Check is string contains special characters and at least 2 characters amongs digit and letter
You can assert the 2 occurrences of a character or digit in the same lookahead, and then match at least a single "special" character.
Using a case insensitive pattern:
^(?=(?:[^a-z\d\n]*[a-z\d]){2})[a-z\d]*[~!@#$%^&*()_+<>•`{}\\][~!@#$%^&*()_+<>•`{}\\a-z\d]*$
The pattern matches:
^
Start of string(?:[^a-z\d\n]*[a-z\d]){2}
Assert 2 occurrences of either a char a-z or a digit. The[^a-z\d\n]*
part negates the character class using[^
to prevent unnecessary backtracking[a-z\d]*
Match optional chars a-z or a digit[~!@#$%^&*()_+<>•`{}\]
Match a special character[~!@#$%^&()_+<>•`{}\a-z\d]
Match optional allowed chars$
End of string
Regex demo
Check for special characters in string
I suggest using RegExp .test()
function to check for a pattern match, and the only thing you need to change is remove the start/end of line anchors (and the *
quantifier is also redundant) in the regex:
var format = /[ `!@#$%^&*()_+\-=\[\]{};':"\\|,.<>\/?~]/;
// ^ ^
document.write(format.test("My@string-with(some%text)") + "<br/>");
document.write(format.test("My string with spaces") + "<br/>");
document.write(format.test("MyStringContainingNoSpecialChars"));
Check for special characters (/*-+_@&$#%) in a string?
The easiest way it to use a regular expression:
Regular Expression for alphanumeric and underscores
Using regular expressions in .net:
http://www.regular-expressions.info/dotnet.html
MSDN Regular Expression
Regex.IsMatch
var regexItem = new Regex("^[a-zA-Z0-9 ]*$");
if(regexItem.IsMatch(YOUR_STRING)){..}
Regex pattern to check if string has no special characters - Java
You missed a \
before the -
. You should use
^[a-zA-Z0-9_\-.]*$
See the demo
Check string contains special characters in batch skript
Found solution with pattern:
Echo "%cd%"|findstr /R "[%%#^&^^^^@^$~!]" 1>nul
if %errorlevel%==0 (
Echo Invalid path: "%cd%"
Echo Remove special symbols: "%#&^@$~!"
)
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