How to merge 2 vectors alternating indexes?
This will work using rbind
:
c(rbind(a, b))
For example:
a = c(1,2,3)
b = c(11,12,13)
c(rbind(a,b))
#[1] 1 11 2 12 3 13
Cross merge two vectors
a <- c(1, 2, 3, 4)
b <- c(5, 6, 7, 8)
ab <- as.vector(matrix(c(a, b), nrow = 2, byrow = TRUE))
ab
[1] 1 5 2 6 3 7 4 8
Combining 2 vectors in alternating way by step of 4 in R
We can do this by splitting. Create a function to create a grouping variable with gl
that increments at blocks of 'n' (here n is 4), then split both the vectors into a list
, use Map
to concatenate the corresponding list
elements and unlist
the list
to create a vector
f1 <- function(x, n) split(x, as.integer(gl(length(x), n, length(x))))
unlist( Map(c, f1(a, 4), f1(b, 4)), use.names = FALSE)
#[1] 723 680 2392 2063 1 2 3 4
#[9] 721 746 2053 2129 5 6 7 8
Or if the lengths are the same, then we can rbind
and concatenate after creating a matrix
c(rbind(matrix(a, nrow =4), matrix(b, nrow = 4)))
#[1] 723 680 2392 2063 1 2 3 4 721 746 2053 2129 5 6 7 8
combine two vectors in correct order
v1 <- c("a","j","d")
v2 <- c("book","tree","river")
c(rbind(v1,v2))
# [1] "a" "book" "j" "tree" "d" "river"
Merge two arrays with alternating values
You could iterate the min length of both array and build alternate elements and at the end push the rest.
var array1 = ["a", "b", "c", "d"], array2 = [1, 2], result = [], i, l = Math.min(array1.length, array2.length); for (i = 0; i < l; i++) { result.push(array1[i], array2[i]);}result.push(...array1.slice(l), ...array2.slice(l));
console.log(result);
Pythonic way to combine (interleave) two lists in an alternating fashion?
Here's one way to do it by slicing:
>>> list1 = ['f', 'o', 'o']
>>> list2 = ['hello', 'world']
>>> result = [None]*(len(list1)+len(list2))
>>> result[::2] = list1
>>> result[1::2] = list2
>>> result
['f', 'hello', 'o', 'world', 'o']
join two lists in R offset by a lag of 1
You can do :
as.list(c(rbind(l1, l2)))
#[[1]]
#[1] "a"
#[[2]]
#[1] "d"
#[[3]]
#[1] "b"
#[[4]]
#[1] "e"
#[[5]]
#[1] "c"
#[[6]]
#[1] "f"
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