How to Get the Last Row of an Oracle Table

How to get the last row of an Oracle table

There is no such thing as the "last" row in a table, as an Oracle table has no concept of order.

However, assuming that you wanted to find the last inserted primary key and that this primary key is an incrementing number, you could do something like this:

select *
  from ( select a.*, max(pk) over () as max_pk
           from my_table a
                )
 where pk = max_pk

If you have the date that each row was created this would become, if the column is named created:

select *
  from ( select a.*, max(created) over () as max_created
           from my_table a
                )
 where created = max_created

Alternatively, you can use an aggregate query, for example:

select *
  from my_table
 where pk = ( select max(pk) from my_table )

Here's a little SQL Fiddle to demonstrate.

Select last row of table, Oracle 12c

You would seem to want this:

select t.*
from (select symbol
      from ticker
      order by price DESC
     ) t
 where rownum <= 1;

Or in more modern versions of Oracle:

select symbol
from ticker
order by price desc
fetch first 1 row only;

Or, if you want to have fun:

select max(symbol) keep (dense_rank first order by price desc)
from ticket;

The where condition goes before the order by.

Get last row from a query generated table

You can wrap your query and use ROW_NUM():

SELECT *
FROM (
    -- your query with an ORDER BY clause
) x WHERE ROWNUM = 1

Please note that this selects the first row in the resultset. If you want the last row, you would need to change your ORDER BY clause to sort the opposite way in the first place.

If you are running Oracle 12c or higher, you don't need to wrap the query, you can use a FETCH FIRST ROW ONLY clause.

SELECT ...
FROM ...
ORDER BY ...
FETCH FIRST ROW ONLY

Get last row per group in SQL

You can get the expected result with the following query:

select * from tbl1
where id1 in (select max(id1) from tbl1 group by desc1);

Select all but last row in Oracle SQL

Note: the question was changed after this answer was posted. The first two queries work for the original question. The last query (in the addendum) works for the updated question.

This should do the trick, though it will be a bit slow for larger tables:

SELECT prikey, authnum FROM myTable
WHERE prikey <> (SELECT MAX(prikey) FROM myTable)
ORDER BY prikey

This query is longer but for a large table it should faster. I'll leave it to you to decide:

SELECT * FROM (
  SELECT
    prikey,
    authnum,
    ROW_NUMBER() OVER (ORDER BY prikey DESC) AS RowRank
  FROM myTable)
WHERE RowRank <> 1
ORDER BY prikey

---

Addendum There was an update to the question; here's the updated answer.

SELECT
  common,
  SUM(miles)
FROM (
  SELECT
    common,
    miles,
    ROW_NUMBER() OVER (PARTITION BY common ORDER BY prikey DESC) AS RowRank
  FROM myTable
)
WHERE RowRank <> 1
GROUP BY common

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