Replacing Placeholder Variables in a String
I think for such a simple task you don't need to use RegEx:
$variables = array("first_name"=>"John","last_name"=>"Smith","status"=>"won");
$string = 'Dear {FIRST_NAME} {LAST_NAME}, we wanted to tell you that you {STATUS} the competition.';
foreach($variables as $key => $value){
$string = str_replace('{'.strtoupper($key).'}', $value, $string);
}
echo $string; // Dear John Smith, we wanted to tell you that you won the competition.
how to replace a placeholder in a string?
You can use place-holders and str_replace. Or use PHP's built-in sprintf and use %s. (And as of v4.0.6 you can swap the ordering of arguments if you'd like).
$name = 'Alica';
// sprintf method:
$format = 'Hello, %s!';
echo sprintf($format, $name); // Hello, Alica!
// replace method:
$format = "Hello, {NAME}!";
echo str_replace("{NAME}", $name, $format);
And, for anyone wondering, I understood that is trouble templating a string, not PHP's integrated concatenation/parsing. I just assume keep this answer up though as I'm still not 100% sure this OP's intent
Java Is there a feature for replacing placeholders inside a String with a String variable
JDK 7+ has String.format() which I what I think you're looking for
replace placeholders in string
If you receive your string in a variable you should do interpolation by yourself
To do so, you need to find all placeholders and replace they value. You can do this with regular expression (can be simplified if placeholder can start with digits)
{(?<placeholder>[a-z_][a-z0-9_]*?)}
Next method will do this replacement:
public static string Replace(string input, Dictionary<string, object> replacement)
{
var regex = new Regex("{(?<placeholder>[a-z_][a-z0-9_]*?)}",
RegexOptions.Compiled | RegexOptions.IgnoreCase);
return regex.Replace(input, m =>
{
var key = m.Groups["placeholder"].Value;
if (replacement.TryGetValue(key, out var value))
return value.ToString();
throw new Exception($"Unknown key {key}");
});
}
Usage:
var input = "Insert into Emp(Id,Name,Number,Address) values({Id},\"Abc\",{Number},{Address});";
var replaces = new Dictionary<string, object>
{
{"Id", 123},
{ "Number", 55668878},
{"Address", "\"test address\"" },
};
var result = Replace(input, replaces);
Console.WriteLine(result);
Ouput:
Insert into Emp(Id,Name,Number,Address) values(123,"Abc",55668878,"test address");
String interpolation in Typescript, replacing 'placeholders' with variables
Use a template string which are much better than String.Format in my opinion as they do not suffer from poor indexing (wrong placeholder) issues:
var text = "blah blah";
var strTest = `This is a ${text}`;
console.log(strTest);Twig: Replace placeholder in string with include
You have to do it in two steps, first capture the partial in a variable, then use the variable to replace the placeholder, e.g.
{%- set bar -%}
{% include "partial.twig" %}
{%- endset -%}
{% set foo = 'this is {foo}' %}
{% set foo = foo|replace({'{foo}': bar }) %}
{{ foo }}
demo
note: {%- ... -%} is used to strip whitespaces
Replace placeholders in string stored in a text file with variables
Meta-character \b matches a zero-width boundary between a word-class character and a non-word class character.
{ and } are not word-class characters. So your pattern doesn't work.
Remove \b or replace it to \s.
Replace placeholders with dynamic data in strings with php
Use the function strtr
<?php
$string = '[1] edited profile picture of [2]';
$replaceArray = array('[1]' => 'Mark Zuckerberg',
'[2]' => 'John doe');
$string = strtr($sting, $replaceArray);
echo $string;
?>
Gives you
Mark Zuckerberg edited profile picture of John doe
format string in oracle SQL to replace placeholders with variable names given at the end of the string
I am assuming that the last comma is the delimiter between the template string and the delimited terms. You can use a recursive sub-query factoring clause and simple string functions:
WITH terms ( value, terms, num_terms ) AS (
SELECT SUBSTR( value, 1, INSTR( value, ', ', -1 ) - 1 ),
SUBSTR( value, INSTR( value, ', ', -1 ) + 2 ),
REGEXP_COUNT(
SUBSTR( value, INSTR( value, ', ', -1 ) + 2 ),
'.+?(\| |$)'
)
FROM table_name
),
term_bounds ( rn, value, terms, start_pos, lvl ) AS (
SELECT ROWNUM,
REPLACE(
value,
'%' || num_terms,
CASE num_terms
WHEN 1
THEN terms
ELSE SUBSTR( terms, INSTR( terms, '| ', 1, num_terms - 1 ) + 2 )
END
),
terms,
CASE
WHEN num_terms > 1
THEN INSTR( terms, '| ', 1, num_terms - 1 )
ELSE 1
END,
num_terms
FROM terms
UNION ALL
SELECT rn,
REPLACE(
value,
'%' || (lvl - 1),
CASE lvl - 1
WHEN 1
THEN SUBSTR( terms, 1, start_pos - 1 )
ELSE SUBSTR(
terms,
INSTR( terms, '| ', 1, lvl - 2 ) + 2,
start_pos - INSTR( terms, '| ', 1, lvl - 2 ) - 2
)
END
),
terms,
CASE
WHEN lvl > 2
THEN INSTR( terms, '| ', 1, lvl - 2 )
ELSE 1
END,
lvl - 1
FROM term_bounds
WHERE lvl > 1
)
SEARCH DEPTH FIRST BY rn SET rn_order
SELECT value
FROM term_bounds
WHERE lvl = 1;
Which, for the sample data:
CREATE TABLE table_name ( value ) AS
SELECT '%1||'-'||%2||%3, SITE_NO| SITE_NAME| COUNTRY' FROM DUAL UNION ALL
SELECT '0.1 * %1, WIND_RES' FROM DUAL UNION ALL
SELECT '%1, TOTAL' FROM DUAL UNION ALL
SELECT 'CASE WHEN LENGTH(%1) < 8 THEN NULL ELSE TO_DATE(%1,'yyyymmdd')END, MIN_DATE' FROM DUAL UNION ALL
SELECT '%1(+)=%3 and %2(+)=%4, ABC| LMN| PQR| XYZ' FROM DUAL UNION ALL
SELECT '%1, %2, %3, %4, %5, %6, %7, %8, %9, %10, %11, ONE| TWO| THREE| FOUR| FIVE| SIX| SEVEN| EIGHT| NINE| TEN| ELEVEN' FROM DUAL UNION ALL
SELECT '%%%%%%%7, HELLO| 1| 2| 3| 4| 5| 6' FROM DUAL
Outputs:
| VALUE |
| :----------------------------------------------------------------------------------------- |
| SITE_NO||'-'||SITE_NAME||COUNTRY |
| 0.1 * WIND_RES |
| TOTAL |
| CASE WHEN LENGTH(MIN_DATE) < 8 THEN NULL ELSE TO_DATE(MIN_DATE,'yyyymmdd')END |
| ABC(+)=PQR and LMN(+)=XYZ |
| ONE, TWO, THREE, FOUR, FIVE, SIX, SEVEN, EIGHT, NINE, TEN, ELEVEN |
| HELLO |
db<>fiddle here
Or as a PL/SQL function:
CREATE FUNCTION substitute_values(
i_value IN VARCHAR2,
i_terms IN VARCHAR2,
i_term_delimiter IN VARCHAR2 DEFAULT '| '
) RETURN VARCHAR2 DETERMINISTIC
IS
TYPE term_list_type IS TABLE OF VARCHAR2(200);
v_start PLS_INTEGER := 1;
v_end PLS_INTEGER;
v_index PLS_INTEGER;
v_terms term_list_type := term_list_type();
v_output VARCHAR2(4000) := i_value;
BEGIN
LOOP
v_end := INSTR(i_terms, i_term_delimiter, v_start);
v_terms.EXTEND;
IF v_end > 0 THEN
v_terms(v_terms.COUNT) := SUBSTR(i_terms, v_start, v_end - v_start);
ELSE
v_terms(v_terms.COUNT) := SUBSTR(i_terms, v_start);
EXIT;
END IF;
v_start := v_end + LENGTH(i_term_delimiter);
END LOOP;
LOOP
v_index := TO_NUMBER(REGEXP_SUBSTR(v_output, '^(.*?)%(\d+)', 1, 1, NULL, 2));
IF v_index IS NULL THEN
RETURN v_output;
ELSIF v_index > v_terms.COUNT THEN
RETURN NULL;
END IF;
v_output := REGEXP_REPLACE(v_output, '^(.*?)%(\d+)', '\1' || v_terms(v_index));
END LOOP;
END;
/
Then:
SELECT SUBSTITUTE_VALUES(
SUBSTR(value, 1, INSTR(value, ', ', -1) - 1),
SUBSTR(value, INSTR(value, ', ', -1) + 2)
) AS value
FROM table_name
Outputs:
VALUE SITE_NO||'-'||SITE_NAME||COUNTRY 0.1 * WIND_RES TOTAL CASE WHEN LENGTH(MIN_DATE) < 8 THEN NULL ELSE TO_DATE(MIN_DATE,'yyyymmdd')END ABC(+)=PQR and LMN(+)=XYZ ONE, TWO, THREE, FOUR, FIVE, SIX, SEVEN, EIGHT, NINE, TEN, ELEVEN HELLO
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