineAmount is of type money.
The second approach is probably better as the first one works with the limit of maximum_value_of_money_type/2
More on ROUND
Rounding to multiples of 5
You could write it this way:
int roundTo5(int value)
{
return ((value + 2) / 5) * 5;
}
This takes any forint value, adds 2 and divides by 5. This makes a "floor rounding" of integers and multiplies 5 again.
0 → 2 → 0 → 0
1 → 3 → 0 → 0
2 → 4 → 0 → 0
3 → 5 → 1 → 5
4 → 6 → 1 → 5
5 → 7 → 1 → 5
6 → 8 → 1 → 5
7 → 9 → 1 → 5
8 → 10 → 2 → 10
9 → 11 → 2 → 10
Round to nearest 5 up C#
To always round up, you should use Math.Ceiling
instead of Math.Round
:
static int RoundUpToMultipleOf5(decimal value) => (int)Math.Ceiling(value / 5) * 5
Rounding up to the nearest 0.05 in JavaScript
Multiply by 20, then divide by 20:
(Math.ceil(number*20)/20).toFixed(2)
Round up to nearest multiple of five in PHP
This can be accomplished in a number of ways, depending on your preferred rounding convention:
1. Round to the next multiple of 5, exclude the current number
Behaviour: 50 outputs 55, 52 outputs 55
function roundUpToAny($n,$x=5) {
return round(($n+$x/2)/$x)*$x;
}
2. Round to the nearest multiple of 5, include the current number
Behaviour: 50 outputs 50, 52 outputs 55, 50.25 outputs 50
function roundUpToAny($n,$x=5) {
return (round($n)%$x === 0) ? round($n) : round(($n+$x/2)/$x)*$x;
}
3. Round up to an integer, then to the nearest multiple of 5
Behaviour: 50 outputs 50, 52 outputs 55, 50.25 outputs 55
function roundUpToAny($n,$x=5) {
return (ceil($n)%$x === 0) ? ceil($n) : round(($n+$x/2)/$x)*$x;
}
Round to nearest 0.05 using Python
def round_to(n, precision):
correction = 0.5 if n >= 0 else -0.5
return int( n/precision+correction ) * precision
def round_to_05(n):
return round_to(n, 0.05)
How would you round up or down a Float to nearest even numbered integer in Swift 3?
If you want to round to the nearest even number, divide by 2, round and then multiply by 2:
let rounded = Int(round(value / 2.0)) * 2
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