Get Character Position in Alphabet

Get character position in alphabet

It is called index. For e.g.

>>> import string
>>> string.lowercase.index('b')
1
>>>

Note: in Python 3, string.lowercase has been renamed to string.ascii_lowercase.

how to take a number and find its alphabet position python

Use the chr() and ord() functions.

print(ord('a'))  # 97
print(chr(97 + 4))  # e
print(chr(ord('f') + 2))  # h

How to get character position in alphabet in Python 3.4?

import string
message='bonjour'

print(string.ascii_lowercase.index(message[2]))

o/p

This will work for you, Remove the ' in change index.

When you give '' then it will be considered as a string.

How to get character's position in alphabet in C language?

int position = 'g' - 'a' + 1;

In C, char values are convertible to int values and take on their ASCII values. In this case, 'a' is the same as 97 and 'g' is 103. Since the alphabet is contiguous within the ASCII character set, subtracting 'a' from your value gives its relative position. Add 1 if you consider 'a' to be the first (instead of zeroth) position.

Replace a letter with its alphabet position

The Kata works with this code. Try with this one:

function alphabetPosition(text) {  var result = "";  for (var i = 0; i < text.length; i++) {    var code = text.toUpperCase().charCodeAt(i)    if (code > 64 && code < 91) result += (code - 64) + " ";  }
  return result.slice(0, result.length - 1);}console.log(alphabetPosition("The sunset sets at twelve o' clock."));

Alphabet position in python

Following your logic you need to create a new_text string and then iteratively replace its letters. With your code, you are only replacing one letter at a time, then start from scratch with your original string:

def alphabet_position(text):

    dict = {'a':'1','b':'2','c':'3','d':'4','e':'5','f':'6','g':'7','h':'8','i':'9','j':'10','k':'11','l':'12','m':'13','n':'14','o':'15','p':'16','q':'17','r':'18','s':'19','t':'20','u':'21','v':'22','w':'23','x':'24','y':'25','z':'26'}
    new_text = text.lower()
    for i in new_text:
        if i in dict:
            new_text = new_text.replace(i, dict[i])
    print (new_text)

And as suggested by Kevin, you can optimize a bit using set. (adding his comment here since he deleted it: for i in set(new_text):) Note that this might be beneficial only for large inputs though...

Converting alphabet letter to alphabet position in PHP

By using the ascii value:

ord(strtoupper($letterOfAlphabet)) - ord('A') + 1

in ASCII the letters are sorted by alphabetic order, so...

Get Character Position in Alphabet