SQL Split Comma Separated Row

How to split a comma-separated value to columns

CREATE FUNCTION [dbo].[fn_split_string_to_column] (
    @string NVARCHAR(MAX),
    @delimiter CHAR(1)
    )
RETURNS @out_put TABLE (
    [column_id] INT IDENTITY(1, 1) NOT NULL,
    [value] NVARCHAR(MAX)
    )
AS
BEGIN
    DECLARE @value NVARCHAR(MAX),
        @pos INT = 0,
        @len INT = 0

    SET @string = CASE 
            WHEN RIGHT(@string, 1) != @delimiter
                THEN @string + @delimiter
            ELSE @string
            END

    WHILE CHARINDEX(@delimiter, @string, @pos + 1) > 0
    BEGIN
        SET @len = CHARINDEX(@delimiter, @string, @pos + 1) - @pos
        SET @value = SUBSTRING(@string, @pos, @len)

        INSERT INTO @out_put ([value])
        SELECT LTRIM(RTRIM(@value)) AS [column]

        SET @pos = CHARINDEX(@delimiter, @string, @pos + @len) + 1
    END

    RETURN
END

Turning a Comma Separated string into individual rows

You can use the wonderful recursive functions from SQL Server:

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Sample table:

CREATE TABLE Testdata
(
    SomeID INT,
    OtherID INT,
    String VARCHAR(MAX)
);

INSERT Testdata SELECT 1,  9, '18,20,22';
INSERT Testdata SELECT 2,  8, '17,19';
INSERT Testdata SELECT 3,  7, '13,19,20';
INSERT Testdata SELECT 4,  6, '';
INSERT Testdata SELECT 9, 11, '1,2,3,4';

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The query

WITH tmp(SomeID, OtherID, DataItem, String) AS
(
    SELECT
        SomeID,
        OtherID,
        LEFT(String, CHARINDEX(',', String + ',') - 1),
        STUFF(String, 1, CHARINDEX(',', String + ','), '')
    FROM Testdata
    UNION all

    SELECT
        SomeID,
        OtherID,
        LEFT(String, CHARINDEX(',', String + ',') - 1),
        STUFF(String, 1, CHARINDEX(',', String + ','), '')
    FROM tmp
    WHERE
        String > ''
)
SELECT
    SomeID,
    OtherID,
    DataItem
FROM tmp
ORDER BY SomeID;
-- OPTION (maxrecursion 0)
-- normally recursion is limited to 100. If you know you have very long
-- strings, uncomment the option

---

Output

 SomeID | OtherID | DataItem 
--------+---------+----------
 1      | 9       | 18       
 1      | 9       | 20       
 1      | 9       | 22       
 2      | 8       | 17       
 2      | 8       | 19       
 3      | 7       | 13       
 3      | 7       | 19       
 3      | 7       | 20       
 4      | 6       |          
 9      | 11      | 1        
 9      | 11      | 2        
 9      | 11      | 3        
 9      | 11      | 4        

Split comma separated string table row into separate rows using TSQL

Alternatively, you could use XML like so:

DECLARE @yourTable TABLE(ID INT,SomeValue VARCHAR(25));

INSERT INTO @yourTable
VALUES  (1,'a,b,c,d'),
        (2,'e,f,g');

WITH CTE
AS
(
    SELECT  ID,
            [xml_val] = CAST('<t>' + REPLACE(SomeValue,',','</t><t>') + '</t>' AS XML)
    FROM @yourTable
)

SELECT  ID,
        [SomeValue] = col.value('.','VARCHAR(100)')
FROM CTE
CROSS APPLY [xml_val].nodes('/t') CA(col)

How can I get comma delimited values into new row in BigQuery?

Try this one:

with mytable as (
    select "X" as model, "1,34,60,1000" as alarm union all 
    select "Y", "2,4,5,900,1000" union all 
    select "Z", "1"
)
select model, newalarm
from mytable, unnest(split(alarm)) as newalarm

How to split more than one comma separated column as a separate row in SQL using CROSS APPLY

Since - according to your description - you used CROSS APPLY and your query was successfully executed, this means you are using a SQL Server DB, not MY SQL. You can do two CROSS APPLY to get your expected result. This will produce exactly the outcome you have shown in your question:

SELECT name, phone, value courses FROM
(SELECT name, value phone, courses 
FROM tblName CROSS APPLY STRING_SPLIT(phones, ',')) x
CROSS APPLY STRING_SPLIT(courses, ',')
ORDER BY name, courses, phone;

You can verify this here: db<>fiddle

But this is very risky and you really should avoid such comma-separated contents in one column. I highly recommend to create separate columns for the different values in future.

How to split the row by a comma and unpivot the table in PostgreSQL?

you can use string_to_array() and unnest()

SELECT t.birthday_id , 
       t.child_birthday_id,
       p.place
FROM sh.test t
  CROSS JOIN LATERAL unnest(string_to_array(place, ',')) as p(place);

If you are using Postgres 14 you can also use string_to_table(t.place, ',')

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