How to Check If a Files Exists in a Specific Directory in a Bash Script

How to check if a files exists in a specific directory in a bash script?

You can use $FILE to concatenate with the directory to make the full path as below.

FILE="$1"
if [ -e ~/.myexample/"$FILE" ]; then
    echo "File exists"
else
    echo "File does not exist"
fi

How to check if a file exists in a shell script

You're missing a required space between the bracket and -e:

#!/bin/bash
if [ -e x.txt ]
then
    echo "ok"
else
    echo "nok"
fi

Check if same file exists in another directory using Bash

When you have a construct like for file in $firstPath/*, the value of $file is going to include the value of $firstPath, which does not exist within $secondPath. You need to strip the path in order to get the bare filename.

In traditional POSIX shell, the canonical way to do this was with an external tool called basename. You can, however, achieve what is generally thought to be equivalent functionality using Parameter Expansion, thus:

for file in "$firstPath"/*; do
   if [[ -f "$secondPath/${file##*/}" ]]; then
       # file exists, do something
   fi
done

The ${file##*/} bit is the important part here. Per the documentation linked above, this means "the $file variable, with everything up to the last / stripped out." The result should be the same as what basename produces.

As a general rule, you should quote your variables in bash. In addition, consider using [[ instead of [ unless you're actually writing POSIX shell scripts which need to be portable. You'll have a more extensive set of tests available to you, and more predictable handling of variables. There are other differences too.

linux script to check if file exists at a particular directory more than an hour

I think you should try this:

#!/bin/bash

if [[ `find /path/to/my/directory/ -type f -mmin +60 | wc -l` -gt 0 ]];then
        echo "files do exist"
else
        echo "files do not exist"
fi

Explain: i will find all files under directory: /path/to/my/directory/ with modify time greater than 60 minutes then count them.

How do I check whether a file or file directory exist in bash?

Checking file and/or directory existence

To check whether a file exists in bash, you use the -f operator. For directories, use -d. Example usage:

$ mkdir dir
$ [ -d dir ] && echo exists!
exists!
$ rmdir dir
$ [ -d dir ] && echo exists!
$ touch file
$ [ -f file ] || echo "doesn't exist..."
$ rm file
$ [ -f file ] || echo "doesn't exist..."
doesn't exist...

For more information simply execute man test.

A note on -e, this test operator checks whether a file exists. While this may seem like a good choice, it's better to use -f which will return false if the file isn't a regular file. /dev/null for example is a file but nor a regular file. Having the check return true is undesired in this case.

A note on variables

Be sure to quote variables too, once you have a space or any other special character contained in a variable it can have undesired side effects. So when you test for existence of files and directories, wrap the file/dir in double quotes. Something like [ -f "/path/to/some/${dir}/" ] will work while the following would fail if there is a space in dir: [ -f /path/to/some/${dir}/ ].

Fixing the syntax error

You are experiencing a syntax error in the control statements. A bash if clause is structured as following:

if ...; then
    ...
fi

Or optional with an else clause:

if ...; then
    ...
else
    ...
fi

You cannot omit the then clause. If you wish to only use the else clause you should negate the condition. Resulting in following code:

if [ ! -f "/usr/share/icons/$j/scalable" ]; then
    mkdir "/usr/share/icons/$j/scalable/"
fi

Here we add an exclamation point (!) to flip the expression's evaluation. If the expression evaluates to true, the same expression preceded by ! will return false and the other way around.

Checking from shell script if a directory contains files

The solutions so far use ls. Here's an all bash solution:

#!/bin/bash
shopt -s nullglob dotglob     # To include hidden files
files=(/some/dir/*)
if [ ${#files[@]} -gt 0 ]; then echo "huzzah"; fi

Check if file exist relative to current script (one level up)

There are three problems in your script.

1. To store the output of a command in a variable, use $(), not ${}.
2. [ -f "$dir" ] checks if $dir is a a file, which will never happen, because dirname outputs a directory.
3. Your script can be executed from any other working directory as well. Just because the script is stored in ···/app/scripts/ does not mean it will always run from there.

Try

file=$(dirname "$BASH_SOURCE")/../dist/file.js
if [ -f "$file" ]; then
    echo "file exists."
else 
    echo "file does not exist."
fi

How to check if a file is present in a particular directory in Unix?

We can make use of [ls] and [$?] command to do this.
Use below command :

ls -l filename.txt

Followed by,

echo $?

If the file exists, the [ls] command will be successful.Hence [echo $?] will print 0.

If the file does not exists, then [ls] command will fail and hence [echo $?] will print 1.

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