How to Find Files and Skip Directories in Os.Listdir

How to find files and skip directories in os.listdir

You need to filter out directories; os.listdir() lists all names in a given path. You can use os.path.isdir() for this:

basepath = '/path/to/directory'
for fname in os.listdir(basepath):
    path = os.path.join(basepath, fname)
    if os.path.isdir(path):
        # skip directories
        continue

Note that this only filters out directories after following symlinks. fname is not necessarily a regular file, it could also be a symlink to a file. If you need to filter out symlinks as well, you'd need to use not os.path.islink() first.

On a modern Python version (3.5 or newer), an even better option is to use the os.scandir() function; this produces DirEntry() instances. In the common case, this is faster as the direntry loaded already has cached enough information to determine if an entry is a directory or not:

basepath = '/path/to/directory'
for entry in os.scandir(basepath):
    if entry.is_dir():
        # skip directories
        continue
    # use entry.path to get the full path of this entry, or use
    # entry.name for the base filename

You can use entry.is_file(follow_symlinks=False) if only regular files (and not symlinks) are needed.

os.walk() does the same work under the hood; unless you need to recurse down subdirectories, you don't need to use os.walk() here.

How would I exclude directories from os.listdir results?

You can use os.path.isdir function to check if the current file is a directory.

Also, it is much better to use string formatting operations instead of string concatenation: not

print("File " + str(fileprogress) + "/" + str(filecount))

but

print("File {}/{}".format(fileprogress, filecount))

Such code is much easier to understand and modify.

Ignore some folders in os.listdir(path) Python

ignored = {"folder_one", "folder_two", "folder_three"}
folders = [x for x in os.listdir(path) if x not in ignored]

list only files of a directory and ignore the subdirectories with python

files=[i for i in os.listdir() if os.path.isfile(i)]

Edit:

for list all files in specific direcotry

import os
from os import listdir
from os.path import isfile, join

input_folder = 'headfolder/'
list_files = []

files = [f for f in listdir(input_folder) if isfile(join(input_folder, f))]
for filename in files:
    joined = os.path.join(input_folder, filename)
    list_files.append(joined)

print(list_files)

How to skip first few files when looping using os.listdir(path)?

os.listdir doesn't guarantee order, so you should sort first to make sure, then you can just slice:

for file in sorted(os.listdir(local_path))[5:]:
    # rest of the code goes here

How to scan only some directories or exclude directories while using os.walk()

After reading @tripleee is comment I have made this piece of code that gets most recently modified files.

import os

os.chdir('Folder')
projloc = os.getcwd() #getting the folder to scan

list_of_dirs_to_exclude = []

def get_recent_files():
    max_mtime = 0
    
    for root, dirs, files in os.walk(projloc):
        if root not in list_of_dirs_to_exclude: # I have made a change by adding the `not` in unlike @tripleee's answer
            for fname in files:
                full_path = os.path.join(root, fname)
                mtime = os.stat(full_path).st_mtime
                if mtime > max_mtime:
                    max_mtime = mtime
                    max_dir = root
                    max_file = fname

    list_of_dirs_to_exclude.insert(0, max_dir)
    print(max_file)

    if len(list_of_dirs_to_exclude) == 5: #You can keep whatever number you want such as 6, 7, 4 etc...
        pass

    else:
        get_recent_files()

get_recent_files()

Here is updated code if you want the code all in the same def

def get_recent_files():
    list_of_dirs_to_exclude = []
    list_of_dirs = []
    max_mtime = 0

    for dirs in os.listdir(projloc): #projloc is predefined for me. I got it using the same method in the above code
        list_of_dirs.insert(0, dirs)

    while len(list_of_dirs) != 5: 
        for root, dirs, files in os.walk(projloc):
            if root not in list_of_dirs_to_exclude:
                for fname in files:
                    full_path = os.path.join(root, fname)
                    mtime = os.stat(full_path).st_mtime
                    if mtime > max_mtime:
                        max_mtime = mtime
                        max_dir = root
                        max_file = fname

        list_of_dirs_to_exclude.insert(0, max_dir)
        print(max_file)
        max_mtime = 0

        if len(list_of_dirs_to_exclude) == 5:
            break

How to ignore hidden files using os.listdir()?

You can write one yourself:

import os

def listdir_nohidden(path):
    for f in os.listdir(path):
        if not f.startswith('.'):
            yield f

Or you can use a glob:

import glob
import os

def listdir_nohidden(path):
    return glob.glob(os.path.join(path, '*'))

Either of these will ignore all filenames beginning with '.'.

How to skip the inaccessible folders with python's os.listdir?

for el in os.listdir('C:\Users\MyUser'):
    try:
        (check if you can open, if so, you can show this folder)
    except WindowsError:
        pass  

python - ignore directory in os.listdir()

You could filter the list before going through it.

runbooksrc_files = [i for i in os.listdir(runbooksrc) if not os.path.isdir(i)]

Find all files in a directory with extension .txt in Python

You can use glob:

import glob, os
os.chdir("/mydir")
for file in glob.glob("*.txt"):
    print(file)

or simply os.listdir:

import os
for file in os.listdir("/mydir"):
    if file.endswith(".txt"):
        print(os.path.join("/mydir", file))

or if you want to traverse directory, use os.walk:

import os
for root, dirs, files in os.walk("/mydir"):
    for file in files:
        if file.endswith(".txt"):
             print(os.path.join(root, file))

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