Get JSON object from URL
$json = file_get_contents('url_here');
$obj = json_decode($json);
echo $obj->access_token;
For this to work, file_get_contents
requires that allow_url_fopen
is enabled. This can be done at runtime by including:
ini_set("allow_url_fopen", 1);
You can also use curl
to get the url. To use curl, you can use the example found here:
$ch = curl_init();
// IMPORTANT: the below line is a security risk, read https://paragonie.com/blog/2017/10/certainty-automated-cacert-pem-management-for-php-software
// in most cases, you should set it to true
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'url_here');
$result = curl_exec($ch);
curl_close($ch);
$obj = json_decode($result);
echo $obj->access_token;
How to extract and access data from JSON with PHP?
Intro
First off you have a string. JSON is not an array, an object, or a data structure. JSON is a text-based serialization format - so a fancy string, but still just a string. Decode it in PHP by using json_decode()
.
$data = json_decode($json);
Therein you might find:
- scalars: strings, ints, floats, and bools
- nulls (a special type of its own)
- compound types: objects and arrays.
These are the things that can be encoded in JSON. Or more accurately, these are PHP's versions of the things that can be encoded in JSON.
There's nothing special about them. They are not "JSON objects" or "JSON arrays." You've decoded the JSON - you now have basic everyday PHP types.
Objects will be instances of stdClass, a built-in class which is just a generic thing that's not important here.
Accessing object properties
You access the properties of one of these objects the same way you would for the public non-static properties of any other object, e.g. $object->property
.
$json = '
{
"type": "donut",
"name": "Cake"
}';
$yummy = json_decode($json);
echo $yummy->type; //donut
Accessing array elements
You access the elements of one of these arrays the same way you would for any other array, e.g. $array[0]
.
$json = '
[
"Glazed",
"Chocolate with Sprinkles",
"Maple"
]';
$toppings = json_decode($json);
echo $toppings[1]; //Chocolate with Sprinkles
Iterate over it with foreach
.
foreach ($toppings as $topping) {
echo $topping, "\n";
}
Glazed
Chocolate with Sprinkles
Maple
Or mess about with any of the bazillion built-in array functions.
Accessing nested items
The properties of objects and the elements of arrays might be more objects and/or arrays - you can simply continue to access their properties and members as usual, e.g. $object->array[0]->etc
.
$json = '
{
"type": "donut",
"name": "Cake",
"toppings": [
{ "id": "5002", "type": "Glazed" },
{ "id": "5006", "type": "Chocolate with Sprinkles" },
{ "id": "5004", "type": "Maple" }
]
}';
$yummy = json_decode($json);
echo $yummy->toppings[2]->id; //5004
Passing true
as the second argument to json_decode()
When you do this, instead of objects you'll get associative arrays - arrays with strings for keys. Again you access the elements thereof as usual, e.g. $array['key']
.
$json = '
{
"type": "donut",
"name": "Cake",
"toppings": [
{ "id": "5002", "type": "Glazed" },
{ "id": "5006", "type": "Chocolate with Sprinkles" },
{ "id": "5004", "type": "Maple" }
]
}';
$yummy = json_decode($json, true);
echo $yummy['toppings'][2]['type']; //Maple
Accessing associative array items
When decoding a JSON object to an associative PHP array, you can iterate both keys and values using the foreach (array_expression as $key => $value)
syntax, eg
$json = '
{
"foo": "foo value",
"bar": "bar value",
"baz": "baz value"
}';
$assoc = json_decode($json, true);
foreach ($assoc as $key => $value) {
echo "The value of key '$key' is '$value'", PHP_EOL;
}
Prints
The value of key 'foo' is 'foo value'
The value of key 'bar' is 'bar value'
The value of key 'baz' is 'baz value'
Don't know how the data is structured
Read the documentation for whatever it is you're getting the JSON from.
Look at the JSON - where you see curly brackets {}
expect an object, where you see square brackets []
expect an array.
Hit the decoded data with a print_r()
:
$json = '
{
"type": "donut",
"name": "Cake",
"toppings": [
{ "id": "5002", "type": "Glazed" },
{ "id": "5006", "type": "Chocolate with Sprinkles" },
{ "id": "5004", "type": "Maple" }
]
}';
$yummy = json_decode($json);
print_r($yummy);
and check the output:
stdClass Object
(
[type] => donut
[name] => Cake
[toppings] => Array
(
[0] => stdClass Object
(
[id] => 5002
[type] => Glazed
)
[1] => stdClass Object
(
[id] => 5006
[type] => Chocolate with Sprinkles
)
[2] => stdClass Object
(
[id] => 5004
[type] => Maple
)
)
)
It'll tell you where you have objects, where you have arrays, along with the names and values of their members.
If you can only get so far into it before you get lost - go that far and hit that with print_r()
:
print_r($yummy->toppings[0]);
stdClass Object
(
[id] => 5002
[type] => Glazed
)
Take a look at it in this handy interactive JSON explorer.
Break the problem down into pieces that are easier to wrap your head around.
json_decode()
returns null
This happens because either:
- The JSON consists entirely of just that,
null
. - The JSON is invalid - check the result of
json_last_error_msg
or put it through something like JSONLint. - It contains elements nested more than 512 levels deep. This default max depth can be overridden by passing an integer as the third argument to
json_decode()
.
If you need to change the max depth you're probably solving the wrong problem. Find out why you're getting such deeply nested data (e.g. the service you're querying that's generating the JSON has a bug) and get that to not happen.
Object property name contains a special character
Sometimes you'll have an object property name that contains something like a hyphen -
or at sign @
which can't be used in a literal identifier. Instead you can use a string literal within curly braces to address it.
$json = '{"@attributes":{"answer":42}}';
$thing = json_decode($json);
echo $thing->{'@attributes'}->answer; //42
If you have an integer as property see: How to access object properties with names like integers? as reference.
Someone put JSON in your JSON
It's ridiculous but it happens - there's JSON encoded as a string within your JSON. Decode, access the string as usual, decode that, and eventually get to what you need.
$json = '
{
"type": "donut",
"name": "Cake",
"toppings": "[{ \"type\": \"Glazed\" }, { \"type\": \"Maple\" }]"
}';
$yummy = json_decode($json);
$toppings = json_decode($yummy->toppings);
echo $toppings[0]->type; //Glazed
Data doesn't fit in memory
If your JSON is too large for json_decode()
to handle at once things start to get tricky. See:
- Processing large JSON files in PHP
- How to properly iterate through a big json file
How to sort it
See: Reference: all basic ways to sort arrays and data in PHP.
Get JSON from URL by PHP
$json = file_get_contents('http://www.myapifilms.com/imdb/top');
$array = json_decode($json);
$urlPoster=array();
foreach ($array as $value) {
$urlPoster[]=$value->urlPoster;
}
print_r($urlPoster);
Get JSON data from PHP using Javascript:
Your code is working fine, you could check if you are getting any warning in php response which cause an error in JSON.parse at client side, meanwhile same error I got while running your script in my system.
Getting Response from php -
<br />
<b>Warning</b>: Creating default object from empty value in <b>/opt/lampp/htdocs/tst/get_info.php</b> on line <b>5</b><br />
{"name":"John","age":30,"city":"New York"}
At Client Side :
Uncaught SyntaxError: Unexpected token < in JSON at position 0
at JSON.parse (<anonymous>)
at XMLHttpRequest.req.onreadystatechange
Fixed this issue by disabling the warning in my php code -
error_reporting(E_ERROR | E_PARSE);
Reading JSON POST using PHP
You have empty $_POST
. If your web-server wants see data in json-format you need to read the raw input and then parse it with JSON decode.
You need something like that:
$json = file_get_contents('php://input');
$obj = json_decode($json);
Also you have wrong code for testing JSON-communication...
CURLOPT_POSTFIELDS
tells curl
to encode your parameters as application/x-www-form-urlencoded
. You need JSON-string here.
UPDATE
Your php code for test page should be like that:
$data_string = json_encode($data);
$ch = curl_init('http://webservice.local/');
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data_string))
);
$result = curl_exec($ch);
$result = json_decode($result);
var_dump($result);
Also on your web-service page you should remove one of the lines header('Content-type: application/json');
. It must be called only once.
Get JSON response from API using PHP, format the JSON data into HTML using Javascript
To print the data, you can use:
$result = json_decode ( $json, true);
foreach ( $result["webPages"]["value"] as $data)
{
echo "<a href=\"" . urlencode ( $data["id"]) . "\">" . $data["name"] . "</a>\n";
}
I like to use json_decode() method returning array instead of object, using true as second parameter, but you can also use it as object if you prefer.
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