Forecasting Time Series Data

Forecasting time series data

Here's what I did:

x$Date = as.Date(x$Date,format="%m/%d/%Y")
x = xts(x=x$Used, order.by=x$Date)
# To get the start date (305)
# > as.POSIXlt(x = "2011-11-01", origin="2011-11-01")$yday
## [1] 304
# Add one since that starts at "0"
x.ts = ts(x, freq=365, start=c(2011, 305))
plot(forecast(ets(x.ts), 10))

Resulting in:

Example output

What can we learn from this:

  • Many of your steps can be combined reducing the number of intermediate objects you create
  • The output is still not as pretty as @joran, but it is still easily readable. 2011.85 means "day number 365*.85" (day 310 in the year).
  • Figuring out the day in a year can be done by using as.POSIXlt(x = "2011-11-01", origin="2011-11-01")$yday and figuring out the date from a day number can be done by using something like as.Date(310, origin="2011-01-01")

Update

You can drop even more intermediate steps, since there's no reason to first convert your data into an xts.

x = ts(x$Used, start=c(2011, as.POSIXlt("2011-11-01")$yday+1), frequency=365)
# NOTE: We have only selected the "Used" variable
# since ts will take care of dates
plot(forecast(ets(x), 10))

This gives exactly the same result as the image above.

Update 2

Building on the solution provided by @joran, you can try:

# 'start' calculation = `as.Date("2011-11-01")-as.Date("2011-01-01")+1`
# No need to convert anything to dates at this point using xts
x = ts(x$Used, start=c(2011, 305), frequency=365)
# Directly plot your forecast without your axes
plot(forecast(ets(x), 10), axes = FALSE)
# Generate labels for your x-axis
a = seq(as.Date("2011-11-01"), by="weeks", length=11)
# Plot your axes.
# `at` is an approximation--there's probably a better way to do this,
# but the logic is approximately 365.25 days in a year, and an origin
# date in R of `January 1, 1970`
axis(1, at = as.numeric(a)/365.25+1970, labels = a, cex.axis=0.6)
axis(2, cex.axis=0.6)

Which will yield:

Second attempt

Part of the problem in your original code is that after you have converted your data to an xts object, and converted that to a ts object, you lose the dates in your forecast points.

Compare the first column (Point) of your x.fore output to the following:

> forecast(ets(x), 10)
Point Forecast Lo 80 Hi 80 Lo 95 Hi 95
2012.000 741.6437 681.7991 801.4884 650.1192 833.1682
2012.003 741.6437 676.1250 807.1624 641.4415 841.8459
2012.005 741.6437 670.9047 812.3828 633.4577 849.8298
2012.008 741.6437 666.0439 817.2435 626.0238 857.2637
2012.011 741.6437 661.4774 821.8101 619.0398 864.2476
2012.014 741.6437 657.1573 826.1302 612.4328 870.8547
2012.016 741.6437 653.0476 830.2399 606.1476 877.1399
2012.019 741.6437 649.1202 834.1672 600.1413 883.1462
2012.022 741.6437 645.3530 837.9345 594.3797 888.9078
2012.025 741.6437 641.7276 841.5599 588.8352 894.4523

Hopefully this helps you understand the problem with your original approach and improves your capacity with dealing with time series in R.

Update 3

Final, and more accurate solution--because I'm avoiding other work that I should actually be doing right now...

Use the lubridate package for better date handling:

require(lubridate)
y = ts(x$Used, start=c(2011, yday("2011-11-01")), frequency=365)
plot(forecast(ets(y), 10), xaxt="n")
a = seq(as.Date("2011-11-01"), by="weeks", length=11)
axis(1, at = decimal_date(a), labels = format(a, "%Y %b %d"), cex.axis=0.6)
abline(v = decimal_date(a), col='grey', lwd=0.5)

Resulting in:

Final plot

Note the alternative method of identifying the start date for your ts object.

Forecasting time series data (creating predictions)

It is good to remove NA now, otherwise predict() thinks the series ends on 2014.Qtr4, not 2014.Qtr1:

xx <- na.omit(x)
mod = auto.arima(xx, max.p = 4, max.q = 4, max.d = 0, seasonal = FALSE)
predict(mod, n.ahead = 3)
#$pred
# Qtr2 Qtr3 Qtr4
#2014 13.70785 17.79853 16.86842
#
#$se
# Qtr2 Qtr3 Qtr4
#2014 2.614327 3.092998 3.156169


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