How to Lowercase a String in Python

How do I lowercase a string in Python?

Use str.lower():

"Kilometer".lower()

Python Lowercase and Uppercase String

a = 'Kilometers'

print(''.join([char.upper() if i%2==0 else char.lower() for i, char in enumerate(a)]))

result = 'KiLoMeTeRs'

How do I lowercase a string and also change space into underscore in python?

Use lower and replace on whitespace

df['type'] = df['type'].str.replace(' ','_').str.lower()

input:

df = pd.DataFrame({'type':['Ground Improvement']})
df

looks like this

    type
0   Ground Improvement

output

    type
0   ground_improvement

How to make everything in a string lowercase

As per official documentation,

str.lower()

Return a copy of the string with all the cased characters [4] converted to lowercase.

So you could use it at several different places, e.g.

lines.append(line.lower())

reversed_line = remove_punctuation(line).strip().split(" ").lower()

or

print(len(lines) - i, " ".join(reversed_line).lower())

(this would not store the result, but only print it, so it is likely not what you want).

Note that, depending on the language of the source, you may need a little caution, e.g., this.
See also other relevant answers for How to convert string to lowercase in Python

Python: How do you make a list start with the lowercase strings?

You can pass a custom key function to sort with.

words.sort(key=lambda s: (s[0].isupper(), s))

How do I make part of a string lowercase in python?

All your current code does is rebind the word variable, so that instead of 'fOx' it now holds 'fox'. That has no effect on the original string variable.

You could print out each word as you get it:

for word in string.split(' '):
    # your existing code
    print(word, end=' ')

Or, maybe better, you could accumulate all of the words into a list, join them back into a string, and print that:

words = []
for word in string.split(' '):
    # your existing code
    words.append(word)
print(' '.join(words))

Check if all letter is uppercase or lowercase python, if there is one word in string is different print none

No need for loops here. Just simply use the functions isupper() and islower() in an if-elif block, and add an else block to take care of mixed case (i.e., print out None or NONE), like so:

test_str = input()
    
if test_str.isupper():
    print('UPPER')
elif test_str.islower():
    print('LOWER')
else:
    print(None) # or print('NONE')

Example input/output:

HELLO USER
UPPER

HELLO UsER    
None 

hello user  
LOWER

hello User
None 

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Active reading: GeeksForGeeks

Convert All String Values to Lower/Uppercase in Python

You can use the builtin function lower:

start = input("Hello there! Press 'y' to start, or 'n' to stop. ").lower()
if start in ['y', 'yes']:
    main()
elif start in ['n', 'no']:
    print("Hope you can play some other time!")

And if you want without the list at all, you can check only the first letter:

start = input("Hello there! Press 'y' to start, or 'n' to stop. ").lower()
if start[0] == 'y':
    main()
elif start[0] == 'n':
    print("Hope you can play some other time!")

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