Why can't I enter this date into a table using sql?
Please convert the date into correct date format
insert into employees_table values(05,'Sophie','Kuchinskey','sophiekuchinskey@yahoo.com',105,5000000,60,to_date('20-sep-1994','dd-Mon-YYYY'));
Also you can't give month as sept . it should be sep.
Can't insert date into SQL table
Well, the format YYYYMMDD
is probably not the database date format (you should look for NLS_DATE_FORMAT
to see what's the db date format).
But there's a NLS_DATE_FORMAT
at the system level and a (maybe other) NLS_DATE_FORMAT
at the session level.
You can achieve what you want using TO_DATE
and specifying the format :
INSERT INTO match VALUES(1001, TO_DATE('20130515', 'YYYYMMDD'), 90000, 'American Airlines Arena', 001);
How to enter a Date into a table in TSQL? (Error converting data type varchar to datetime)
The following works in both SQL Server and MySql without ambiguity: yyyy-mm-dd
, like so:
INSERT INTO TableName(DateColumn) VALUES ('1988-10-30');
...as an added benefit there's no question of whether it's a US or European style date on days like the fourth of March...
Unable to insert date data into oracle table
Please try the below query:
INSERT INTO TEST.SUPPLIER (SUPPLIER_ID, SUPPLIER_NAME, CONTACT_NAME, DOB) VALUES(6, 'rr', 'ss',DATE '2019-06-19');**
DATE
keyword interprets the following string as a date.
Can't add row in sql server because of date
You must use a string-based date format, you should pick one that is safe and works in every SQL Server instance, regardless of date format, language and regional settings.
--Format: mon dd yyyy hh:mmAM (or PM)
--result: Dec 7 2018 4:09PM
SELECT convert(varchar, getdate(), 100)
--Format: mm/dd/yyyy
--result: 12/07/2018
SELECT convert(varchar, getdate(), 101)
--Format: yyyy.mm.dd
--result: 2018.12.07
SELECT convert(varchar, getdate(), 102)
--Format: dd/mm/yyyy
--result: 07/12/2018
SELECT convert(varchar, getdate(), 103)
--Format: dd.mm.yyyy
--result: 07.12.2018
SELECT convert(varchar, getdate(), 104)
--Format: dd-mm-yyyy
--result: 07-12-2018
SELECT convert(varchar, getdate(), 105)
--Format: dd mon yyyy
--result: 07 Dec 2018
SELECT convert(varchar, getdate(), 106)
--Format: mon dd, yyyy
--result: Dec 07, 2018
SELECT convert(varchar, getdate(), 107)
--Format: hh:mm:ss
--result: 15:49:24
SELECT convert(varchar, getdate(), 108)
--Format: mon dd yyyy hh:mm:ss:mmmAM (or PM)
--result: Dec 7 2018 3:50:13:540PM
SELECT convert(varchar, getdate(), 109)
--Format: mm-dd-yyyy
--result: 12-07-2018
SELECT convert(varchar, getdate(), 110)
--Format: yyyy/mm/dd -- yyyymmdd - ISO date format - international standard - works with any language setting
--result: 2018/12/07
SELECT convert(varchar, getdate(), 111)
--Format: yyyymmdd
--result: 20181207
SELECT convert(varchar, getdate(), 112)
--Format: dd mon yyyy hh:mm:ss:mmm
--result: 07 Dec 2018 15:53:14:053
SELECT convert(varchar, getdate(), 113)
--Format: hh:mm:ss:mmm(24h)
--result: 15:54:05:693
SELECT convert(varchar, getdate(), 114)
--Format: yyyy-mm-dd hh:mm:ss(24h)
--result: 2018-12-07 15:54:23
SELECT convert(varchar, getdate(), 120)
--Format: yyyy-mm-dd hh:mm:ss.mmm
--result: 2018-12-07 15:55:15.630
SELECT convert(varchar, getdate(), 121)
--Format: yyyy-mm-ddThh:mm:ss.mmm
--result: 2018-12-07T15:55:44.147
SELECT convert(varchar, getdate(), 126)
--Without century (YY) date / datetime conversion - there are exceptions!
--Format: mon dd yyyy hh:mmAM (or PM)
--result: Dec 7 2018 3:56PM
SELECT convert(varchar, getdate(), 0)
--Format: mm/dd/yy
--result: 12/07/18
SELECT convert(varchar, getdate(), 1)
--Format: yy.mm.dd
--result: 18.12.07
SELECT convert(varchar, getdate(), 2)
--Format: dd/mm/yy
--result: 07/12/18
SELECT convert(varchar, getdate(), 3)
--Format: dd.mm.yy
--result: 07.12.18
SELECT convert(varchar, getdate(), 4)
--Format: dd-mm-yy
--result: 07-12-18
SELECT convert(varchar, getdate(), 5)
--Format: dd mon yy
--result: 07 Dec 18
SELECT convert(varchar, getdate(), 6)
--Format: mon dd, yy
--result: Dec 07, 18
SELECT convert(varchar, getdate(), 7)
--Format: hh:mm:ss
--result: 16:02:32
SELECT convert(varchar, getdate(), 8)
--Format: mon dd yyyy hh:mm:ss:mmmAM (or PM)
--result: Dec 7 2018 4:03:02:100PM
SELECT convert(varchar, getdate(), 9)
--Format: mm-dd-yy
--result: 12-07-18
SELECT convert(varchar, getdate(), 10)
--Format: yy/mm/dd
--result: 18/12/07
SELECT convert(varchar, getdate(), 11)
--Format: yymmdd
--result: 181207
SELECT convert(varchar, getdate(), 12)
--Format: dd mon yyyy hh:mm:ss:mmm
--result: 07 Dec 2018 16:05:07:547
SELECT convert(varchar, getdate(), 13)
--Format: hh:mm:ss:mmm(24h)
--result: 16:05:34:363
SELECT convert(varchar, getdate(), 14)
--Format: yyyy-mm-dd hh:mm:ss(24h)
--result: 2018-12-07 16:06:14
SELECT convert(varchar, getdate(), 20)
--Format: yyyy-mm-dd hh:mm:ss.mmm
--result: 2018-12-07 16:06:43.970
SELECT convert(varchar, getdate(), 21)
--Format: mm/dd/yy hh:mm:ss AM (or PM)
--result: 12/07/18 4:06:59 PM
SELECT convert(varchar, getdate(), 22)
--Format: yyyy-mm-dd
--result: 2018-12-07
SELECT convert(varchar, getdate(), 23)
--Format: hh:mm:ss
--result: 16:08:11
SELECT convert(varchar, getdate(), 24)
--Format: yyyy-mm-dd hh:mm:ss.mmm
--result: 2018-12-07 16:08:28.353
SELECT convert(varchar, getdate(), 25)
Convert String to Datetime
Convert Datetime to Date
AND here
SEE THIS ANSWER : Insert converted varchar into datetime sql
SQL query to insert datetime in SQL Server
You will want to use the YYYYMMDD for unambiguous date determination in SQL Server.
insert into table1(approvaldate)values('20120618 10:34:09 AM');
If you are married to the dd-mm-yy hh:mm:ss xm
format, you will need to use CONVERT with the specific style.
insert into table1 (approvaldate)
values (convert(datetime,'18-06-12 10:34:09 PM',5));
5
here is the style for Italian dates. Well, not just Italians, but that's the culture it's attributed to in Books Online.
Insert current date into a date column using T-SQL?
Couple of ways. Firstly, if you're adding a row each time a [de]activation occurs, you can set the column default to GETDATE() and not set the value in the insert. Otherwise,
UPDATE TableName SET [ColumnName] = GETDATE() WHERE UserId = @userId
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