pandas rolling get most frequent value in window
Use rolling().apply
with mode method:
df.rolling(window = 3).apply(lambda x: x.mode()[0])
x
will be a pd.Series
object of length equal to window. mode
method will return a list of most frequent values. lambda
will return the first item from the list of modes.
How to find the frequency of the most frequent value (mode) of a series in polars?
There is a value_counts
expression. This expression will return a Struct
datatype where the first field is the unique value and the second field is the count of that value.
df.select([
pl.col("tags").value_counts()
])
shape: (4, 1)
┌───────────┐
│ tags │
│ --- │
│ struct[2] │
╞═══════════╡
│ {"c",4} │
├╌╌╌╌╌╌╌╌╌╌╌┤
│ {"a",3} │
├╌╌╌╌╌╌╌╌╌╌╌┤
│ {"b",1} │
├╌╌╌╌╌╌╌╌╌╌╌┤
│ {"d",1} │
└───────────┘
Or if you want to have that result as a DataFrame
:
(df.select([
pl.col("tags").value_counts()
]).to_series().struct.to_frame())
shape: (4, 2)
┌──────┬────────┐
│ tags ┆ counts │
│ --- ┆ --- │
│ str ┆ u32 │
╞══════╪════════╡
│ c ┆ 4 │
├╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌┤
│ a ┆ 3 │
├╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌┤
│ d ┆ 1 │
├╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌┤
│ b ┆ 1 │
└──────┴────────┘
Edited:
Which can be even simpler:
df["tags"].value_counts()
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