Calculating number of full months between two dates in SQL
The original post had some bugs... so I re-wrote and packaged it as a UDF.
CREATE FUNCTION FullMonthsSeparation
(
@DateA DATETIME,
@DateB DATETIME
)
RETURNS INT
AS
BEGIN
DECLARE @Result INT
DECLARE @DateX DATETIME
DECLARE @DateY DATETIME
IF(@DateA < @DateB)
BEGIN
SET @DateX = @DateA
SET @DateY = @DateB
END
ELSE
BEGIN
SET @DateX = @DateB
SET @DateY = @DateA
END
SET @Result = (
SELECT
CASE
WHEN DATEPART(DAY, @DateX) > DATEPART(DAY, @DateY)
THEN DATEDIFF(MONTH, @DateX, @DateY) - 1
ELSE DATEDIFF(MONTH, @DateX, @DateY)
END
)
RETURN @Result
END
GO
SELECT dbo.FullMonthsSeparation('2009-04-16', '2009-05-15') as MonthSep -- =0
SELECT dbo.FullMonthsSeparation('2009-04-16', '2009-05-16') as MonthSep -- =1
SELECT dbo.FullMonthsSeparation('2009-04-16', '2009-06-16') as MonthSep -- =2
SQL Server - Count difference months between two dates
If I understood your question correctly, This will be my suggestion:
Just add 1 to your DATEDIFF
output.
SELECT DATEDIFF(mm, '2015-11-01', '2015-12-01') +1
how do I get the EXACT number of months between two dates?
You could do the calculation yourself in the following way:
DECLARE @startdate date = '1/1/2014'
DECLARE @enddate date = '12/30/2014'
DECLARE @startday int = DATEPART(DAY, @startdate)
DECLARE @endday int = DATEPART(DAY, @enddate)
DECLARE @startdateBase date = DATEADD(DAY, 1 - @startday, @startdate)
DECLARE @enddateBase date = DATEADD(DAY, 1 - @endday, @enddate)
DECLARE @deciMonthDiff float = CAST(DATEDIFF(MONTH, @startdate, @enddate) AS float) -
(@startday - 1.0) / DATEDIFF(DAY, @startdateBase, DATEADD(MONTH, 1, @startdateBase)) +
(@endday - 1.0) / DATEDIFF(DAY, @enddateBase, DATEADD(MONTH, 1, @enddateBase))
SELECT @deciMonthDiff
This calculates the @deciMonthDiff
to be 11.935483870967.
Of course you can "inline" this as much as you want in order to avoid all the middle declarations.
The idea is to calculate the total month diff, then subtract the relative part of the first & last month depending on the actual day.
How to count the number of months between two dates SQL
In Postgres you can use the generate_series(date,date,interval) function to construct the date table and then simply group by and count to determine how many times each month occurs in the range.
SELECT EXTRACT(month from d) as month, count(*)
FROM generate_series('2010-8-24'::date, '2012-3-29'::date, '1 month'::interval) d
GROUP BY 1
ORDER BY 1;
month | count
-------+-------
1 | 2
2 | 2
3 | 2
4 | 1
5 | 1
6 | 1
7 | 1
8 | 2
9 | 2
10 | 2
11 | 2
12 | 2
(12 rows)
Count full months between two dates
Test setup
With some sample rows (should be provided in the question):
CREATE TABLE test (
test_id serial PRIMARY KEY
, date1 date NOT NULL
, date2 date NOT NULL
);
INSERT INTO test(date1, date2)
VALUES
('2012-03-20', '2012-01-05') -- 2012-02 lies in between
, ('2012-01-20', '2012-03-05') -- 2012-02 (reversed)
, ('2012-05-06', '2012-05-05') -- nothing
, ('2012-05-01', '2012-06-30') -- still nothing
, ('2012-08-20', '2012-11-05') -- 2012-09 - 2012-10
, ('2012-11-20', '2013-03-05') -- 2012-12 - 2013-02
;
Postgres 9.3 or newer
Use a LATERAL
join:
SELECT to_char(mon, 'YYYY') AS year
, to_char(mon, 'MM') AS month
, count(*) AS ct
FROM (
SELECT date_trunc('mon', least(date1, date2)::timestamp) + interval '1 mon' AS d1
, date_trunc('mon', greatest(date1, date2)::timestamp) - interval '1 mon' AS d2
FROM test
) sub1
, generate_series(d1, d2, interval '1 month') mon -- implicit CROSS JOIN LATERAL
WHERE d2 >= d1 -- exclude ranges without gap right away
GROUP BY mon
ORDER BY mon;
- What is the difference between LATERAL and a subquery in PostgreSQL?
Postgres 9.2 or older
No LATERAL
, yet. Use a subquery instead:
SELECT to_char(mon, 'YYYY') AS year
, to_char(mon, 'MM') AS month
, count(*) AS ct
FROM (
SELECT generate_series(d1, d2, interval '1 month') AS mon
FROM (
SELECT date_trunc('mon', least(date1, date2)::timestamp) + interval '1 mon' AS d1
, date_trunc('mon', greatest(date1, date2)::timestamp) - interval '1 mon' AS d2
FROM test
) sub1
WHERE d2 >= d1 -- exclude ranges without gap right away
) sub2
GROUP BY mon
ORDER BY mon;
Result
year | month | ct
------+-------+----
2012 | 2 | 2
2012 | 9 | 1
2012 | 10 | 1
2012 | 12 | 1
2013 | 1 | 1
2013 | 2 | 1
db<>fiddle here
SQL Fiddle.
Explanation
You are looking for complete calendar months between the two dates.
These queries work with any dates or timestamps in ascending or descending order and should perform well.
The WHERE
clause is optional, since generate_series()
returns no row if start > end. But it should be a bit faster to exclude empty ranges a priori.
The cast to timestamp
makes it a bit cleaner and faster. Rationale:
- Generating time series between two dates in PostgreSQL
Calculate full years and partial months between 2 dates
Take a look and see if this gives you what you are looking for.
Declare @date1 date = '11/01/2001'
Declare @date2 date = '12/01/2002'
Select @date1
,@date2
,Case
when datediff(M,@date1,@date2) < 12 then ''
when datediff(M,@date1,@date2) < 24 then 'one year'
else cast(floor(datediff(M,@date1,@date2)/12) as varchar(20)) + ' Years'
end + ' ' +
Case
when datediff(M,@date1,@date2) - floor(datediff(M,@date1,@date2)/12)*12 = 0 then ''
when datediff(M,@date1,@date2) - floor(datediff(M,@date1,@date2)/12)*12 = 1 then 'one month'
else cast(datediff(M,@date1,@date2) - floor(datediff(M,@date1,@date2)/12)*12 as varchar(20)) + ' Months'
end
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