How to extract the substring between two markers?
Using regular expressions - documentation for further reference
import re
text = 'gfgfdAAA1234ZZZuijjk'
m = re.search('AAA(.+?)ZZZ', text)
if m:
found = m.group(1)
# found: 1234
or:
import re
text = 'gfgfdAAA1234ZZZuijjk'
try:
found = re.search('AAA(.+?)ZZZ', text).group(1)
except AttributeError:
# AAA, ZZZ not found in the original string
found = '' # apply your error handling
# found: 1234
Extract all substrings between two markers
What could I do to resolve this?
I would do:
import re
mystr = "&marker1\nThe String that I want /\n&marker1\nAnother string that I want /\n"
found = re.findall(r"\&marker1\n(.*?)/\n", mystr)
print(found)
Output:
['The String that I want ', 'Another string that I want ']
Note that:
&
has special meaning inre
patterns, if you want literal & you need to escape it (\&
).
does match anything except newlinesfindall
is better suited choiced if you just want list of matched substrings, rather thansearch
*?
is non-greedy, in this case.*
would work too, because.
do not match newline, but in other cases you might ending matching more than you wish- I used so-called raw-string (r-prefixed) to make escaping easier
Read module re
documentation for discussion of raw-string usage and implicit list of characters with special meaning.
How to get the substring between two markers in Python multiple times?
you can use regex
import re
s = '''alt="Thunder Force"/>ehkjehkljhiflealt="Godzilla vs. Kong"/>'''
x = re.findall(r'alt="(.*?)"/>', s)
print(x)
output
['Thunder Force', 'Godzilla vs. Kong']
Extract all substrings between two markers for a very long string
I couldn't get re.findall
to work. Now I do use re
but to find the location of markers and extract the substrings manually.
locs_start = [match.start() for match in re.finditer("\&marker1", mylongstring)]
locs_end = [match.start() for match in re.finditer("/\n", mylongstring)]
substrings = []
for i in range(0, len(locs_start)):
substrings.append(mylongstring[locs_start[i]:locs_end[i]+1])
Find string between two substrings
import re
s = 'asdf=5;iwantthis123jasd'
result = re.search('asdf=5;(.*)123jasd', s)
print(result.group(1))
How to capture multiple substrings between two markers using regular expressions?
You need a regex method that will find all the matches in a string. You should try re.findall('\$\{(.+?)\}', text)
or re.finditer('\$\{(.+?)\}', text)
. The first will return a list, the second will return an iterable.
extract text between two markers in a pandas column
You can use
df[0].str.extract(r'\((\w+),', expand=False)
See the regex demo.
The regex matches one or more letters/digits/underscores between a (
and ,
chars. Since Series.str.extract
requires a capturing group in a regex pattern, there \w+
is enclosed with two unescape capturing parentheses.
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