Strip Non-Numeric Characters from a String

Strip all non-numeric characters from string in JavaScript

Use the string's .replace method with a regex of \D, which is a shorthand character class that matches all non-digits:

myString = myString.replace(/\D/g,'');

Java String remove all non numeric characters but keep the decimal separator

Try this code:

String str = "a12.334tyz.78x";
str = str.replaceAll("[^\\d.]", "");

Now str will contain "12.334.78".

Remove non numeric characters from string and cast numbers as an int into an array

You can use Regex to split up your numbers and letters,

string line = "ABD1254AGSHF56984,5845fhfhjekf!54685";

// This splits up big string into a collection of strings until anything other than a character is seen.
var words = Regex.Matches(line, @"[a-zA-Z]+"); 

// This gives you a collection of numbers... 
var numbers = Regex.Matches(line, @"[0-9]+");
foreach (Match number in numbers)
{
    Console.WriteLine(number.Value);
}

// prints
1254
56984
5845
54685

Regex Documentation should be read before implementation for better understanding.

How can I remove non-numeric characters from strings using gsub in R?

Simply use

gsub("[^0-9.-]", "", x)

You can in case of multiple - and . have a second regEx dealing with that.
If you struggle with it, open a new question.

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(Make sure to change . with , if needed)

Removing non numeric characters from a string

The easiest way is with a regexp

import re
a = 'lkdfhisoe78347834 (())&/&745  '
result = re.sub('[^0-9]','', a)

print result
>>> '78347834745'

PHP - remove all non-numeric characters from a string

You can use preg_replace in this case;

$res = preg_replace("/[^0-9]/", "", "Every 6 Months" );

$res return 6 in this case.

If want also to include decimal separator or thousand separator check this example:

$res = preg_replace("/[^0-9.]/", "", "$ 123.099");

$res returns "123.099" in this case

Include period as decimal separator or thousand separator: "/[^0-9.]/"

Include coma as decimal separator or thousand separator: "/[^0-9,]/"

Include period and coma as decimal separator and thousand separator: "/[^0-9,.]/"

Stripping out non-numeric characters in string

There are many ways, but this should do (don't know how it performs with really large strings though):

private static string GetNumbers(string input)
{
    return new string(input.Where(c => char.IsDigit(c)).ToArray());
}

Remove all non-numeric characters from a string in swift

I was hoping there would be something like stringFromCharactersInSet() which would allow me to specify only valid characters to keep.

You can either use trimmingCharacters with the inverted character set to remove characters from the start or the end of the string. In Swift 3 and later:

let result = string.trimmingCharacters(in: CharacterSet(charactersIn: "0123456789.").inverted)

Or, if you want to remove non-numeric characters anywhere in the string (not just the start or end), you can filter the characters, e.g. in Swift 4.2.1:

let result = string.filter("0123456789.".contains)

Or, if you want to remove characters from a CharacterSet from anywhere in the string, use:

let result = String(string.unicodeScalars.filter(CharacterSet.whitespaces.inverted.contains))

Or, if you want to only match valid strings of a certain format (e.g. ####.##), you could use regular expression. For example:

if let range = string.range(of: #"\d+(\.\d*)?"#, options: .regularExpression) {
    let result = string[range] // or `String(string[range])` if you need `String`
}

The behavior of these different approaches differ slightly so it just depends on precisely what you're trying to do. Include or exclude the decimal point if you want decimal numbers, or just integers. There are lots of ways to accomplish this.

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For older, Swift 2 syntax, see previous revision of this answer.

How to remove non-numeric characters (except full stop . ) from a string in amazon redshift

Please try this:

The below regex_replace expression will replace all character which are not ("^") in the (range of 0-9) & "."

SELECT regexp_replace('ABC$$$%%11633123.60','([^0-9.])','') FROM DUAL;

It returns the expected output "11633123.60"

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