Breaking Out of Nested Loops

How to break out of nested loops?

Use:

if (condition) {
    i = j = 1000;
    break;
}

How do I break out of nested loops in Java?

Like other answerers, I'd definitely prefer to put the loops in a different method, at which point you can just return to stop iterating completely. This answer just shows how the requirements in the question can be met.

You can use break with a label for the outer loop. For example:

public class Test {
    public static void main(String[] args) {
        outerloop:
        for (int i=0; i < 5; i++) {
            for (int j=0; j < 5; j++) {
                if (i * j > 6) {
                    System.out.println("Breaking");
                    break outerloop;
                }
                System.out.println(i + " " + j);
            }
        }
        System.out.println("Done");
    }
}

This prints:

How can I break out of multiple loops?

My first instinct would be to refactor the nested loop into a function and use return to break out.

Breaking out of nested loops

It has at least been suggested, but also rejected. I don't think there is another way, short of repeating the test or re-organizing the code. It is sometimes a bit annoying.

In the rejection message, Mr van Rossum mentions using return, which is really sensible and something I need to remember personally. :)

What's the best way to break from nested loops in JavaScript?

Just like Perl,

loop1:
    for (var i in set1) {
loop2:
        for (var j in set2) {
loop3:
            for (var k in set3) {
                break loop2;  // breaks out of loop3 and loop2
            }
        }
    }

as defined in EMCA-262 section 12.12. [MDN Docs]

Unlike C, these labels can only be used for continue and break, as Javascript does not have goto.

Python-Break out of nested loops

I found the answer to be, to just include the code that I want to execute afterwards, in the else statment.
As shown here:

for i in range(10):
    for j in range(10):
        print(i*j)
        if testfunction(i,j):
            break
    else:
        executecode(i,j) # only gets executed if testfunction was never true

Breaking out of a nested loop

Well, goto, but that is ugly, and not always possible. You can also place the loops into a method (or an anon-method) and use return to exit back to the main code.

    // goto
    for (int i = 0; i < 100; i++)
    {
        for (int j = 0; j < 100; j++)
        {
            goto Foo; // yeuck!
        }
    }
Foo:
    Console.WriteLine("Hi");

vs:

// anon-method
Action work = delegate
{
    for (int x = 0; x < 100; x++)
    {
        for (int y = 0; y < 100; y++)
        {
            return; // exits anon-method
        }
    }
};
work(); // execute anon-method
Console.WriteLine("Hi");

Note that in C# 7 we should get "local functions", which (syntax tbd etc) means it should work something like:

// local function (declared **inside** another method)
void Work()
{
    for (int x = 0; x < 100; x++)
    {
        for (int y = 0; y < 100; y++)
        {
            return; // exits local function
        }
    }
};
Work(); // execute local function
Console.WriteLine("Hi");

How to break out of nested loops in Go?

use function

package main

import (
    "fmt"
)

func getWord() string {
    word := ""
    for word != "DC" {
        for _, i := range "ABCDE" {
            for _, j := range "ABCDE" {
                word = string(i) + string(j)
                fmt.Println(word)
                if word == "DC" {
                    return word
                }
            }
        }
    }
    return word
}

func main(){
    word := getWord()
}

Edit: thanks to @peterSO who points on some mistakes in the details and provides this playground https://play.golang.org/p/udcJptBW9pQ