Why Can't I Access Datetime-≫Date in PHP'S Datetime Class

Why can't I access DateTime-date in PHP's DateTime class?

This is a known issue.

Date being available is actually a side-effect of support for var_dump() here – derick@php.net

For some reason, you're not supposed to be able to access the property but var_dump shows it anyways. If you really want to get the date in that format, use the DateTime::format() function.

echo $mydate->format('Y-m-d H:i:s');

How to get current time in Datetime format PHP?

You should find info about the DateTime class to work with dates in php

$d = new DateTime('now');
$d->setTimezone(new DateTimeZone('UTC'));
echo $d->format('Y-m-d H:i:s');

Object of class DateTime could not be converted

You can't echo the DateTime object directly. You have to use the format method to get the date and / or time part:

$tempDate = DateTime::createFromFormat('j-M-Y', '15-Feb-2009');
echo $tempDate->format('Y-m-d H:i:s');
// NOT echo $tempDate!!!

demo: http://ideone.com/IyqRWj

If you want to see the details of the object (for debug) you can use var_dump:

$tempDate = DateTime::createFromFormat('j-M-Y', '15-Feb-2009');
var_dump($tempDate);

DateTime object returning NULL without var_dump

It has something to do with PHP being forced to create a full object representation when you dump the whole object which happens to update the object state, as opposed to you just accessing the one individual property.

The bigger point is though that you don't really have any business accessing DateTime::$date at all. It's an undocumented internal implementation detail that you're not supposed to use anywhere. If you want to output the date, use DateTime::format or one of the other public interface methods.

Verify valid date using PHP's DateTime class

You can try this one:

static public function verifyDate($date)
{
    return (DateTime::createFromFormat('m/d/Y', $date) !== false);
}

This outputs true/false. You could return DateTime object directly:

static public function verifyDate($date)
{
    return DateTime::createFromFormat('m/d/Y', $date);
}

Then you get back a DateTime object or false on failure.

UPDATE:

Thanks to Elvis Ciotti who showed that createFromFormat accepts invalid dates like 45/45/2014.
More information on that: https://stackoverflow.com/a/10120725/1948627

I've extended the method with a strict check option:

static public function verifyDate($date, $strict = true)
{
    $dateTime = DateTime::createFromFormat('m/d/Y', $date);
    if ($strict) {
        $errors = DateTime::getLastErrors();
        if (!empty($errors['warning_count'])) {
            return false;
        }
    }
    return $dateTime !== false;
}

DateTime function affects original variable when modifying a new variable

$new = $original; just assigns the same reference that's in $original to $new. Instead you want to make a copy.

$new = clone $original;

PHP Issues with DateTime in array from JIRA api

$issue->fields->created is already a DateTime object. To format that as Y-m-d format, you can simply call format() on that directly:

echo '<tr>
    <td>'.$issue->fields->status->name.'</td>
    <td>'.$issue->fields->created->format('Y-m-d').'</td>
    <td>'.$issue->fields->priority->name.'</td>
    <td>'.$issue->fields->summary.'</td>
    <td>'.$issue->fields->assignee->displayName.'</td>
</tr>';

If you want to convert it to a different timezone, you can do that as well:

$issue->fields->created->setTimezone(new DateTimeZone("UTC"))->format('Y-m-d')

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