SQL Statement to Select All Rows from Previous Day

SQL statement to select all rows from previous day

get today no time:

SELECT dateadd(day,datediff(day,0,GETDATE()),0)

get yestersday no time:

SELECT dateadd(day,datediff(day,1,GETDATE()),0)

query for all of rows from only yesterday:

select 
    * 
    from yourTable
    WHERE YourDate >= dateadd(day,datediff(day,1,GETDATE()),0)
        AND YourDate < dateadd(day,datediff(day,0,GETDATE()),0)

SQL statement to select all rows from previous day with time

You can use:

where date >= dateadd(day, -1, convert(date, getdate())) and
      date < dateadd(hour, -16, convert(date, getdate()))

This query is structured so it can make use of indexes.

You can also phrase this as:

where convert(date, [date]) = dateadd(day, -1, convert(date, getdate()) and
      convert(time, [date]) <= '08:00:00'

This should also use indexes, because conversion to a date is perhaps the only function that does not prevent the use of an index.

SQL Select Records based on current date minus two days

you should try to use dateadd function

select * from orders where orderdate > dateadd(dd,-1,cast(getdate() as date))

Now, this may be exactly what you need but then you need to understand that by casting to date we remove the time part and effectively go back to the start of the day and a day behind it(-1) gives the start of yesterday.

SELECT ROW OF PREVIOUS DAY SQL

If you want all records from any point yesterday, we can use NOW() with an appropriate range:

SELECT object_key, audited_changes
FROM pg_audits
WHERE
    source_action = 'funding' AND
    created_at >= CURRENT_DATE - 1 AND
    created_at < CURRENT_DATE
ORDER BY
    created_at DESC
LIMIT 1000;

NOW()::date returns the current day at midnight, so the above range targets anything on or after midnight of yesterday, but strictly earlier than midnight of today.

how to get records of previous day using tsql?

In SQL Server 2005, this is generally the fastest way to convert a datetime to a date:

DATEADD(day, DATEDIFF(day, 0, yourDate), 0)

In your case, it's done only once, so the how doesn't really matter much. But it does give the following query.

Select
  *
from
  table1
where
      tabledate >= DATEADD(day, DATEDIFF(day, 0, getDate()) - 1, 0)
  AND tabledate <  DATEADD(day, DATEDIFF(day, 0, getDate()),     0)

Selecting all rows that are between yesterday's date time and todays date and time

Your current dateadd will return yesterday at 5:00 PM. Simply add 30 minutes to that dateadd using another dateadd. It will look like: dateadd(minute, 30, [your current dateadd])

Using your code:

dateadd(MINUTE, 30, dateadd(hour, 17, datediff(day, 1, GETDATE())))

All MySQL records from yesterday

Since you're only looking for the date portion, you can compare those easily using MySQL's DATE() function.

SELECT * FROM table WHERE DATE(created_at) = DATE(NOW() - INTERVAL 1 DAY);

Note that if you have a very large number of records this can be inefficient; indexing advantages are lost with the derived value of DATE(). In that case, you can use this query:

SELECT * FROM table
    WHERE created_at BETWEEN CURDATE() - INTERVAL 1 DAY
        AND CURDATE() - INTERVAL 1 SECOND;

This works because date values such as the one returned by CURDATE() are assumed to have a timestamp of 00:00:00. The index can still be used because the date column's value is not being transformed at all.

Select data using getdate for previous day - but only return data for the previous day not previous 24 hours

From the MSDN documentation, here is the expression for today at midnight:

DATEADD(Day, 0, DATEDIFF(Day, 0, GetDate()))

If I read your question correctly, you want to target the 24 hours starting yesterday at midnight up to, but not including, today at midnight. The query below is almost identical to what you already have, except that the WHERE clause imposes the range you want.

SELECT
    UpdateOn = DATEADD(hh, DATEPART(hh, UpdateOn),
        CAST(CAST(UpdateOn AS DATE) AS DATETIME)),
    ROUND(AVG(P1Temp), 1)
FROM TABLE
WHERE
    UpdateOn >=
        DATEADD(day, -1, DATEADD(Day, 0, DATEDIFF(Day, 0, GetDate()))) AND
    UpdateOn < DATEADD(Day, 0, DATEDIFF(Day, 0, GetDate()))
GROUP BY
    DATEADD(hh, DATEPART(hh, UpdateOn),
        CAST(CAST(UpdateOn AS DATE) AS DATETIME));

What would be the right SQL statement to select all records for the latest day IGNORING time stamp?

Use the date() function in the where clause to get only the date part of the timestamp:

select * from tablename
where date(datetime) = (select max(date(datetime)) from tablename)

or:

select * from tablename
where datetime >= (select max(date(datetime)) from tablename)

See the demo.

Results:

> cent_id | datetime            |     NO
> ------: | :------------------ | -----:
>    1094 | 2020-03-08 12:00:00 |   5.16
>    1093 | 2020-03-08 11:00:00 | 10.539
>    1092 | 2020-03-08 10:00:00 | 18.568
>    1091 | 2020-03-08 09:00:00 |  29.63
>    1090 | 2020-03-08 08:00:00 | 29.912
>    1089 | 2020-03-08 07:00:00 | 26.893
>    1088 | 2020-03-08 06:00:00 |  16.27
>    1087 | 2020-03-08 05:00:00 | 29.653

---

Related Topics