Why Is Tkinter Widget Stored as None? (Attributeerror: 'Nonetype' Object ...)(Typeerror: 'Nonetype' Object ...)

Why is Tkinter widget stored as None? (AttributeError: 'NoneType' object ...)(TypeError: 'NoneType' object ...)

widget is stored as None because geometry manager methods grid, pack, place return None, and thus they should be called on a separate line than the line that creates an instance of the widget as in:

widget = ...
widget.grid(..)

or:

widget = ...
widget.pack(..)

or:

widget = ...
widget.place(..)

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And for the 2nd code snippet in the question specifically:

widget = tkinter.Button(...).pack(...)

should be separated to two lines as:

widget = tkinter.Button(...)
widget.pack(...)

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Info: This answer is based on, if not for the most parts copied from, this answer.

Error when configuring tkinter widget: 'NoneType' object has no attribute

NoneType object has no attribute ... means that you have an object that is None, and you're trying to use an attribute of that object.

In your case you're doing q.get(...), so q must be None. Since q is the result of calling nse.get_quote(...), that function must have the possibility of returning None. You'll need to adjust your code to account for that possibility, such as checking the result before trying to use it:

q = nse.get_quote(stock)
if q is not None:
    print ...

The root of the problem is likely in how you're reading the file. stock will include the newline, so you should strip that off before calling nse.get_quote:

q = nse.get_quote(stock.strip())

Tkinter: AttributeError: NoneType object has no attribute attribute name

The grid, pack and place functions of the Entry object and of all other widgets returns None. In python when you do a().b(), the result of the expression is whatever b() returns, therefore Entry(...).grid(...) will return None.

You should split that on to two lines like this:

entryBox = Entry(root, width=60)
entryBox.grid(row=2, column=1, sticky=W)

That way you get your Entry reference stored in entryBox and it's laid out like you expect. This has a bonus side effect of making your layout easier to understand and maintain if you collect all of your grid and/or pack statements in blocks.

tkinter label does not respond to button

Declare the label and it's grid separately

Sign = Label()
Sign.grid() 

See the type of

Label(). grid ()

It is None because grid method returns none and you assign it to sign.
So,

 sign = none

And none has no attribute called config. That's why the error occurs

Also remove master, from the def tryout(): section or else there will be a '_tkinter.TclError: unknown option' error.

Thanks, C Vith, for debugging the code (Also remove ..... error) Suggested by C Vith

how to fix AttributeError: 'NoneType' object has no attribute 'get' for tkinter entry

it's entry.grid(...) return None

I think you want

    from tkinter import *

    root = Tk()

    a = Entry(root)
    a.grid(row = 0, column = 0)

    b = Button(root,text = 'CLICK', command= lambda: test()).grid(row = 2, column = 2)

    def test():
        print(a.get())

    root.mainloop()

Global variable process

You can't use a single line to initialize and layout a widget. You have to put that on 2 lines, like this:

labelP = Label(mainframe, text = np.array(A[1,0]), width=5, font = 'Arial 10 bold')
labelP.grid(column=2, row=5, sticky=W)

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