Count Occurrences of a Char in Plain Text File

Count occurrences of a char in plain text file

How about this:

fgrep -o f <file> | wc -l

Note: Besides much easier to remember/duplicate and customize, this is about three times (sorry, edit! botched the first test) faster than Vereb's answer.

Counting the occurrence of characters within a text file in Java

You are initializing variable count in every iteration, which is wrong. Declare variable outside of while and check it will work. From your code it will print only the last line count.
Please do following change to your code:

public class LetterCounter
{
   public static void main( String[] args ) throws FileNotFoundException
   {
      Scanner input = new Scanner( new File( "src/para1.txt" ) );
      char someChar = 'a';
      int count = 0;
      while ( input.hasNextLine() )
      {
         String answer = input.nextLine();
         answer = answer.toLowerCase();
         for ( int i = 0; i < answer.length(); i++ )
         {
            if ( answer.charAt( i ) == someChar )
            {
               count++;
            }
         }
         System.out.println( answer );
      }
      System.out.println( "a - " + count );
      input.close();
   }
}

Counting All Character Occurrences in a Text File in C

This is because of fgets() . It considers until it encounters a newline character. you are reading line by line. Either you can use static int n = 0; or do

int k = 0;

ficheiro1 = fopen("encrypted_file.txt", "r");

 while(fgets(texto_str, 3000, ficheiro1) != NULL)
    {
            k = k +strcountc(texto_str,'a' );
    }

    printf("no of char\t %d", k);

Count occurrences of character in file -C

There are multiple problems in your code:

• ch must be defined as int to handle EOF reliably.

• while (!feof(fp)) is incorrect. Learn Why is “while ( !feof (file) )” always wrong? You should instead write:

  while ((ch - getc(fp)) != EOF)
  

• strcmp(&ch, ":") is incorrect because &ch is not a C string. You should use ch == ':' instead.

• you forget to close the file, causing a resource leak.

Here is a modified version:

int NumColon(const char *filename) {
    FILE *fp = fopen(filename, "r");
    if (fp == NULL) {
        return -1;
    }
    int count = 0;
    int c;
    while ((c = getc(fp)) != EOF) {
        count += (c == ':');
    }
    fclose(fp);
    return count;
}

Counting Character usage in text file? C

Rewind the pointer to the beginning of the file at the end of your for loop?

This has been posted before: Resetting pointer to the start of file

P.S. - maybe use an array for your output values : int charactercount[pow(2,sizeof(char))] so that you don't have to parse the file repeatedly?

edit: was missing pow()

Count number of character occurrences from input text file

In order to convert each String into its representing characters, you need an additional flatMap:

val characters = lines.flatMap(_.split(" ")).flatMap(_.toCharArray)

scala> val lines = Array("hello world", "yay more lines")
lines: Array[String] = Array(hello world, yay more lines)

scala> lines.flatMap(_.split(" ")).flatMap(_.toCharArray)
res3: Array[Char] = Array(h, e, l, l, o, w, o, r, l, d, y, a, y, m, o, r, e, l, i, n, e, s)

Although this is a Scala console, it will work the same on an RDD.

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