How Does R's Ifelse Work with Character Data

How does R's ifelse work with character data?

+1 for using a data.frame named blarg.

To expand on what Ben said, factors are internally stored as integers so when you do something like this, R doesn't handle it the way you expect.

Take a look at str(blarg) in the steps of your code above.

You can either use stringsAsFactors=FALSE as Ben suggested, or make use of the factor:

ifelse(blarg$a!='bb', levels(blarg$a), 'ZZZ')

Or better yet, if you want to replace the levels of blarg$a that are 'bb', you can eliminate the ifelse statement altogether:

levels(blarg$a)[levels(blarg$a)=='bb'] <- 'ZZZ'

R if else with multiple conditions for character vectors with NAs

A tidyverse approach

library(tidyverse)
DATA %>%
mutate_if(is.factor, as.character) %>%
mutate(Col.B = if_else(Col.A %in% c("Yes", "yes", "No", "no"), Col.B, Col.A))
# Col.A Col.B
#1 Some Text Some Text
#2 Some other text Some other text
#3 Yes Green
#4 No <NA>
#5 no <NA>
#6 <NA> <NA>
#7 No <NA>
#8 Yes Blue
#9 yes Blue 2
#10 <NA> <NA>
#11 <NA> <NA>
#12 <NA> <NA>

In base R using grepl

transform(DATA, Col.B = ifelse(
grepl("([Yy]es|[Nn]o)", Col.A),
as.character(Col.B), as.character(Col.A)))

or similar to the tidyverse approach using %in% with tolower (thanks @DJV)

transform(DATA, Col.B = ifelse(
tolower(Col.A) %in% c("yes", "no"),
as.character(Col.B), as.character(Col.A)))

Why ifelse with character statement is not working?

There are three changes to be made,

  1. converting to character would be with deparse/substitute

  2. if/else would be appropriate as ifelse requires all the arguments to be of same length

  3. iris * 2 as an else option wouldn't work as the dataset includes a factor column as well. So, we need to multiply only those numeric columns

    my_fun <- function(x) {               
    x <- deparse(substitute(x))
    if(x == 'Species') {
    iris %>%
    select(all_of(x))
    } else {
    iris %>%
    mutate(across(where(is.numeric), ~ .* 2))
    }
    }

-testing

my_fun(Species)
# Species
#1 setosa
#2 setosa
#3 setosa
#4 setosa
#5 setosa
#6 setosa
#...

and if we pass another input

my_fun(hello)
# Sepal.Length Sepal.Width Petal.Length Petal.Width Species
#1 10.2 7.0 2.8 0.4 setosa
#2 9.8 6.0 2.8 0.4 setosa
#3 9.4 6.4 2.6 0.4 setosa
#4 9.2 6.2 3.0 0.4 setosa
#5 10.0 7.2 2.8 0.4 setosa
#6 10.8 7.8 3.4 0.8 setosa
# ...

Using ifelse() statements to get objects of different classes in R

ifelse requires all the arguments to be same length. Here, it is not the case. Therefore, we need if/else

if(is.data.frame(mtcars) ) get(mtcars__string_object) else NA

-ouptut

                  mpg cyl  disp  hp drat    wt  qsec vs am gear carb
Mazda RX4 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout 18.7 8 360.0 175 3.15 3.440 17.02 0 0 3 2
Valiant 18.1 6 225.0 105 2.76 3.460 20.22 1 0 3 1
Duster 360 14.3 8 360.0 245 3.21 3.570 15.84 0 0 3 4
Merc 240D 24.4 4 146.7 62 3.69 3.190 20.00 1 0 4 2
Merc 230 22.8 4 140.8 95 3.92 3.150 22.90 1 0 4 2
Merc 280 19.2 6 167.6 123 3.92 3.440 18.30 1 0 4 4
Merc 280C 17.8 6 167.6 123 3.92 3.440 18.90 1 0 4 4
Merc 450SE 16.4 8 275.8 180 3.07 4.070 17.40 0 0 3 3
Merc 450SL 17.3 8 275.8 180 3.07 3.730 17.60 0 0 3 3
Merc 450SLC 15.2 8 275.8 180 3.07 3.780 18.00 0 0 3 3
Cadillac Fleetwood 10.4 8 472.0 205 2.93 5.250 17.98 0 0 3 4
Lincoln Continental 10.4 8 460.0 215 3.00 5.424 17.82 0 0 3 4
Chrysler Imperial 14.7 8 440.0 230 3.23 5.345 17.42 0 0 3 4
Fiat 128 32.4 4 78.7 66 4.08 2.200 19.47 1 1 4 1
Honda Civic 30.4 4 75.7 52 4.93 1.615 18.52 1 1 4 2
Toyota Corolla 33.9 4 71.1 65 4.22 1.835 19.90 1 1 4 1
Toyota Corona 21.5 4 120.1 97 3.70 2.465 20.01 1 0 3 1
Dodge Challenger 15.5 8 318.0 150 2.76 3.520 16.87 0 0 3 2
AMC Javelin 15.2 8 304.0 150 3.15 3.435 17.30 0 0 3 2
Camaro Z28 13.3 8 350.0 245 3.73 3.840 15.41 0 0 3 4
Pontiac Firebird 19.2 8 400.0 175 3.08 3.845 17.05 0 0 3 2
Fiat X1-9 27.3 4 79.0 66 4.08 1.935 18.90 1 1 4 1
Porsche 914-2 26.0 4 120.3 91 4.43 2.140 16.70 0 1 5 2
Lotus Europa 30.4 4 95.1 113 3.77 1.513 16.90 1 1 5 2
Ford Pantera L 15.8 8 351.0 264 4.22 3.170 14.50 0 1 5 4
Ferrari Dino 19.7 6 145.0 175 3.62 2.770 15.50 0 1 5 6
Maserati Bora 15.0 8 301.0 335 3.54 3.570 14.60 0 1 5 8
Volvo 142E 21.4 4 121.0 109 4.11 2.780 18.60 1 1 4 2

ifelse statement with string

double is of length 1

length(double)
#[1] 1

whereas

length(data$var1)
#[1] 10

while using ifelse it returns the value which is of same length as test as

double == "true"

returns a vector of length 1, hence you get only one value back which is the first value of calculation

2*data$var1[1]
#[1] 2

and this value is recycled across all values.

For ifelse to work for all value we need to somehow make the length equal

ifelse(rep(double == "true", length(data$var1)), 2*data$var1, NA)
#[1] 2 4 6 8 10 12 14 16 18 20

However, if you have only one value to compare it is better to use simple if/else instead of ifelse

data$var2 <- if (double == "true") 2*data$var1 else NA 

New character values based on date range using ifelse

I found the problem vue$Name <- ifelse(vue$Serial == "483689" && vue$Date >= "2019-8-23 10:00:00", "newname", vue$Name)

I was missing the second & and vue$ before Date



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