Valueerror: Invalid Literal For Int() With Base 10: ''

ValueError: invalid literal for int () with base 10

Answer:

Your traceback is telling you that int() takes integers, you are trying to give a decimal, so you need to use float():

a = float(a)

This should work as expected:

>>> int(input("Type a number: "))
Type a number: 0.3
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '0.3'
>>> float(input("Type a number: "))
Type a number: 0.3
0.3

Computers store numbers in a variety of different ways. Python has two main ones. Integers, which store whole numbers (ℤ), and floating point numbers, which store real numbers (ℝ). You need to use the right one based on what you require.

(As a note, Python is pretty good at abstracting this away from you, most other language also have double precision floating point numbers, for instance, but you don't need to worry about that. Since 3.0, Python will also automatically convert integers to floats if you divide them, so it's actually very easy to work with.)

Previous guess at answer before we had the traceback:

Your problem is that whatever you are typing is can't be converted into a number. This could be caused by a lot of things, for example:

>>> int(input("Type a number: "))
Type a number: -1
-1
>>> int(input("Type a number: "))
Type a number: - 1
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '- 1'

Adding a space between the - and 1 will cause the string not to be parsed correctly into a number. This is, of course, just an example, and you will have to tell us what input you are giving for us to be able to say for sure what the issue is.

Advice on code style:

y = [int(a)**(-2),int(a)**(-1.75),int(a)**(-1.5),int(a)**(-1.25),
            int(a)**(-1),int(a)**(-0.75),int(a)**(-0.5),int(a)**(-0.25),
            int(a)**(0),int(a)**(0.25),int(a)**(0.5),int(a)**(0.75),
            int(a)**1,int(a)**(1.25),int(a)**(1.5),int(a)**(1.75), int(a)**(2)]

This is an example of a really bad coding habit. Where you are copying something again and again something is wrong. Firstly, you use int(a) a ton of times, wherever you do this, you should instead assign the value to a variable, and use that instead, avoiding typing (and forcing the computer to calculate) the value again and again:

a = int(a)

In this example I assign the value back to a, overwriting the old value with the new one we want to use.

y = [a**i for i in x]

This code produces the same result as the monster above, without the masses of writing out the same thing again and again. It's a simple list comprehension. This also means that if you edit x, you don't need to do anything to y, it will naturally update to suit.

Also note that PEP-8, the Python style guide, suggests strongly that you don't leave spaces between an identifier and the brackets when making a function call.

Getting ValueError: invalid literal for int() with base 10 trying to use datanews module

The Python ValueError: invalid literal for int() with base 10 error is raised when you try to convert a string value that is not formatted as an integer.

To solve this problem, you can use the float() method to convert a floating-point number in a string to an integer. Then, you can use int() to convert your number to an integer.

If this does not work, make sure that the value of a string does not contain any letters. Strings with letters cannot be converted to an integer unless those letters have a special meaning in Python.

To know correctly >> Debug using print statements

..............
for num in articles:
    print(num) # This will tell you the truth
    nnum = int(str(num))
..............

# if you have a list and you want to get index value pair
for i,v in enumerate(yourList)

I don't see any int in your input:
'{\'url\': \'https://www.theapplepost.com/2020/10/22/apple-discontinues-apple-tv-remote-app/\', \'source\': \'theapplepost.com\', \'authors\': [\'The Apple Post\'], \'title\': "Apple discontinues Appl

ValueError: invalid literal for int() with base 10

I think the problem here is the order of arguments. when you call AppAssessment() with positional arguments, the order of arguments may not be what you expect. so calling AppAssessment() with keyword arguments may solve the problem.

replace this line:

response_data = AppAssessment(contact_uuid, step, value, optionId)

with this:

response_data = AppAssessment(contact_uuid=contact_uuid, step=step, optionId=optionId, user_input=value)

I am not sure which attribute you wanted to use value for. but I guess it was user_input.

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