Unknown column in 'field list' error on MySQL Update query
Try using different quotes for "y" as the identifier quote character is the backtick (`). Otherwise MySQL "thinks" that you point to a column named "y".
See also MySQL 8 Documentation
Please use double-/single quotes for values, strings, etc.
Use backticks for column-names only.
New column - multiple conditions from multiple rows and columns
df |>
group_by(id) |>
mutate(train_avail = {
car <- min(duration[main_mode == "car"])
if_else(main_mode == "train",
if_else(duration > 2* car, 0, 1),
NA_real_)
})
##> + # A tibble: 8 × 4
##> # Groups: id [3]
##> main_mode duration id train_avail
##> <chr> <int> <int> <dbl>
##> 1 train 1250 1 0
##> 2 train 900 1 1
##> 3 car 540 1 NA
##> 4 train 650 2 1
##> 5 car 450 2 NA
##> 6 plane 350 2 NA
##> 7 train 350 3 1
##> 8 car 890 3 NA
Understand the warning message in across in R
There is not much difference between using where
and not using it. It just shows a warning to suggest a better syntax. Basically where
takes a predicate function and apply it on every variable (column) of your data set. It then returns every variable for which the function returns TRUE
. The following examples are taken from the documentations of where
:
iris %>% select(where(is.numeric))
# or an anonymous function
iris %>% select(where(function(x) is.numeric(x)))
# or a purrr style formula as a shortcut for creating a function on the spot
iris %>% select(where(~ is.numeric(.x)))
Or you can also have two conditions using shorthand &&
:
# The following code selects are numeric variables whose means are greater thatn 3.5
iris %>% select(where(~ is.numeric(.x) && mean(.x) > 3.5))
You can use select(where(is.character))
for .cols
argument of the across
function and then apply a function in .fns
argument on the selected columns.
For more information you can always refer to documentations which are the best source to learn more about these materials.
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