Shell Script Change Directory with Variable

Shell script change directory with variable

You variable contains a carriage return. Try saying:

cd $(echo $RED_INSTANCE_NAME | tr -d '\r')

and it should work. In order to remove the CR from the variable you can say:

RED_INSTANCE_NAME=$(echo $RED_INSTANCE_NAME | tr -d '\r')

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The following would illustrate the issue:

$ mkdir abc
$ foo=abc$'\r'
$ echo "${foo}"
abc
$ cd "${foo}"
: No such file or directory
$ echo $foo | od -x
0000000 6261 0d63 000a
0000005
$ echo $foo | tr -d '\r' | od -x
0000000 6261 0a63
0000004
$ echo $'\r' | od -x
0000000 0a0d
0000002

how to change directory to a path stored in variable bash

Try this:

cd $(eval "echo \"$(cat $HOME/devdir.txt)\"");

or:

eval "cd \"$(cat $HOME/devdir.txt)\"";

It will change the directory inside the script session that you are running. If you run ./script it won't cd externally

Bash: use cd command on a variable including spaces

Why don't you just...

cd "$input_path"

since it is quoted, there won't be any problem with spaces.

By saying cd $(echo "$input_path") you are in fact saying cd my path, whereas you want to do cd "my path". Thus, as commented by JID below, you can also say cd "$(echo $input_path)" because the important quotes are the ones that are "closer" to cd.

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If you don't quote, cd sees:

cd my path

So it tries to cd my, whereas if you quote it sees:

cd "my path"

How can i change directory in shell script with variables

I would suggest a function called "prj" to put in your .bashrc:

prj () {
    cd /home/byram/workspace/"$1"/src/com/seri
}

Then use it like this

prj 1    # Switch to ...1/src/com/seri
prj 2    # Switch to ...2/src/com/seri

Bash script to change directory from user input

It is better to use quotes in the cd command, regardless of whether the directory has spaces or not, like this:

#!/bin/bash
read -p "Enter destination: " folder
cd "$folder"
pwd

Test:

Another solution (use with caution as it may cause other problems) is using eval in your code:

#!/bin/bash
read -p "Enter destination: " folder
folder=$(sed -e 's/^/"/' -e 's/$/"/' <<< $folder)
eval cd $folder

References:

• Bash script to cd to directory with spaces in pathname

Cannot cd with external variable in bash script

The problem came from invsible \r (carriage return) generated by windows at the end of lines.
I change the EOL Conversion to Unix (LF)!

How to use variable in bash script

Spacing is important. Because of the space in your command, this doesn't do what you expect:

user= whoami

What that does is define an empty variable called user, and then calls the whoami command with that empty variable added to the environment. The "pbsh56" you see is from the whoami command, not from the echo.

What you want is

user=$(whoami)
echo $user
cd /home/$user

Change directory in script bash

Source your script instead of running it like you do. When you run it like you do, you spawn a new shell that executes the cd, completes succesfully, closes the shell and returns to your current shell, leaving you in your pwd.

Use source myscript.sh or . myscript.sh instead of bash myscript.sh or myscript.sh.

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