Typeerror: List Indices Must Be Integers or Slices, Not Str

TypeError: list indices must be integers or slices, not str

First, array_length should be an integer and not a string:

array_length = len(array_dates)

Second, your for loop should be constructed using range:

for i in range(array_length):  # Use `xrange` for python 2.

Third, i will increment automatically, so delete the following line:

i += 1

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Note, one could also just zip the two lists given that they have the same length:

import csv

dates = ['2020-01-01', '2020-01-02', '2020-01-03']
urls = ['www.abc.com', 'www.cnn.com', 'www.nbc.com']

csv_file_patch = '/path/to/filename.csv'

with open(csv_file_patch, 'w') as fout:
    csv_file = csv.writer(fout, delimiter=';', lineterminator='\n')
    result_array = zip(dates, urls)
    csv_file.writerows(result_array)

TypeError: list indices must be integers or slices, not str - While accessing element of list

I was solve this by the following

1. Passing [{"id":9,"name":"Foo"}] instead of ['{"id":9,"name":"Foo"}'] which can done by removing json_encode() while sending data to Flask Application. In my case was from Laravel / PHP.

2. By accessing element using a[0]['id'] as pointed by @mhhabib

How to fix TypeError: list indices must be integers or slices, not str. ?

There are two main issues:

• You are not iterating the ResultSet of urls, you push table as list of urls to your function.

• Your urls become invalid, while prepending baseUrl, just try to use jobUrl = link['href'] cause path is absolute.

Note You also should check if the elements you are looking for exists in the responses

Example

Iterates over the first two urls - Third will give you an error, cause there is no <h3> in response, but this should be asked in new question with exact this focus:

def jobScan(link):
     
    the_job = {}

    jobUrl = link['href']
    print(jobUrl)
    the_job['urlLink'] = jobUrl

    job = requests.get(jobUrl, headers = headers )
    jobC = job.content
    jobSoup = BeautifulSoup(jobC, "lxml")

    name = jobSoup.find("h3", attrs={"class": "loop-item-title"})
    title = name.a.text
    the_job['title'] = title

    company = jobSoup.find_all("span", {"class": "job-company"})[0]
    company = company.text
    the_job['company'] = company

    return the_job

data = []

for a in table[:2]:
    data.append(jobScan(a))

data

Output

[{'urlLink': 'https://elitejobstoday.com/jobs/office-assistant-ngo-careers-at-world-vision-uganda/',
  'title': 'Project Accountant – Lego Foundation Playful Parenting Project (NGO Careers) at World Vision Uganda',
  'company': ' World Vision Uganda\n'},
 {'urlLink': 'https://elitejobstoday.com/jobs/survey-enumerators-41-positions-ngo-careers-at-catholic-relief-services-2022/',
  'title': 'Project Accountant – Lego Foundation Playful Parenting Project (NGO Careers) at World Vision Uganda',
  'company': ' Catholic Relief Services (CRS)\n'}]

Finding a needle in a haystack *TypeError: list indices must be integers or slices, not str*

There are different numbers involved here - you have the value/element (i.e. the thing you're adding to the array) and the index; the element's position within that array. When comparing your needle value with your haystack value you want to compare the values (which you're doing); but to get those values you want to look in the array in the relevant position (which you're not).

Instead, try something like this:

needle = [] 
for x in range(2015,2017):
    needle.append(str(x))

hay = [] 
for x in range(2015,2022):
    hay.append(str(x))

print(needle)
print(hay)

for needleIndex in range(len(needle)):
    for hayIndex in range(len(hay)):
        if needle[needleIndex] == hay[hayIndex]:
            print("Found!")
        else:        
            print("Not found!")

This change means that instead of a being '2015', '2016', '2017' instead needleIndex is 0,1,2 and needle[needleIndex] is '2015', '2016', '2017'.

Hope that helps to clarify what's going on.

ps. For this example you don't need the indexes; you could just have

for a in needle:
    for b in hay:
        if b == a:
            print("Found!")
        else:        
            print("Not found!")

Simpler still; you've shown that you're aware of the in operator; though you've been comparing individual values from the 2 arrays (hence I changed it to == above)... You can use your in operator like this:

for a in needle:
    if a in hay:
        print("Found!")
    else:        
        print("Not found!")

You can also use the array_intersect function to check for all elements which exist in both arrays... More on that here: https://stackoverflow.com/a/8679430/361842

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