jsonify a SQLAlchemy result set in Flask
It seems that you actually haven't executed your query. Try following:
return jsonify(json_list = qryresult.all())
[Edit]: Problem with jsonify is, that usually the objects cannot be jsonified automatically. Even Python's datetime fails ;)
What I have done in the past, is adding an extra property (like serialize
) to classes that need to be serialized.
def dump_datetime(value):
"""Deserialize datetime object into string form for JSON processing."""
if value is None:
return None
return [value.strftime("%Y-%m-%d"), value.strftime("%H:%M:%S")]
class Foo(db.Model):
# ... SQLAlchemy defs here..
def __init__(self, ...):
# self.foo = ...
pass
@property
def serialize(self):
"""Return object data in easily serializable format"""
return {
'id' : self.id,
'modified_at': dump_datetime(self.modified_at),
# This is an example how to deal with Many2Many relations
'many2many' : self.serialize_many2many
}
@property
def serialize_many2many(self):
"""
Return object's relations in easily serializable format.
NB! Calls many2many's serialize property.
"""
return [ item.serialize for item in self.many2many]
And now for views I can just do:
return jsonify(json_list=[i.serialize for i in qryresult.all()])
Hope this helps ;)
[Edit 2019]:
In case you have more complex objects or circular references, use a library like marshmallow).
How to serialize SqlAlchemy result to JSON?
A flat implementation
You could use something like this:
from sqlalchemy.ext.declarative import DeclarativeMeta
class AlchemyEncoder(json.JSONEncoder):
def default(self, obj):
if isinstance(obj.__class__, DeclarativeMeta):
# an SQLAlchemy class
fields = {}
for field in [x for x in dir(obj) if not x.startswith('_') and x != 'metadata']:
data = obj.__getattribute__(field)
try:
json.dumps(data) # this will fail on non-encodable values, like other classes
fields[field] = data
except TypeError:
fields[field] = None
# a json-encodable dict
return fields
return json.JSONEncoder.default(self, obj)
and then convert to JSON using:
c = YourAlchemyClass()
print json.dumps(c, cls=AlchemyEncoder)
It will ignore fields that are not encodable (set them to 'None').
It doesn't auto-expand relations (since this could lead to self-references, and loop forever).
A recursive, non-circular implementation
If, however, you'd rather loop forever, you could use:
from sqlalchemy.ext.declarative import DeclarativeMeta
def new_alchemy_encoder():
_visited_objs = []
class AlchemyEncoder(json.JSONEncoder):
def default(self, obj):
if isinstance(obj.__class__, DeclarativeMeta):
# don't re-visit self
if obj in _visited_objs:
return None
_visited_objs.append(obj)
# an SQLAlchemy class
fields = {}
for field in [x for x in dir(obj) if not x.startswith('_') and x != 'metadata']:
fields[field] = obj.__getattribute__(field)
# a json-encodable dict
return fields
return json.JSONEncoder.default(self, obj)
return AlchemyEncoder
And then encode objects using:
print json.dumps(e, cls=new_alchemy_encoder(), check_circular=False)
This would encode all children, and all their children, and all their children... Potentially encode your entire database, basically. When it reaches something its encoded before, it will encode it as 'None'.
A recursive, possibly-circular, selective implementation
Another alternative, probably better, is to be able to specify the fields you want to expand:
def new_alchemy_encoder(revisit_self = False, fields_to_expand = []):
_visited_objs = []
class AlchemyEncoder(json.JSONEncoder):
def default(self, obj):
if isinstance(obj.__class__, DeclarativeMeta):
# don't re-visit self
if revisit_self:
if obj in _visited_objs:
return None
_visited_objs.append(obj)
# go through each field in this SQLalchemy class
fields = {}
for field in [x for x in dir(obj) if not x.startswith('_') and x != 'metadata']:
val = obj.__getattribute__(field)
# is this field another SQLalchemy object, or a list of SQLalchemy objects?
if isinstance(val.__class__, DeclarativeMeta) or (isinstance(val, list) and len(val) > 0 and isinstance(val[0].__class__, DeclarativeMeta)):
# unless we're expanding this field, stop here
if field not in fields_to_expand:
# not expanding this field: set it to None and continue
fields[field] = None
continue
fields[field] = val
# a json-encodable dict
return fields
return json.JSONEncoder.default(self, obj)
return AlchemyEncoder
You can now call it with:
print json.dumps(e, cls=new_alchemy_encoder(False, ['parents']), check_circular=False)
To only expand SQLAlchemy fields called 'parents', for example.
How to serialize SqlAlchemy result to JSON?
A flat implementation
You could use something like this:
from sqlalchemy.ext.declarative import DeclarativeMeta
class AlchemyEncoder(json.JSONEncoder):
def default(self, obj):
if isinstance(obj.__class__, DeclarativeMeta):
# an SQLAlchemy class
fields = {}
for field in [x for x in dir(obj) if not x.startswith('_') and x != 'metadata']:
data = obj.__getattribute__(field)
try:
json.dumps(data) # this will fail on non-encodable values, like other classes
fields[field] = data
except TypeError:
fields[field] = None
# a json-encodable dict
return fields
return json.JSONEncoder.default(self, obj)
and then convert to JSON using:
c = YourAlchemyClass()
print json.dumps(c, cls=AlchemyEncoder)
It will ignore fields that are not encodable (set them to 'None').
It doesn't auto-expand relations (since this could lead to self-references, and loop forever).
A recursive, non-circular implementation
If, however, you'd rather loop forever, you could use:
from sqlalchemy.ext.declarative import DeclarativeMeta
def new_alchemy_encoder():
_visited_objs = []
class AlchemyEncoder(json.JSONEncoder):
def default(self, obj):
if isinstance(obj.__class__, DeclarativeMeta):
# don't re-visit self
if obj in _visited_objs:
return None
_visited_objs.append(obj)
# an SQLAlchemy class
fields = {}
for field in [x for x in dir(obj) if not x.startswith('_') and x != 'metadata']:
fields[field] = obj.__getattribute__(field)
# a json-encodable dict
return fields
return json.JSONEncoder.default(self, obj)
return AlchemyEncoder
And then encode objects using:
print json.dumps(e, cls=new_alchemy_encoder(), check_circular=False)
This would encode all children, and all their children, and all their children... Potentially encode your entire database, basically. When it reaches something its encoded before, it will encode it as 'None'.
A recursive, possibly-circular, selective implementation
Another alternative, probably better, is to be able to specify the fields you want to expand:
def new_alchemy_encoder(revisit_self = False, fields_to_expand = []):
_visited_objs = []
class AlchemyEncoder(json.JSONEncoder):
def default(self, obj):
if isinstance(obj.__class__, DeclarativeMeta):
# don't re-visit self
if revisit_self:
if obj in _visited_objs:
return None
_visited_objs.append(obj)
# go through each field in this SQLalchemy class
fields = {}
for field in [x for x in dir(obj) if not x.startswith('_') and x != 'metadata']:
val = obj.__getattribute__(field)
# is this field another SQLalchemy object, or a list of SQLalchemy objects?
if isinstance(val.__class__, DeclarativeMeta) or (isinstance(val, list) and len(val) > 0 and isinstance(val[0].__class__, DeclarativeMeta)):
# unless we're expanding this field, stop here
if field not in fields_to_expand:
# not expanding this field: set it to None and continue
fields[field] = None
continue
fields[field] = val
# a json-encodable dict
return fields
return json.JSONEncoder.default(self, obj)
return AlchemyEncoder
You can now call it with:
print json.dumps(e, cls=new_alchemy_encoder(False, ['parents']), check_circular=False)
To only expand SQLAlchemy fields called 'parents', for example.
How to create sqlalchemy to json
It looks like your LabelsData
object is a SQLAlchemy model. You need to serialize it before dumping it to JSON. Here's a short example that extracts all the columns from your LabelsData
object and converts the results of your query to JSON:
from json import dumps
from sqlalchemy.orm import class_mapper
def serialize(model):
"""Transforms a model into a dictionary which can be dumped to JSON."""
# first we get the names of all the columns on your model
columns = [c.key for c in class_mapper(model.__class__).columns]
# then we return their values in a dict
return dict((c, getattr(model, c)) for c in columns)
# we can then use this for your particular example
serialized_labels = [
serialize(label)
for label in session.query(LabelsData).filter(LabelsData.deleted == False)
]
your_json = dumps(serialized_labels)
jsonify a SQLAlchemy result set in Flask
It seems that you actually haven't executed your query. Try following:
return jsonify(json_list = qryresult.all())
[Edit]: Problem with jsonify is, that usually the objects cannot be jsonified automatically. Even Python's datetime fails ;)
What I have done in the past, is adding an extra property (like serialize
) to classes that need to be serialized.
def dump_datetime(value):
"""Deserialize datetime object into string form for JSON processing."""
if value is None:
return None
return [value.strftime("%Y-%m-%d"), value.strftime("%H:%M:%S")]
class Foo(db.Model):
# ... SQLAlchemy defs here..
def __init__(self, ...):
# self.foo = ...
pass
@property
def serialize(self):
"""Return object data in easily serializable format"""
return {
'id' : self.id,
'modified_at': dump_datetime(self.modified_at),
# This is an example how to deal with Many2Many relations
'many2many' : self.serialize_many2many
}
@property
def serialize_many2many(self):
"""
Return object's relations in easily serializable format.
NB! Calls many2many's serialize property.
"""
return [ item.serialize for item in self.many2many]
And now for views I can just do:
return jsonify(json_list=[i.serialize for i in qryresult.all()])
Hope this helps ;)
[Edit 2019]:
In case you have more complex objects or circular references, use a library like marshmallow).
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