Get all dates between two dates in SQL Server
My first suggestion would be use your calendar table, if you don't have one, then create one. They are very useful. Your query is then as simple as:
DECLARE @MinDate DATE = '20140101',
@MaxDate DATE = '20140106';
SELECT Date
FROM dbo.Calendar
WHERE Date >= @MinDate
AND Date < @MaxDate;
If you don't want to, or can't create a calendar table you can still do this on the fly without a recursive CTE:
DECLARE @MinDate DATE = '20140101',
@MaxDate DATE = '20140106';
SELECT TOP (DATEDIFF(DAY, @MinDate, @MaxDate) + 1)
Date = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, @MinDate)
FROM sys.all_objects a
CROSS JOIN sys.all_objects b;
For further reading on this see:
- Generate a set or sequence without loops – part 1
- Generate a set or sequence without loops – part 2
- Generate a set or sequence without loops – part 3
With regard to then using this sequence of dates in a cursor, I would really recommend you find another way. There is usually a set based alternative that will perform much better.
So with your data:
date | it_cd | qty
24-04-14 | i-1 | 10
26-04-14 | i-1 | 20
To get the quantity on 28-04-2014 (which I gather is your requirement), you don't actually need any of the above, you can simply use:
SELECT TOP 1 date, it_cd, qty
FROM T
WHERE it_cd = 'i-1'
AND Date <= '20140428'
ORDER BY Date DESC;
If you don't want it for a particular item:
SELECT date, it_cd, qty
FROM ( SELECT date,
it_cd,
qty,
RowNumber = ROW_NUMBER() OVER(PARTITION BY ic_id
ORDER BY date DESC)
FROM T
WHERE Date <= '20140428'
) T
WHERE RowNumber = 1;
Get a list of dates between two dates using a function
Try something like this:
CREATE FUNCTION dbo.ExplodeDates(@startdate datetime, @enddate datetime)
returns table as
return (
with
N0 as (SELECT 1 as n UNION ALL SELECT 1)
,N1 as (SELECT 1 as n FROM N0 t1, N0 t2)
,N2 as (SELECT 1 as n FROM N1 t1, N1 t2)
,N3 as (SELECT 1 as n FROM N2 t1, N2 t2)
,N4 as (SELECT 1 as n FROM N3 t1, N3 t2)
,N5 as (SELECT 1 as n FROM N4 t1, N4 t2)
,N6 as (SELECT 1 as n FROM N5 t1, N5 t2)
,nums as (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) as num FROM N6)
SELECT DATEADD(day,num-1,@startdate) as thedate
FROM nums
WHERE num <= DATEDIFF(day,@startdate,@enddate) + 1
);
You then use:
SELECT *
FROM dbo.ExplodeDates('20090401','20090531') as d;
Edited (after the acceptance):
Please note... if you already have a sufficiently large nums table then you should use:
CREATE FUNCTION dbo.ExplodeDates(@startdate datetime, @enddate datetime)
returns table as
return (
SELECT DATEADD(day,num-1,@startdate) as thedate
FROM nums
WHERE num <= DATEDIFF(day,@startdate,@enddate) + 1
);
And you can create such a table using:
CREATE TABLE dbo.nums (num int PRIMARY KEY);
INSERT dbo.nums values (1);
GO
INSERT dbo.nums SELECT num + (SELECT COUNT(*) FROM nums) FROM nums
GO 20
These lines will create a table of numbers containing 1M rows... and far quicker than inserting them one by one.
You should NOT create your ExplodeDates function using a function that involves BEGIN and END, as the Query Optimizer becomes unable to simplify the query at all.
select all dates between two date column in table
Generate a calendar table containing all dates within, e.g. 2018, and then inner join that table to your current table:
DECLARE @todate datetime, @fromdate datetime
SELECT @fromdate='2018-01-01', @todate='2018-12-31'
;WITH calendar (FromDate) AS (
SELECT @fromdate AS FromDate
UNION ALL
SELECT DATEADD(day, 1, FromDate)
FROM Calendar
WHERE FromDate < @todate
)
SELECT t1.FromDate
FROM calendar t1
INNER JOIN yourTable t2
ON t1.FromDate BETWEEN t2.[From] AND t2.[To];
Demo
Get all dates for all date ranges in table using SQL Server
If you are regularly dealing with "jobs" and "schedules" then I propose that you need a permanent calendar table (a table where each row is a unique date). You can create rows for dates dynamically but why do this many times when you can do it once and just re-use?
A calendar table, even of several decades, isn't "big" and when indexed they can be very fast as well. You can also store information about holidays and/or fiscal periods etc.
There are many scripts available to produce these tables, here's an answer with 2 scripts on this site: https://stackoverflow.com/a/5635628/2067753
Assuming you use the second (more comprehensive) script, then you can exclude weekends, or other conditions such as holidays, from query results.
Once you have a permanent Calendar table this style of query may be used:
CREATE TABLE WorkSchedules(
Id INTEGER NOT NULL PRIMARY KEY
,[From] DATE NOT NULL
,[To] DATE NOT NULL
);
INSERT INTO WorkSchedules(Id,[From],[To]) VALUES (1,'2018-01-01','2018-01-05');
INSERT INTO WorkSchedules(Id,[From],[To]) VALUES (2,'2018-01-12','2018-01-12');
with range as (
select min(ws.[From]) as dt_from, max(ws.[To]) dt_to
from WorkSchedules as ws
)
select c.*
from calendar as c
inner join range on c.date between range.dt_from and range.dt_to
where c.KindOfDay = 'BANKDAY'
order by c.date
and the result looks like this (note: "News Years Day" has been excluded)
Date Year Quarter Month Week Day DayOfYear Weekday Fiscal_Year Fiscal_Quarter Fiscal_Month KindOfDay Description
---- --------------------- ------ --------- ------- ------ ----- ----------- --------- ------------- ---------------- -------------- ----------- -------------
1 02.01.2018 00:00:00 2018 1 1 1 2 2 2 2018 1 1 BANKDAY NULL
2 03.01.2018 00:00:00 2018 1 1 1 3 3 3 2018 1 1 BANKDAY NULL
3 04.01.2018 00:00:00 2018 1 1 1 4 4 4 2018 1 1 BANKDAY NULL
4 05.01.2018 00:00:00 2018 1 1 1 5 5 5 2018 1 1 BANKDAY NULL
5 08.01.2018 00:00:00 2018 1 1 2 8 8 1 2018 1 1 BANKDAY NULL
6 09.01.2018 00:00:00 2018 1 1 2 9 9 2 2018 1 1 BANKDAY NULL
7 10.01.2018 00:00:00 2018 1 1 2 10 10 3 2018 1 1 BANKDAY NULL
8 11.01.2018 00:00:00 2018 1 1 2 11 11 4 2018 1 1 BANKDAY NULL
9 12.01.2018 00:00:00 2018 1 1 2 12 12 5 2018 1 1 BANKDAY NULL
Without the where clause the full range is:
Date Year Quarter Month Week Day DayOfYear Weekday Fiscal_Year Fiscal_Quarter Fiscal_Month KindOfDay Description
---- --------------------- ------ --------- ------- ------ ----- ----------- --------- ------------- ---------------- -------------- ----------- ----------------
1 01.01.2018 00:00:00 2018 1 1 1 1 1 1 2018 1 1 HOLIDAY New Year's Day
2 02.01.2018 00:00:00 2018 1 1 1 2 2 2 2018 1 1 BANKDAY NULL
3 03.01.2018 00:00:00 2018 1 1 1 3 3 3 2018 1 1 BANKDAY NULL
4 04.01.2018 00:00:00 2018 1 1 1 4 4 4 2018 1 1 BANKDAY NULL
5 05.01.2018 00:00:00 2018 1 1 1 5 5 5 2018 1 1 BANKDAY NULL
6 06.01.2018 00:00:00 2018 1 1 1 6 6 6 2018 1 1 SATURDAY NULL
7 07.01.2018 00:00:00 2018 1 1 1 7 7 7 2018 1 1 SUNDAY NULL
8 08.01.2018 00:00:00 2018 1 1 2 8 8 1 2018 1 1 BANKDAY NULL
9 09.01.2018 00:00:00 2018 1 1 2 9 9 2 2018 1 1 BANKDAY NULL
10 10.01.2018 00:00:00 2018 1 1 2 10 10 3 2018 1 1 BANKDAY NULL
11 11.01.2018 00:00:00 2018 1 1 2 11 11 4 2018 1 1 BANKDAY NULL
12 12.01.2018 00:00:00 2018 1 1 2 12 12 5 2018 1 1 BANKDAY NULL
and weekends and holidays may be excluded using the column KindOfDay
See this as a demonstration (with build of calendar table) here: http://rextester.com/CTSW63441
Get all dates in date range in SQL Server
With a little help of a numbers table.
declare @T table
(
ID int identity primary key,
FromDate date,
ToDate date
)
insert into @T values
('2011-11-10', '2011-11-12'),
('2011-12-12', '2011-12-14')
select row_number() over(order by D.Dates) as SN,
D.Dates
from @T as T
inner join master..spt_values as N
on N.number between 0 and datediff(day, T.FromDate, T.ToDate)
cross apply (select dateadd(day, N.number, T.FromDate)) as D(Dates)
where N.type ='P'
Try on SE Data
t-sql get all dates between 2 dates
Assuming SQL Server 2005+, use a recursive query:
WITH sample AS (
SELECT CAST('2010-12-01' AS DATETIME) AS dt
UNION ALL
SELECT DATEADD(dd, 1, dt)
FROM sample s
WHERE DATEADD(dd, 1, dt) <= CAST('2010-12-04' AS DATETIME))
SELECT *
FROM sample
Returns:
dt
---------
2010-12-01 00:00:00.000
2010-12-02 00:00:00.000
2010-12-03 00:00:00.000
2010-12-04 00:00:00.000
Use CAST/CONVERT to format as you like.
Using parameters for start & end:
INSERT INTO dbo.YOUR_TABLE
(datetime_column)
WITH sample AS (
SELECT @start_date AS dt
UNION ALL
SELECT DATEADD(dd, 1, dt)
FROM sample s
WHERE DATEADD(dd, 1, dt) <= @end_date)
SELECT s.dt
FROM sample s
SQL Server: How to select all days in a date range even if no data exists for some days
You can use a recursive CTE to build your list of 30 days, then join that to your data
--test
select cast('05 jan 2011' as datetime) as DT, 1 as val into #t
union all select CAST('05 jan 2011' as datetime), 1
union all select CAST('29 jan 2011' as datetime), 1
declare @start datetime = '01 jan 2011'
declare @end datetime = dateadd(day, 29, @start)
;with amonth(day) as
(
select @start as day
union all
select day + 1
from amonth
where day < @end
)
select amonth.day, count(val)
from amonth
left join #t on #t.DT = amonth.day
group by amonth.day
>>
2011-01-04 00:00:00.000 0
2011-01-05 00:00:00.000 2
2011-01-06 00:00:00.000 0
2011-01-07 00:00:00.000 0
2011-01-08 00:00:00.000 0
2011-01-09 00:00:00.000 0
...
Generate Dates between date ranges
Easy on SQL 2005+; easier if you have a numbers or tally table. I faked it below:
DECLARE @StartDate DATE = '20110901'
, @EndDate DATE = '20111001'
SELECT DATEADD(DAY, nbr - 1, @StartDate)
FROM ( SELECT ROW_NUMBER() OVER ( ORDER BY c.object_id ) AS nbr
FROM sys.columns c
) nbrs
WHERE nbr - 1 <= DATEDIFF(DAY, @StartDate, @EndDate)
If you have a tally table, replace the subquery with the table. No recursion.
EDIT: Since folks seem to have questions about the tally table, let me rewrite this using a zero-based tally table. First, here's some code to create and populate a table.
CREATE TABLE [dbo].[nbrs](
[nbr] [INT] NOT NULL
) ON [PRIMARY]
GO
CREATE UNIQUE CLUSTERED INDEX [clidx] ON [dbo].[nbrs]
(
[nbr] ASC
)
GO
INSERT INTO dbo.nbrs (nbr)
SELECT nbr-1
FROM ( SELECT ROW_NUMBER() OVER ( ORDER BY c.object_id ) AS nbr
FROM sys.columns c
) nbrs
GO
Now, that you have the numbers table as a permanent object in your database, you can reuse it for the query INSTEAD of the subquery. The query has also been edited to use a zero-based calculation.
DECLARE @StartDate DATE = '20110901'
, @EndDate DATE = '20111001'
SELECT DATEADD(DAY, nbr, @DateStart)
FROM nbrs
WHERE nbr <= DATEDIFF(DAY, @DateStart, @DateEnd)
Performant, and no recursion.
How to get all dates between two dates in sql server
You Can Try this
Declare @StartDate Date ='2014-04-01'
,@EndDate date ='2014-04-04'
(OR)
Declare @StartDate Datetime ='2014-04-01 00:00:00'
,@EndDate datetime ='2014-04-04 12:59:59'
Query:-
Select * from table where date between @Startdate and @EndDate
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