How to Tell If a File Is Older Than 30 Minutes from /Bin/Sh

If file modification date is older than N days

Several approaches are available. One is just to ask find to do the filtering for you:

if [[ $(find "$filename" -mtime +100 -print) ]]; then
  echo "File $filename exists and is older than 100 days"
fi

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Another is to use GNU date to do the math:

# collect both times in seconds-since-the-epoch
hundred_days_ago=$(date -d 'now - 100 days' +%s)
file_time=$(date -r "$filename" +%s)

# ...and then just use integer math:
if (( file_time <= hundred_days_ago )); then
  echo "$filename is older than 100 days"
fi

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If you have GNU stat, you can ask for a file's timestamp in seconds-since-epoch, and do some math yourself (though this will potentially be a bit off on the boundary cases, since it's counting seconds -- and not taking into account leap days and such -- and not rounding to the beginning of a day):

file_time=$(stat --format='%Y' "$filename")
current_time=$(( date +%s ))
if (( file_time < ( current_time - ( 60 * 60 * 24 * 100 ) ) )); then
  echo "$filename is older than 100 days"
fi

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Another option, if you need to support non-GNU platforms, is to shell out to Perl (which I'll leave it to others to demonstrate).

If you're interested more generally in getting timestamp information from files, and portability and robustness constraints surrounding same, see also BashFAQ #87.

Check the existence of file from 9 to 9:30 am using shell script and stop checking if file is found any time in between

Something like this run just once at the start of the 30 minute period from cron:

#!/bin/bash

MESSAGE="Some message"
SUBJECT="Some subject"
RECIPIENT="somebody@somewhere.com"

# Test for 30 minutes
for ((i=0;i<7;i++)) ; do
   if [ -f /home/test/"$1" ];  then
      echo "File /home/test/$1 exists”
      exit 0
   fi
   # Sleep 5 minutes
   sleep 300
done

# Failed to find file in specified time
echo "$MESSAGE" | mailx -s "$SUBJECT" $RECIPIENT

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A slightly different way of doing it is like this:

#!/bin/bash

MESSAGE="Some message"
SUBJECT="Some subject"
RECIPIENT="somebody@somewhere.com"

start=$SECONDS
# Test for 30 minutes
while : ; do
   if [ -f "/home/test/" ];  then
      exit 0
   fi
   ((elapsed=SECONDS-start))
   # Break out of loop if 30 minutes have elapsed
   [ $elapsed -ge 1800 ] && break
   # Sleep 5 minutes
   sleep 300
done
# Failed to find file in specified time
echo "$MESSAGE" | mailx -s "$SUBJECT" $RECIPIENT

how do I check in bash whether a file was created more than x time ago?

Only for modification time

if test `find "text.txt" -mmin +120`
then
    echo old enough
fi

You can use -cmin for change or -amin for access time. As others pointed I don’t think you can track creation time.

Need a way to check content of file (time data) is more than 5 minutes or not

First, I understand that on line 1 you're trying to have the latest file. I would rather have the file created always with the same name, then at the end of the script, after processing it, mv to another name (like myfile.txt.20200101). So you'll always know that myfile.txt is the latest one. More efficient than doing ls. Then again, you could improve your line with : (it's the number one, not the letter "l")

var10=$(ls -1rt /projects/Informatica/INFA_ADMIN/LogFiles/myfile.txt)

From your line 2, I assume the original file is space delimited. Actually, you might use that to your advantage instead of adding commas. Also, using a for loop with "cat" is less performant than using a while loop. For the time comparison, I would use a little trick. Transforming your threshold and reading, in second since epoch then compared them.

MyTreshold=$(date -d 00:05:00 +"%s")    
while read -r line; do
        MyArray=( $line )
        MyReading=$(date -d ${MyArray[5]} +"%s")
        #the array starts a index 0
        if [[ ${MyArray[1]} -ge 75 && $MyReading -gt $MyThreshold ]]; then
           <LOGIC>
        fi
done <$var10

linux script to check if file exists at a particular directory more than an hour

I think you should try this:

#!/bin/bash

if [[ `find /path/to/my/directory/ -type f -mmin +60 | wc -l` -gt 0 ]];then
        echo "files do exist"
else
        echo "files do not exist"
fi

Explain: i will find all files under directory: /path/to/my/directory/ with modify time greater than 60 minutes then count them.

How to delete files older than X hours

Does your find have the -mmin option? That can let you test the number of mins since last modification:

find $LOCATION -name $REQUIRED_FILES -type f -mmin +360 -delete

Or maybe look at using tmpwatch to do the same job. phjr also recommended tmpreaper in the comments.

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