Rreplace - How to Replace the Last Occurrence of an Expression in a String

rreplace - How to replace the last occurrence of an expression in a string?

>>> def rreplace(s, old, new, occurrence):
...  li = s.rsplit(old, occurrence)
...  return new.join(li)
... 
>>> s
'1232425'
>>> rreplace(s, '2', ' ', 2)
'123 4 5'
>>> rreplace(s, '2', ' ', 3)
'1 3 4 5'
>>> rreplace(s, '2', ' ', 4)
'1 3 4 5'
>>> rreplace(s, '2', ' ', 0)
'1232425'

Replace last occurrence of character in string

You don't need jQuery, just a regular expression.

This will remove the last underscore:

var str = 'a_b_c';console.log(  str.replace(/_([^_]*)$/, '$1')  ) //a_bc

Finding last occurrence of substring in string, replacing that

This should do it

old_string = "this is going to have a full stop. some written sstuff!"
k = old_string.rfind(".")
new_string = old_string[:k] + ". - " + old_string[k+1:]

Replace the last occurrence of a string in another string

Find the index of the last occurrence of the substring.

String myWord = "AAAAAasdas";
String toReplace = "AA";
String replacement = "BBB";

int start = myWord.lastIndexOf(toReplace);

Create a StringBuilder (you can just concatenate Strings if you wanted to).

StringBuilder builder = new StringBuilder();

Append the part before the last occurrence.

builder.append(myWord.substring(0, start));

Append the String you want to use as a replacement.

builder.append(replacement);

Append the part after the last occurrence from the original `String.

builder.append(myWord.substring(start + toReplace.length()));

And you're done.

System.out.println(builder);

To replace but the last occurrence of string in a text

str.replace() method has a count argument:

str.replace(old, new[, count])

Return a copy of the string with all occurrences of substring old replaced by new. If the optional argument count is given, only the first count occurrences are replaced.

Then, use str.count() to check how many and in the string and then -1 (because you need the last and):

str.count(sub[, start[, end]])

Return the number of non-overlapping occurrences of substring sub in the range [start, end]. Optional arguments start and end are interpreted as in slice notation.

Demo:

>>> string = 'Saturday and Sunday and Monday and Tuesday and Wednesday and Thursday and Friday are days of the week.'   
>>> string.replace(' and ', ", ", (string.count(' and ')-1))
'Saturday, Sunday, Monday, Tuesday, Wednesday, Thursday and Friday are days of the week.  '

How to replace the last occurrence of a part of a search string in Python

You can use a group () and a backreference \1.

>>> mystring = "a, b, c, d"
>>> print(re.sub(r", (\w)$", r" & \1", mystring))
a, b, c & d

Reference

Replace last occurrence of a string in a string

You can use this function:

function str_lreplace($search, $replace, $subject)
{
    $pos = strrpos($subject, $search);

    if($pos !== false)
    {
        $subject = substr_replace($subject, $replace, $pos, strlen($search));
    }

    return $subject;
}

Replace the last occurrence of a word in a string - C#

Here is the function to replace the last occurrence of a string

public static string ReplaceLastOccurrence(string Source, string Find, string Replace)
{
    int place = Source.LastIndexOf(Find);
    
    if(place == -1)
       return Source;
    
    return Source.Remove(place, Find.Length).Insert(place, Replace);
}

• Source is the string on which you want to do the operation.
• Find is the string that you want to replace.
• Replace is the string that you want to replace it with.

JavaScript: replace last occurrence of text in a string

Well, if the string really ends with the pattern, you could do this:

str = str.replace(new RegExp(list[i] + '$'), 'finish');

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