MySQL Query Group by Day/Month/Year

MySQL Query GROUP BY day / month / year

GROUP BY YEAR(record_date), MONTH(record_date)

Check out the date and time functions in MySQL.

isn't in GROUP BY with DAY, MONTH, YEAR

A day by definition is not some free standing abstraction, but also lies in a month and a year. So, you can just select the day, month, and year in your query:

SELECT
    DAY(date_event),
    MONTH(date_event),
    YEAR(date_event),
    COUNT(id) AS howmuch
FROM mytable
WHERE date_event BETWEEN SUBDATE(CURDATE(), 7) AND NOW() 
GROUP BY DAY(date_event), MONTH(date_event), YEAR(date_event) 
ORDER BY YEAR(date_event), MONTH(date_event), DAY(date_event);

But we can make this more concise by just grouping by the DATE(date_event):

SELECT
    DATE(date_event),
    COUNT(id) AS howmuch
FROM mytable
WHERE date_event BETWEEN SUBDATE(CURDATE(), 7) AND NOW() 
GROUP BY DATE(date_event)
ORDER BY DATE(date_event);

GROUP BY month on DATETIME field

Could you try this?

select count(*), DATE_FORMAT(timestamp, "%Y-%m-01")
from title
group by DATE_FORMAT(timestamp, "%Y-%m-01")

Please, note that MONTH() can't differentiate '2013-01-01' and '2014-01-01' as follows.

mysql> SELECT MONTH('2013-01-01'), MONTH('2014-01-01');
+---------------------+---------------------+
| MONTH('2013-01-01') | MONTH('2014-01-01') |
+---------------------+---------------------+
|                   1 |                   1 |
+---------------------+---------------------+

Group by month and year in MySQL

GROUP BY YEAR(t.summaryDateTime), MONTH(t.summaryDateTime);

is what you want.

Group by day using the timestamp field

Use MySQL DATE() function to extract the date from the timestamp:

SELECT name, count(*) FROM mytable GROUP BY DATE(mytable.modified);

The DATE() function extracts the date value from a date or datetime expression.

MySQL : Group by Datetime (Hour - Day - Month - Year)

Use DATE_FORMATE() in group By clause. Hope it should be solved your problem

SELECT
    `client_id`,
    `queue_id`,
    `datetime`,
    COUNT(`type`) AS nombre_appels_repondus
FROM
    `appels`
WHERE
    `type` = "non_repondu"
GROUP BY
    `appels`.`client_id`,
    `appels`.`queue_id`,
    DATE_FORMAT(
        `appels`.`datetime`,'%Y-%m-%d %H');

OR

If you want to add in your selected column list with day, month, year and hour then please try this one

SELECT
    `client_id`,
    `queue_id`,
    `datetime`,
    DATE_FORMAT(`appels`.`datetime`, '%Y-%m-%d') AS DAY,
    DATE_FORMAT(`appels`.`datetime`, '%Y-%m') AS MONTH,
    DATE_FORMAT(`appels`.`datetime`, '%Y') AS YEAR,
    DATE_FORMAT(`appels`.`datetime`, '%H') AS HOUR,
    COUNT(`type`) AS nombre_appels_repondus
FROM
    `appels`
WHERE
    `type` = "non_repondu"
GROUP BY
    `appels`.`client_id`,
    `appels`.`queue_id`,
    DATE_FORMAT(
        `appels`.`datetime`,
        '%Y-%m-%d %H'
    );

How to Group By Year and Month in MySQL

This query will count all the rows, and will also count just the rows where Attribute is not null, grouping by year and month in rows:

SELECT
  Year(`date`),
  Month(`date`),
  Count(*) As Total_Rows,
  Count(`Attribute`) As Rows_With_Attribute
FROM your_table
GROUP BY Year(`date`), Month(`date`)

(this because Count(*) counts all the rows, Count(Attibute) counts all the rows where Attribute is not null)

If you need your table in PIVOT, you can use this to count only the rows where Attribute is not null:

SELECT
  Year(`date`),
  Count(case when month(`date`)=1 then `Attribute` end) As Jan,
  Count(case when month(`date`)=2 then `Attribute` end) As Feb,
  Count(case when month(`date`)=3 then `Attribute` end) As Mar,
  ...
FROM your_table
GROUP BY Year(`date`)

And this to count all the rows:

SELECT
  Year(`date`),
  Count(case when month(`date`)=1 then id end) As Jan,
  Count(case when month(`date`)=2 then id end) As Feb,
  Count(case when month(`date`)=3 then id end) As Mar,
  ...
FROM your_table
GROUP BY Year(`date`)

(or, instead of counting id, you can use Sum(Month(date)=1) like in kander's answer). Of course you can combine both queries into this:

SELECT
  Year(`date`),
  Count(case when month(`date`)=1 then id end) As Jan_Tot,
  Count(case when month(`date`)=1 then `Attribute` end) As Jan_Attr,
  Count(case when month(`date`)=2 then id end) As Feb_Tot,
  Count(case when month(`date`)=2 then `Attribute` end) As Feb_Attr,
  Count(case when month(`date`)=3 then id end) As Mar_Tot,
  Count(case when month(`date`)=3 then `Attribute` end) As Mar_Attr,
  ...
FROM your_table
GROUP BY Year(`date`)

How to group by day/month/year on a subquery

Don't join the table again. Apply the grouping directly to the subquery:

SELECT YEAR(time), MONTHNAME(time), SUM(diff)
FROM (select EL.sensor_id,
             EL.value_id,
             EL.time,
             EL.value,
             if(@lastSN = EL.sensor_id, EL.value - @lastValue, 0.0) as diff,
             @lastSN := EL.sensor_id,
             @lastValue := EL.value
      FROM data_test_debug EL, (SELECT @lastSN := 0,
                                @lastValue := 0) SQLVars
      WHERE EL.value_id = "gas"
      ORDER BY EL.sensor_id, EL.time
     ) AS t
GROUP BY YEAR(time), MONTH(time)

It can be greatly simplified by removing all those fields that you're not using, but you can do that after you get it working.

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