Mysqli_Stmt::Execute() Expects Exactly 0 Parameters, 1 Given

mysqli_stmt::execute() expects exactly 0 parameters, 1 given error

<?php

include 'dbconnect.php';

$g_id = 'g_id';
$g_name = 'g_name';

$query = mysqli_query ($con, "SELECT g_id, g_name, h_d FROM g_post WHERE g_id = '$g_id'") or die(mysqli_error($con));
$name=( $query) ? mysqli_fetch_assoc( $query) : false;

The $con variable would come from your dbconnect.php file, where you've set a connection string and put it into a $con variable or whatever you've called it.

Hope this helps,

Sohail.

Uncaught ArgumentCountError: mysqli_stmt::execute() expects exactly 0 arguments, 1 given

It looks like you are using PHP 8.0. This version didn't allow passing an array in the execute() method; it's only available as of PHP 8.1. You must bind the parameters using the bind_param() method.

$sql = "INSERT INTO image_upload (image_name) VALUES (?)";
$stmt = $conn->prepare($sql);
$stmt->bind_param('s', $new_img_name); // one s for each parameter
$stmt->execute();

You should also consider using PDO instead of mysqli which would make your life easier. With PDO you could always pass an array to execute().

mysqli_stmt::execute() expects exactly 0 parameters, 1 given

you need to bind params before executing the query,
in procedural way do like this

mysqli_stmt_execute($stmt);

if you are doing it like object oriented way after binding params

/* Execute the statement */
$stmt->execute();

Docs link.

http://www.php.net/manual/en/mysqli-stmt.execute.php

PHP script issue expects exactly 0 parameters, 1 given | mySQL PHP

You can't pass an array of values to execute(), you have to use bind_param(). That feature is only available in PDO, not mysqli.

And rowCount() is a PDO method, not mysqli. It should be the num_rows property.

$query = 'SELECT Field1, Field2
    from Table1 WHERE (Field3 =?) AND field3 <> ""';
$stmt = $con->prepare($query);
$stmt->bind_param("s", $_POST['FieldInput']);
if ($stmt->execute()) {
    $stmt->store_result();
    $return['error'] = $stmt->num_rows > 0;
}

PHP with PDO problem mysqli_stmt::fetch()

To convert your code to PDO you must ensure that you connect with PDO first. These are two very different APIs and you can't mix them.

First connect:

$pdo = new PDO("mysql:host=localhost;dbname=test;charset=utf8mb4", 'user', 'pass', [
    \PDO::ATTR_ERRMODE => \PDO::ERRMODE_EXCEPTION,
    \PDO::ATTR_EMULATE_PREPARES => false
]);

Then prepare and execute a statement. Pay attention to never include variables directly in SQL. Every piece of data should be bound separately. In your SQL, put ? where the data should be bound to, and then pass an array with values in execute()

$run_user = $pdo->prepare('SELECT * FROM users where user_email=?'); 
$run_user->execute([
    $_SESSION['user_email']
]);

Now you can fetch the data. Make sure that your SQL actually fetched something before trying to access it.

$row = $run_user->fetch(PDO::FETCH_ASSOC);
if($row) {
    $user_id = $row['user_id']; 
    $user_name = $row['user_name'];
}

Prepared statement expects 0 params with 1 given .., using php manual example

execute (the object-based one, as opposed to the older less-favored variant) doesn't actually take any parameters.

From your query and attempted parameters to execute, it looks like you're trying to pass the needed parameters as an array to the execute call. This is not how it's done.

You need to bind variables to the ? markers in a separate call before calling execute.

This question (once fixed with the accepted answer) shows the general process you need to follow:

create statement;
prepare statement;
bind parameters;
execute (with no parameters);
store result (if buffering);
bind result variables;
fetch (in loop, most likely);
close statement.