PHP Date Validation

php date validation

You could use checkdate. For example, something like this:

$test_date = '03/22/2010';
$test_arr  = explode('/', $test_date);
if (checkdate($test_arr[0], $test_arr[1], $test_arr[2])) {
    // valid date ...
}

A more paranoid approach, that doesn't blindly believe the input:

$test_date = '03/22/2010';
$test_arr  = explode('/', $test_date);
if (count($test_arr) == 3) {
    if (checkdate($test_arr[0], $test_arr[1], $test_arr[2])) {
        // valid date ...
    } else {
        // problem with dates ...
    }
} else {
    // problem with input ...
}

Correctly determine if date string is a valid date in that format

You can use DateTime::createFromFormat() for this purpose:

function validateDate($date, $format = 'Y-m-d')
{
    $d = DateTime::createFromFormat($format, $date);
    // The Y ( 4 digits year ) returns TRUE for any integer with any number of digits so changing the comparison from == to === fixes the issue.
    return $d && $d->format($format) === $date;
}

^{[Function taken from this answer. Also on php.net. Originally written by Glavić.]}

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Test cases:

var_dump(validateDate('2013-13-01'));  // false
var_dump(validateDate('20132-13-01')); // false
var_dump(validateDate('2013-11-32'));  // false
var_dump(validateDate('2012-2-25'));   // false
var_dump(validateDate('2013-12-01'));  // true
var_dump(validateDate('1970-12-01'));  // true
var_dump(validateDate('2012-02-29'));  // true
var_dump(validateDate('2012', 'Y'));   // true
var_dump(validateDate('12012', 'Y'));  // false

Demo!

PHP check user input date

You can use a combination of strtotime() and checkdate() to see if the date is valid:

function isRealDate($date) { 
    if (false === strtotime($date)) { 
        return false;
    } 
    list($year, $month, $day) = explode('-', $date); 
    return checkdate($month, $day, $year);
}

usage

if (isRealDate($geboortedatum)) {
    // date is ok
}
else {
    // date is not ok
}

PHP Regex to check date is in YYYY-MM-DD format

Try this.

$date="2012-09-12";

if (preg_match("/^[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1])$/",$date)) {
    return true;
} else {
    return false;
}

Date validation from form input with PHP

Try this. I recommend you to use DateTime() object instead of time() function.

$checkinDate = new DateTime('2021-05-14 09:52:52'); //use your actual POST value here

if ($checkinDate){
    $today = new DateTime();
    $diff = $checkinDate->diff($today);
    $days= $diff->format('%a');

    if($days>14){
        echo "2 Weeks done. Please enter a new date";
    }
    else{
        echo "Not done 2 weeks yet.";
    }
}

Verify valid date using PHP's DateTime class

You can try this one:

static public function verifyDate($date)
{
    return (DateTime::createFromFormat('m/d/Y', $date) !== false);
}

This outputs true/false. You could return DateTime object directly:

static public function verifyDate($date)
{
    return DateTime::createFromFormat('m/d/Y', $date);
}

Then you get back a DateTime object or false on failure.

UPDATE:

Thanks to Elvis Ciotti who showed that createFromFormat accepts invalid dates like 45/45/2014.
More information on that: https://stackoverflow.com/a/10120725/1948627

I've extended the method with a strict check option:

static public function verifyDate($date, $strict = true)
{
    $dateTime = DateTime::createFromFormat('m/d/Y', $date);
    if ($strict) {
        $errors = DateTime::getLastErrors();
        if (!empty($errors['warning_count'])) {
            return false;
        }
    }
    return $dateTime !== false;
}

Validate date format in php

function _date_is_valid($str) {
    if (substr_count($str, '/') == 2) {
        list($d, $m, $y) = explode('/', $str);
        return checkdate($m, $d, sprintf('%04u', $y));
    }

    return false;
}

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