How to Remove the Left Part of a String

How to remove the left part of a string?

Starting in Python 3.9, you can use removeprefix:

'Path=helloworld'.removeprefix('Path=')
# 'helloworld'

Removing characters from the left side of a Python string?

You can do different things:

string.split(' ')[1]

or

string[11:]

or

string[-14:]

both yielding

'MA:CA:DD:RE:SS'

The last option is the closest to what you want I suppose. It takes the leftmost 14 characters from the string.

How do I remove a substring from the end of a string?

strip doesn't mean "remove this substring". x.strip(y) treats y as a set of characters and strips any characters in that set from both ends of x.

On Python 3.9 and newer you can use the removeprefix and removesuffix methods to remove an entire substring from either side of the string:

url = 'abcdc.com'
url.removesuffix('.com')    # Returns 'abcdc'
url.removeprefix('abcdc.')  # Returns 'com'

The relevant Python Enhancement Proposal is PEP-616.

On Python 3.8 and older you can use endswith and slicing:

url = 'abcdc.com'
if url.endswith('.com'):
    url = url[:-4]

Or a regular expression:

import re
url = 'abcdc.com'
url = re.sub('\.com$', '', url)

How to remove part of a string?

My favourite way of doing this is "splitting and popping":

var str = "test_23";
alert(str.split("_").pop());
// -> 23

var str2 = "adifferenttest_153";
alert(str2.split("_").pop());
// -> 153

split() splits a string into an array of strings using a specified separator string.

pop() removes the last element from an array and returns that element.

How can I remove a substring from a given String?

You could easily use String.replace():

String helloWorld = "Hello World!";
String hellWrld = helloWorld.replace("o","");

Remove a prefix from a string

I don't know about "standard way".

def remove_prefix(text, prefix):
    if text.startswith(prefix):
        return text[len(prefix):]
    return text  # or whatever

As noted by @Boris and @Stefan, on Python 3.9+ you can use

text.removeprefix(prefix)

with the same behavior.

Remove part of string in Java

There are multiple ways to do it. If you have the string which you want to replace you can use the replace or replaceAll methods of the String class. If you are looking to replace a substring you can get the substring using the substring API.

For example

String str = "manchester united (with nice players)";
System.out.println(str.replace("(with nice players)", ""));
int index = str.indexOf("(");
System.out.println(str.substring(0, index));

To replace content within "()" you can use:

int startIndex = str.indexOf("(");
int endIndex = str.indexOf(")");
String replacement = "I AM JUST A REPLACEMENT";
String toBeReplaced = str.substring(startIndex + 1, endIndex);
System.out.println(str.replace(toBeReplaced, replacement));

How to remove a defined part of a string?

you can use this code:

str = str.Substring (10); // to remove the first 10 characters.
str = str.Remove (0, 10); // to remove the first 10 characters
str = str.Replace ("NT-DOM-NV\\", ""); // to replace the specific text with blank

//  to delete anything before \

int i = str.IndexOf('\\');
if (i >= 0) str = str.SubString(i+1);

I want to remove part of string from a string

Assuming there is only one dot

UPDATE TABLE 
SET column_name = left(column_name, charindex('.', column_name) - 1)

For SELECT

select left(column_name, charindex('.', column_name) - 1) AS col
from your_table

Remove part of a string

Use regular expressions. In this case, you can use gsub:

gsub("^.*?_","_","ATGAS_1121")
[1] "_1121"

This regular expression matches the beginning of the string (^), any character (.) repeated zero or more times (*), and underscore (_). The ? makes the match "lazy" so that it only matches are far as the first underscore. That match is replaced with just an underscore. See ?regex for more details and references

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