change date from y-m-d to m/d/y format in R
Since your input date is in ISO 8601 format, you can call as.Date()
on it directly to get a Date-classed object, and then format()
can be used to stringify it in any format specifiable using the format specifiers documented here.
d <- '2008-01-01';
format(as.Date(d),'%m/%d/%Y');
## [1] "01/01/2008"
If you really don't want those leading zeroes, you'll have to strip them off yourself using gsub()
:
gsub('\\b0+','',format(as.Date(d),'%m/%d/%Y'));
## [1] "1/1/2008"
PHP convert date format dd/mm/yyyy = yyyy-mm-dd
Dates in the
m/d/y
ord-m-y
formats are disambiguated by looking
at the separator between the various components: if the separator is a
slash (/
), then the Americanm/d/y
is assumed; whereas if the
separator is a dash (-
) or a dot (.
), then the Europeand-m-y
format is assumed. Check more here.
Use the default date function.
$var = "20/04/2012";
echo date("Y-m-d", strtotime($var) );
EDIT I just tested it, and somehow, PHP doesn't work well with dd/mm/yyyy format. Here's another solution.
$var = '20/04/2012';
$date = str_replace('/', '-', $var);
echo date('Y-m-d', strtotime($date));
Change default date time format on a single database in SQL Server
You could use SET DATEFORMAT, like in this example
declare @dates table (orig varchar(50) ,parsed datetime)
SET DATEFORMAT ydm;
insert into @dates
select '2008-09-01','2008-09-01'
SET DATEFORMAT ymd;
insert into @dates
select '2008-09-01','2008-09-01'
select * from @dates
You would need to specify the dateformat in the code when you parse your XML data
How to get current formatted date dd/mm/yyyy in Javascript and append it to an input
I hope this is what you want:
const today = new Date();
const yyyy = today.getFullYear();
let mm = today.getMonth() + 1; // Months start at 0!
let dd = today.getDate();
if (dd < 10) dd = '0' + dd;
if (mm < 10) mm = '0' + mm;
const formattedToday = dd + '/' + mm + '/' + yyyy;
document.getElementById('DATE').value = formattedToday;
How do I get the current date in JavaScript?
Oracle's default date format is YYYY-MM-DD, WHY?
If you are using this query to generate an input file for your Data Warehouse, then you need to format the data appropriately. Essentially in that case you are converting the date (which does have a time component) to a string. You need to explicitly format your string or change your nls_date_format to set the default. In your query you could simply do:
select to_char(some_date, 'yyyy-mm-dd hh24:mi:ss') my_date
from some_table;
Mysql8.0.22 set default value DATE_FORMAT(sysdate() ,'%Y%m%d') error
Read https://dev.mysql.com/doc/refman/8.0/en/data-type-defaults.html
In particular:
The default value specified in a DEFAULT clause can be a literal constant or an expression. With one exception, enclose expression default values within parentheses to distinguish them from literal constant default values.
So in MySQL, unlike MariaDB, you need to put an expression inside parentheses when using it as a DEFAULT.
Example:
create table if not exists `test` (
`client_id` varchar(18) not null default ' ',
`begin_date` int not null default (DATE_FORMAT(sysdate() ,'%Y%m%d')),
`end_date` int not null default (DATE_FORMAT(sysdate() ,'%Y%m%d')),
unique index `uk_key` (`client_id` asc)
) engine = InnoDB default charset = utf8 collate = utf8_bin comment = '';
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