Sql: How to to Sum Two Values from Different Tables

SQL: How to to SUM two values from different tables

select region,sum(number) total
from
(
    select region,number
    from cash_table
    union all
    select region,number
    from cheque_table
) t
group by region

How to sum two columns of different tables in sql

In case not all books had a CD:

SELECT A.Books
       , A.Book_ID
       , A.Author
       , B.CD_Name
       , A.rate+COALESCE(B.Cd_price,0) AS TOTAL_PRICE
FROM BOOK A
LEFT JOIN CD B ON A.BOOK_ID = B.BOOK_ID

Question's author evidenced that "The table name is book not Books"

I used originally BOOKS as a "suggestion" because (usually) tables name are plural.

how to sum two columns from different tables MySQL

First use UNION ALL to get all the rows from the 2 tables that you want and then aggregate:

SELECT session_id, SUM(points) AS total_points
FROM (
  SELECT session_id, spent_points AS points
  FROM session_details 
  WHERE session_id IN ("-Meagevy6y9ukbmFXvB7","-Meak6dG9iqvHWfAGQvy") 
  UNION ALL
  SELECT session_id, price_points
  FROM template_sales 
  WHERE session_id IN ("-Meagevy6y9ukbmFXvB7","-Meak6dG9iqvHWfAGQvy") 
) t
GROUP BY session_id

Sum two counts from 2 different tables in sql

You need to use UNION ALL and then apply COUNT

SELECT
    gender as Gender,
    COUNT(*) as Total
FROM
(
    SELECT gender
    FROM memberOne
    UNION ALL
    SELECT gender
    FROM memberTwo
) group by gender

SQL How to use SUM and Group By with multiple tables?

Here is a solution based on your data. Issue with your query is that you were joining tables on a non-unique column resulting in Cartesian product.

Data

DROP TABLE IF EXISTS A;

CREATE TABLE A
(num int,
 id int,
 col1 int);

 INSERT INTO A VALUES (1,     100,     0);
 INSERT INTO A VALUES (2,     100,     1);
 INSERT INTO A VALUES (3,     100,     0);
 INSERT INTO A VALUES (1,     101,     1);
 INSERT INTO A VALUES (2,     101,     1);
 INSERT INTO A VALUES (3 ,    101,     0);

DROP TABLE IF EXISTS B;

 CREATE TABLE B
(idx int,
 id int,
 col2 int);

 INSERT INTO B VALUES (1,     100,     20);
 INSERT INTO B VALUES (2,     100,     20);
 INSERT INTO B VALUES (3,     100,     20);
 INSERT INTO B VALUES (4,     101,     100);
 INSERT INTO B VALUES (5,     101,     100);

DROP TABLE IF EXISTS C;

CREATE TABLE C
(idx int,
 id int,
 col3 int);

 INSERT INTO C VALUES (1,     100,     1);
 INSERT INTO C VALUES (2,     100,     1);
 INSERT INTO C VALUES (3,     100,     1);
 INSERT INTO C VALUES (4,     101,     10);
 INSERT INTO C VALUES (5,     101,     1);

Solution

SELECT a_sum.id, col1_sum, col2_sum, col3_sum
 FROM (SELECT id, SUM(col1) AS col1_sum
         FROM a
        GROUP BY id ) a_sum
      JOIN 
      (SELECT id, SUM(col2) AS col2_sum
         FROM b
        GROUP BY id ) b_sum 
      ON (a_sum.id = b_sum.id)
      JOIN 
      (SELECT id, SUM(col3) AS col3_sum
         FROM c
        GROUP BY id ) c_sum 
      ON (a_sum.id = c_sum.id);

Result is as expected

Note: Do outer joins if an id doesnt have to be present in all three tables.

SQL select sum with multiple where from different tables

Original Answer

First off, your submitted SQL was a mess, things were completely out of the conventional order, I'm not sure it would execute as presented. That said, this should do what you want, assuming I understand your desired output correctly:

SELECT users.id, users.name, users.surname, ROUND(SUM(purchases.sum),2) AS totalSum
FROM purchases
    LEFT JOIN users ON users.id = purchases.user_id
WHERE status='completed'
GROUP BY users.name, users.surname
ORDER BY users.id

The key aspect you were missing from your query was the GROUP BY section, I added ORDER BY for my own benefit on my fiddle, use it if you wish, or not.

Here's a fiddle I prepped for you prior to your posting of your sample data, the main answer has been given by others I see so I'm just posting this because I already did the work on it. http://sqlfiddle.com/#!9/8fa2d/6/0

Answer 2.0

Fiddle is acting up so this is untested but give it a try.

SELECT users.id, users.name, users.surname, ROUND(SUM(CASE WHEN purchases.status = 'completed' THEN purchases.sum ELSE 0 END),2) AS totalSum 
FROM users 
    LEFT JOIN purchases ON users.id = purchases.user_id 
GROUP BY users.id
ORDER BY users.id

Select the sum of values from 2 tables and group by common foreign key

Is this what you want?

select u.*,
       (select sum(a.score) from a where a.id_user = u.id_user) as a_sum,
       (select sum(b.score) from b where b.id_user = u.id_user) as b_sum
from user u;

If you want the total score, just add them together:

select u.*,
       ( (select COUNT(1)  from a where a.id_user = u.id_user) +
         (select coalesce(sum(b.score), 0) from b where b.id_user = u.id_user)
       ) as ab_sum
from user u;

Find sum() from two different tables and join them based on a condition?

You can use union all and group by. For all ids:

select id, date, sum(amount), sum(amount_settled)
from ((select id, date, amount, null as amount_settled
       from table1
      ) union all
      (select id, date, null as amount, amount_settled
       from table2
      ) 
     ) t
group by id, date
order by date;

You can filter for a particular id using a where clause in the outer query.

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