How to Do Pagination in SQL Server 2008

How to do pagination in SQL Server 2008

You can try something like

DECLARE @Table TABLE(
        Val VARCHAR(50)
)

DECLARE @PageSize INT,
        @Page INT

SELECT  @PageSize = 10,
        @Page = 2

;WITH PageNumbers AS(
        SELECT Val,
                ROW_NUMBER() OVER(ORDER BY Val) ID
        FROM    @Table
)
SELECT  *
FROM    PageNumbers
WHERE   ID  BETWEEN ((@Page - 1) * @PageSize + 1)
        AND (@Page * @PageSize)

Efficient pagination in SQL Server 2008 R2

depending on the [obscenely long select query] structure you may be able to use a temp table or table variable:

- fill a temp table with the ids of the matching rows

- count the temp table rows to calculate the number of pages

- to retrieve the results for the caller build a query with the temp table joined with the relevant database tables

Pagination on SQL Server 2008

Use this tabe value function:

ALTER FUNCTION [dbo].[GetPagedData] 
(   
    -- Add the parameters for the function here
    @pagesize int, 
    @pageindex int
)
RETURNS TABLE 
AS
RETURN 
(

     SELECT TOP (@pagesize) * ,Row_number() Over(order by a.ID) as count FROM 
     (
          SELECT *,
          ROW_NUMBER() OVER (ORDER BY ID) AS num              
          FROM dbo.Employees where IsActive=1
     ) AS a
     WHERE num > @pageindex*@pagesize
)

Use like this
select * from dbo.GetPagedData(pagesize,pageindex)
i.e select * from dbo.GetPagedData(20,0)
Note: page index starts from 0.

In Java loop over this function by incrementing pageindex each time.

How to add pagination to the following SQL

This link shows a nice pagination mechanism for 2008:

Equivalent of LIMIT and OFFSET for SQL Server?

In SQL 2012 there are OFFSET and FETCH keywords that make it very easy to paginate.

This question should be applicable as well:

How to do pagination in SQL Server 2008

SQL Server 2008 pagination with total rows

That is not the right syntax, You need to use another Over clause for count

Try this

;WITH PAGE AS 
(
SELECT ROW_NUMBER() OVER(ORDER BY SEQUENCE_NO ASC) AS _ROW_,
       COUNT(*) OVER() AS _TOTAL_, * 
FROM mytable
) 
SELECT * FROM PAGE WHERE _ROW_ BETWEEN 0 AND 25

What is the best way to paginate results in SQL Server

Getting the total number of results and paginating are two different operations. For the sake of this example, let's assume that the query you're dealing with is

SELECT * FROM Orders WHERE OrderDate >= '1980-01-01' ORDER BY OrderDate

In this case, you would determine the total number of results using:

SELECT COUNT(*) FROM Orders WHERE OrderDate >= '1980-01-01'

...which may seem inefficient, but is actually pretty performant, assuming all indexes etc. are properly set up.

Next, to get actual results back in a paged fashion, the following query would be most efficient:

SELECT  *
FROM    ( SELECT    ROW_NUMBER() OVER ( ORDER BY OrderDate ) AS RowNum, *
          FROM      Orders
          WHERE     OrderDate >= '1980-01-01'
        ) AS RowConstrainedResult
WHERE   RowNum >= 1
    AND RowNum < 20
ORDER BY RowNum

This will return rows 1-19 of the original query. The cool thing here, especially for web apps, is that you don't have to keep any state, except the row numbers to be returned.

Pagination query for mssql server 2008 Throwing Incorrect syntax near 'OFFSET'

Here is my work around and working fine now.

SELECT * FROM   (SELECT ROW_NUMBER() OVER(ORDER BY id) AS rownumber,*
        FROM document)  as somex  WHERE  rownumber >= (1+1)*10-9
                         AND rownumber <=(1+1)*10

In the above query i am replacing (1+1) with (pageNUmber+1).

Please feel free to suggest me if any elegant way available.

SQL Server 2008 Pagination PHP

I'm not familiar with sql server, but it seems to me you just need the end point:

$tsql = " SELECT *
    FROM (SELECT ROW_NUMBER() OVER(ORDER BY productID) AS
    rownum, productID FROM products) AS products1
    WHERE rownum >= $start AND rownum < ($start + $per_page)";
                                        ^     changed      ^

And if $page is supposed to be an integer, it's always best to make sure that it is:

$page = (int) $_GET['page'];

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